-sql语句练习50题(Mysql学习练习版)
–1.学生表
Student(s_id,s_name,s_birth,s_sex) –学生编号,学生姓名, 出生年月,学生性别
–2.课程表
Course(c_id,c_name,t_id) – –课程编号, 课程名称, 教师编号
–3.教师表
Teacher(t_id,t_name) –教师编号,教师姓名
–4.成绩表
Score(s_id,c_id,s_score) –学生编号,课程编号,分数
测试数据
--建表
--学生表
CREATE TABLE `Student`(
`s_id` VARCHAR(20),
`s_name` VARCHAR(20) NOT NULL DEFAULT '',
`s_birth` VARCHAR(20) NOT NULL DEFAULT '',
`s_sex` VARCHAR(10) NOT NULL DEFAULT '',
PRIMARY KEY(`s_id`)
);
--课程表
CREATE TABLE `Course`(
`c_id` VARCHAR(20),
`c_name` VARCHAR(20) NOT NULL DEFAULT '',
`t_id` VARCHAR(20) NOT NULL,
PRIMARY KEY(`c_id`)
);
--教师表
CREATE TABLE `Teacher`(
`t_id` VARCHAR(20),
`t_name` VARCHAR(20) NOT NULL DEFAULT '',
PRIMARY KEY(`t_id`)
);
--成绩表
CREATE TABLE `Score`(
`s_id` VARCHAR(20),
`c_id` VARCHAR(20),
`s_score` INT(3),
PRIMARY KEY(`s_id`,`c_id`)
);
--插入学生表测试数据
insert into Student values('01' , '赵雷' , '1990-01-01' , '男');
insert into Student values('02' , '钱电' , '1990-12-21' , '男');
insert into Student values('03' , '孙风' , '1990-05-20' , '男');
insert into Student values('04' , '李云' , '1990-08-06' , '男');
insert into Student values('05' , '周梅' , '1991-12-01' , '女');
insert into Student values('06' , '吴兰' , '1992-03-01' , '女');
insert into Student values('07' , '郑竹' , '1989-07-01' , '女');
insert into Student values('08' , '王菊' , '1990-01-20' , '女');
--课程表测试数据
insert into Course values('01' , '语文' , '02');
insert into Course values('02' , '数学' , '01');
insert into Course values('03' , '英语' , '03');
--教师表测试数据
insert into Teacher values('01' , '张三');
insert into Teacher values('02' , '李四');
insert into Teacher values('03' , '王五');
--成绩表测试数据
insert into Score values('01' , '01' , 80);
insert into Score values('01' , '02' , 90);
insert into Score values('01' , '03' , 99);
insert into Score values('02' , '01' , 70);
insert into Score values('02' , '02' , 60);
insert into Score values('02' , '03' , 80);
insert into Score values('03' , '01' , 80);
insert into Score values('03' , '02' , 80);
insert into Score values('03' , '03' , 80);
insert into Score values('04' , '01' , 50);
insert into Score values('04' , '02' , 30);
insert into Score values('04' , '03' , 20);
insert into Score values('05' , '01' , 76);
insert into Score values('05' , '02' , 87);
insert into Score values('06' , '01' , 31);
insert into Score values('06' , '03' , 34);
insert into Score values('07' , '02' , 89);
insert into Score values('07' , '03' , 98);
练习题和sql语句
-- 1、查询"01"课程比"02"课程成绩高的学生的信息及课程分数
select a.* ,b.s_score as 01_score,c.s_score as 02_score from
student a
join score b on a.s_id=b.s_id and b.c_id='01'
left join score c on a.s_id=c.s_id and c.c_id='02' or c.c_id = NULL where b.s_score>c.s_score
-- 2、查询"01"课程比"02"课程成绩低的学生的信息及课程分数
select a.* ,b.s_score as 01_score,c.s_score as 02_score from
student a left join score b on a.s_id=b.s_id and b.c_id='01' or b.c_id=NULL
join score c on a.s_id=c.s_id and c.c_id='02' where b.s_score<c.s_score
-- 3、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩
select b.s_id,b.s_name,ROUND(AVG(a.s_score),2) as avg_score from
student b
join score a on b.s_id = a.s_id
GROUP BY b.s_id,b.s_name HAVING ROUND(AVG(a.s_score),2)>=60;
-- 4、查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩
-- (包括有成绩的和无成绩的)
select b.s_id,b.s_name,ROUND(AVG(a.s_score),2) as avg_score from
student b
left join score a on b.s_id = a.s_id
GROUP BY b.s_id,b.s_name HAVING ROUND(AVG(a.s_score),2)<60
union
select a.s_id,a.s_name,0 as avg_score from
student a
where a.s_id not in (
select distinct s_id from score);
-- 5、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩
select a.s_id,a.s_name,count(b.c_id) as sum_course,sum(b.s_score) as sum_score from
student a
left join score b on a.s_id=b.s_id
GROUP BY a.s_id,a.s_name;
-- 6、查询"李"姓老师的数量
select count(t_id) from teacher where t_name like '李%';
-- 7、查询学过"张三"老师授课的同学的信息
select a.* from
student a
join score b on a.s_id=b.s_id where b.c_id in(
select c_id from course where t_id =(
select t_id from teacher where t_name = '张三'));
-- 8、查询没学过"张三"老师授课的同学的信息
select * from
student c
where c.s_id not in(
select a.s_id from student a join score b on a.s_id=b.s_id where b.c_id in(
select c_id from course where t_id =(
select t_id from teacher where t_name = '张三')));
-- 9、查询学过编号为"01"并且也学过编号为"02"的课程的同学的信息
select a.* from
student a,score b,score c
where a.s_id = b.s_id and a.s_id = c.s_id and b.c_id='01' and c.c_id='02';
-- 10、查询学过编号为"01"但是没有学过编号为"02"的课程的同学的信息
select a.* from
student a
where a.s_id in (select s_id from score where c_id='01' ) and a.s_id not in(select s_id from score where c_id='02')
-- 11、查询没有学全所有课程的同学的信息
select s.* from
student s where s.s_id in(
select s_id from score where s_id not in(
select a.s_id from score a
join score b on a.s_id = b.s_id and b.c_id='02'
join score c on a.s_id = c.s_id and c.c_id='03'
where a.c_id='01'))
-- 12、查询至少有一门课与学号为"01"的同学所学相同的同学的信息
select * from student where s_id in(
select distinct a.s_id from score a where a.c_id in(select a.c_id from score a where a.s_id='01')
);
-- 13、查询和"01"号的同学学习的课程完全相同的其他同学的信息
select a.* from student a where a.s_id in(
select distinct s_id from score where s_id!='01' and c_id in(select c_id from score where s_id='01')
group by s_id
having count(1)=(select count(1) from score where s_id='01'));
-- 14、查询没学过"张三"老师讲授的任一门课程的学生姓名
select a.s_name from student a where a.s_id not in (
select s_id from score where c_id =
(select c_id from course where t_id =(
select t_id from teacher where t_name = '张三'))
group by s_id);
-- 15、查询两门及其以上不及格课程的同学的学号，姓名及其平均成绩
select a.s_id,a.s_name,ROUND(AVG(b.s_score)) from
student a
left join score b on a.s_id = b.s_id
where a.s_id in(
select s_id from score where s_score<60 GROUP BY s_id having count(1)>=2)
GROUP BY a.s_id,a.s_name
-- 16、检索"01"课程分数小于60，按分数降序排列的学生信息
select a.*,b.c_id,b.s_score from
student a,score b
where a.s_id = b.s_id and b.c_id='01' and b.s_score<60 ORDER BY b.s_score DESC;
-- 17、按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩
select a.s_id,(select s_score from score where s_id=a.s_id and c_id='01') as 语文,
(select s_score from score where s_id=a.s_id and c_id='02') as 数学,
(select s_score from score where s_id=a.s_id and c_id='03') as 英语,
round(avg(s_score),2) as 平均分 from score a GROUP BY a.s_id ORDER BY 平均分 DESC;
-- 18.查询各科成绩最高分、最低分和平均分：以如下形式显示：课程ID，课程name，最高分，最低分，平均分，及格率，中等率，优良率，优秀率
--及格为>=60，中等为：70-80，优良为：80-90，优秀为：>=90
select a.c_id,b.c_name,MAX(s_score),MIN(s_score),ROUND(AVG(s_score),2),
ROUND(100*(SUM(case when a.s_score>=60 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 及格率,
ROUND(100*(SUM(case when a.s_score>=70 and a.s_score<=80 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 中等率,
ROUND(100*(SUM(case when a.s_score>=80 and a.s_score<=90 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 优良率,
ROUND(100*(SUM(case when a.s_score>=90 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 优秀率
from score a left join course b on a.c_id = b.c_id GROUP BY a.c_id,b.c_name
-- 19、按各科成绩进行排序，并显示排名(实现不完全)
-- mysql没有rank函数
select a.s_id,a.c_id,
@i:=@i +1 as i保留排名,
@k:=(case when @score=a.s_score then @k else @i end) as rank不保留排名,
@score:=a.s_score as score
from (
select s_id,c_id,s_score from score WHERE c_id='01' GROUP BY s_id,c_id,s_score ORDER BY s_score DESC
)a,(select @k:=0,@i:=0,@score:=0)s
union
select a.s_id,a.c_id,
@i:=@i +1 as i,
@k:=(case when @score=a.s_score then @k else @i end) as rank,
@score:=a.s_score as score
from (
select s_id,c_id,s_score from score WHERE c_id='02' GROUP BY s_id,c_id,s_score ORDER BY s_score DESC
)a,(select @k:=0,@i:=0,@score:=0)s
union
select a.s_id,a.c_id,
@i:=@i +1 as i,
@k:=(case when @score=a.s_score then @k else @i end) as rank,
@score:=a.s_score as score
from (
select s_id,c_id,s_score from score WHERE c_id='03' GROUP BY s_id,c_id,s_score ORDER BY s_score DESC
)a,(select @k:=0,@i:=0,@score:=0)s
-- 20、查询学生的总成绩并进行排名
select a.s_id,
@i:=@i+1 as i,
@k:=(case when @score=a.sum_score then @k else @i end) as rank,
@score:=a.sum_score as score
from (select s_id,SUM(s_score) as sum_score from score GROUP BY s_id ORDER BY sum_score DESC)a,
(select @k:=0,@i:=0,@score:=0)s
-- 21、查询不同老师所教不同课程平均分从高到低显示
select a.t_id,c.t_name,a.c_id,ROUND(avg(s_score),2) as avg_score from course a
left join score b on a.c_id=b.c_id
left join teacher c on a.t_id=c.t_id
GROUP BY a.c_id,a.t_id,c.t_name ORDER BY avg_score DESC;
-- 22、查询所有课程的成绩第2名到第3名的学生信息及该课程成绩
select d.*,c.排名,c.s_score,c.c_id from (
select a.s_id,a.s_score,a.c_id,@i:=@i+1 as 排名 from score a,(select @i:=0)s where a.c_id='01'
)c
left join student d on c.s_id=d.s_id
where 排名 BETWEEN 2 AND 3
UNION
select d.*,c.排名,c.s_score,c.c_id from (
select a.s_id,a.s_score,a.c_id,@j:=@j+1 as 排名 from score a,(select @j:=0)s where a.c_id='02'
)c
left join student d on c.s_id=d.s_id
where 排名 BETWEEN 2 AND 3
UNION
select d.*,c.排名,c.s_score,c.c_id from (
select a.s_id,a.s_score,a.c_id,@k:=@k+1 as 排名 from score a,(select @k:=0)s where a.c_id='03'
)c
left join student d on c.s_id=d.s_id
where 排名 BETWEEN 2 AND 3;
-- 23、统计各科成绩各分数段人数：课程编号,课程名称,[100-85],[85-70],[70-60],[0-60]及所占百分比
select distinct f.c_name,a.c_id,b.`85-100`,b.百分比,c.`70-85`,c.百分比,d.`60-70`,d.百分比,e.`0-60`,e.百分比 from score a
left join (select c_id,SUM(case when s_score >85 and s_score <=100 then 1 else 0 end) as `85-100`,
ROUND(100*(SUM(case when s_score >85 and s_score <=100 then 1 else 0 end)/count(*)),2) as 百分比
from score GROUP BY c_id)b on a.c_id=b.c_id
left join (select c_id,SUM(case when s_score >70 and s_score <=85 then 1 else 0 end) as `70-85`,
ROUND(100*(SUM(case when s_score >70 and s_score <=85 then 1 else 0 end)/count(*)),2) as 百分比
from score GROUP BY c_id)c on a.c_id=c.c_id
left join (select c_id,SUM(case when s_score >60 and s_score <=70 then 1 else 0 end) as `60-70`,
ROUND(100*(SUM(case when s_score >60 and s_score <=70 then 1 else 0 end)/count(*)),2) as 百分比
from score GROUP BY c_id)d on a.c_id=d.c_id
left join (select c_id,SUM(case when s_score >=0 and s_score <=60 then 1 else 0 end) as `0-60`,
ROUND(100*(SUM(case when s_score >=0 and s_score <=60 then 1 else 0 end)/count(*)),2) as 百分比
from score GROUP BY c_id)e on a.c_id=e.c_id
left join course f on a.c_id = f.c_id
---也可以这么做
SELECT
c.c_id,
c.c_name,
a.`85-100`,
a.`85-100百分比`,
b.`70-85`,
b.`70-85百分比`,
ce.`60-70`,
ce.`60-70百分比`,
d.`0-60`,
d.`0-60百分比`
FROM course c
LEFT JOIN(SELECT s.c_id,SUM(CASE WHEN s.s_score >85 AND s.s_score <= 100 THEN 1 ELSE 0 END) AS "85-100",ROUND(100*SUM(CASE WHEN s.s_score >85 AND s.s_score <= 100 THEN 1 ELSE 0 END)/count(1),2) as "85-100百分比" FROM score s GROUP BY s.c_id) a ON a.c_id = c.c_id
LEFT JOIN(SELECT s.c_id,SUM(CASE WHEN s.s_score >85 AND s.s_score <= 100 THEN 1 ELSE 0 END) AS "70-85",ROUND(100*SUM(CASE WHEN s.s_score >70 AND s.s_score <= 85 THEN 1 ELSE 0 END)/count(1),2) as "70-85百分比" FROM score s GROUP BY s.c_id) b ON b.c_id = c.c_id
LEFT JOIN(SELECT s.c_id,SUM(CASE WHEN s.s_score >85 AND s.s_score <= 100 THEN 1 ELSE 0 END) AS "60-70",ROUND(100*SUM(CASE WHEN s.s_score >60 AND s.s_score <= 70 THEN 1 ELSE 0 END)/count(1),2) as "60-70百分比" FROM score s GROUP BY s.c_id) ce ON ce.c_id = c.c_id
LEFT JOIN(SELECT s.c_id,SUM(CASE WHEN s.s_score >85 AND s.s_score <= 100 THEN 1 ELSE 0 END) AS "0-60",ROUND(100*SUM(CASE WHEN s.s_score >0 AND s.s_score <= 60 THEN 1 ELSE 0 END)/count(1),2) as "0-60百分比" FROM score s GROUP BY s.c_id) d ON d.c_id = c.c_id
-- 24、查询学生平均成绩及其名次
select a.s_id,
@i:=@i+1 as '不保留空缺排名',
@k:=(case when @avg_score=a.avg_s then @k else @i end) as '保留空缺排名',
@avg_score:=avg_s as '平均分'
from (select s_id,ROUND(AVG(s_score),2) as avg_s from score GROUP BY s_id)a,(select @avg_score:=0,@i:=0,@k:=0)b;
-- 25、查询各科成绩前三名的记录
-- 1.选出b表比a表成绩大的所有组
-- 2.选出比当前id成绩大的 小于三个的
select a.s_id,a.c_id,a.s_score from score a
left join score b on a.c_id = b.c_id and a.s_score<b.s_score
group by a.s_id,a.c_id,a.s_score HAVING COUNT(b.s_id)<3
ORDER BY a.c_id,a.s_score DESC
-- 26、查询每门课程被选修的学生数
select c_id,count(s_id) from score a GROUP BY c_id
-- 27、查询出只有两门课程的全部学生的学号和姓名
select s_id,s_name from student where s_id in(
select s_id from score GROUP BY s_id HAVING COUNT(c_id)=2);
---另外一种写法
SELECT
st.s_id,
st.s_name
FROM student st
INNER JOIN(
SELECT
s.s_id
FROM score s
GROUP BY s_id
HAVING COUNT(s.c_id) = 2
) a ON a.s_id = st.s_id;
-- 28、查询男生、女生人数
select s_sex,COUNT(s_sex) as 人数 from student GROUP BY s_sex
-- 29、查询名字中含有"风"字的学生信息
select * from student where s_name like '%风%';
-- 30、查询同名同性学生名单，并统计同名人数
select a.s_name,a.s_sex,count(*) from student a JOIN
student b on a.s_id !=b.s_id and a.s_name = b.s_name and a.s_sex = b.s_sex
GROUP BY a.s_name,a.s_sex
-- 31、查询1990年出生的学生名单
select s_name from student where s_birth like '1990%'
-- 32、查询每门课程的平均成绩，结果按平均成绩降序排列，平均成绩相同时，按课程编号升序排列
select c_id,ROUND(AVG(s_score),2) as avg_score from score GROUP BY c_id ORDER BY avg_score DESC,c_id ASC
-- 33、查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩
select a.s_id,b.s_name,ROUND(avg(a.s_score),2) as avg_score from score a
left join student b on a.s_id=b.s_id GROUP BY s_id HAVING avg_score>=85
-- 34、查询课程名称为"数学"，且分数低于60的学生姓名和分数
select a.s_name,b.s_score from score b LEFT JOIN student a on a.s_id=b.s_id where b.c_id=(
select c_id from course where c_name ='数学') and b.s_score<60
----另外一种自己的写法
SELECT
st.s_name,
s.s_score
FROM student st
INNER JOIN score s ON s.s_id = st.s_id
INNER JOIN course c ON c.c_id = s.c_id AND c.c_name = '数学'
WHERE s.s_score < 60;
-- 35、查询所有学生的课程及分数情况；
select a.s_id,a.s_name,
SUM(case c.c_name when '语文' then b.s_score else 0 end) as '语文',
SUM(case c.c_name when '数学' then b.s_score else 0 end) as '数学',
SUM(case c.c_name when '英语' then b.s_score else 0 end) as '英语',
SUM(b.s_score) as '总分'
from student a left join score b on a.s_id = b.s_id
left join course c on b.c_id = c.c_id
GROUP BY a.s_id,a.s_name
--注意case when...和case...when的用法
-- 36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数；
select a.s_name,b.c_name,c.s_score from course b left join score c on b.c_id = c.c_id
left join student a on a.s_id=c.s_id where c.s_score>=70
----另外一种过滤方法
SELECT
st.s_name,
c.c_name,
s.s_score
FROM course c
LEFT JOIN score s on s.c_id = c.c_id AND s.s_score > 70
LEFT JOIN student st ON st.s_id = s.s_id
-- 37、查询不及格的课程
select a.s_id,a.c_id,b.c_name,a.s_score from score a left join course b on a.c_id = b.c_id
where a.s_score<60
--38、查询课程编号为01且课程成绩在80分以上的学生的学号和姓名；
select a.s_id,b.s_name from score a LEFT JOIN student b on a.s_id = b.s_id
where a.c_id = '01' and a.s_score>80
-- 39、求每门课程的学生人数
select count(*) from score GROUP BY c_id;
-- 40、查询选修"张三"老师所授课程的学生中，成绩最高的学生信息及其成绩
-- 查询老师id
select c_id from course c,teacher d where c.t_id=d.t_id and d.t_name='张三'
-- 查询最高分（可能有相同分数）
select MAX(s_score) from score where c_id='02'
-- 查询信息
select a.*,b.s_score,b.c_id,c.c_name from student a
LEFT JOIN score b on a.s_id = b.s_id
LEFT JOIN course c on b.c_id=c.c_id
where b.c_id =(select c_id from course c,teacher d where c.t_id=d.t_id and d.t_name='张三')
and b.s_score in (select MAX(s_score) from score where c_id='02')
--可以将上面组织一下，一次查询出来如下：
SELECT
st.*
FROM student st
left JOIN score s on s.s_id = st.s_id
left JOIN course c on c.c_id = s.c_id
WHERE s.c_id = (SELECT c_id FROM course c,teacher t WHERE c.t_id = t.t_id AND t.t_name LIKE '张三')
AND s.s_score in (SELECT max(s_score) FROM score WHERE c_id = (SELECT c_id FROM course c,teacher t WHERE c.t_id = t.t_id AND t.t_name LIKE '张三'))
-- 41、查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩
select DISTINCT b.s_id,b.c_id,b.s_score from score a,score b where a.c_id != b.c_id and a.s_score = b.s_score
-- 42、查询每门功成绩最好的前两名
-- 牛逼的写法
select a.s_id,a.c_id,a.s_score from score a
where (select COUNT(1) from score b where b.c_id=a.c_id and b.s_score>=a.s_score)<=2 ORDER BY a.c_id
-- 43、统计每门课程的学生选修人数（超过5人的课程才统计）。要求输出课程号和选修人数，查询结果按人数降序排列，若人数相同，按课程号升序排列
select c_id,count(*) as total from score GROUP BY c_id HAVING total>5 ORDER BY total,c_id ASC
-- 44、检索至少选修两门课程的学生学号
select s_id,count(*) as sel from score GROUP BY s_id HAVING sel>=2
-- 45、查询选修了全部课程的学生信息
select * from student where s_id in(
select s_id from score GROUP BY s_id HAVING count(*)=(select count(*) from course))
--46、查询各学生的年龄
-- 按照出生日期来算，当前月日 < 出生年月的月日则，年龄减一
select s_birth,(DATE_FORMAT(NOW(),'%Y')-DATE_FORMAT(s_birth,'%Y') -
(case when DATE_FORMAT(NOW(),'%m%d')>DATE_FORMAT(s_birth,'%m%d') then 0 else 1 end)) as age
from student;
-- 47、查询本周过生日的学生
select * from student where WEEK(DATE_FORMAT(NOW(),'%Y%m%d'))=WEEK(s_birth)
select * from student where YEARWEEK(s_birth)=YEARWEEK(DATE_FORMAT(NOW(),'%Y%m%d'))
select WEEK(DATE_FORMAT(NOW(),'%Y%m%d'))
-- 48、查询下周过生日的学生
select * from student where WEEK(DATE_FORMAT(NOW(),'%Y%m%d'))+1 =WEEK(s_birth)
-- 49、查询本月过生日的学生
select * from student where MONTH(DATE_FORMAT(NOW(),'%Y%m%d')) =MONTH(s_birth)
-- 50、查询下月过生日的学生
select * from student where MONTH(DATE_FORMAT(NOW(),'%Y%m%d'))+1 =MONTH(s_birth)
-sql语句练习50题(Mysql学习练习版)的更多相关文章
- sql语句练习50题(Mysql版-详加注释)
表名和字段 1.学生表 Student(s_id,s_name,s_birth,s_sex) --学生编号,学生姓名, 出生年月,学生性别 2.课程表 Course(c_id, ...
- sql语句练习50题(Mysql版)
表名和字段–1.学生表Student(s_id,s_name,s_birth,s_sex) –学生编号,学生姓名, 出生年月,学生性别–2.课程表Course(c_id,c_name,t_id) – ...
- sql语句练习50题(Mysql版) 围观
表名和字段 –.学生表 Student(s_id,s_name,s_birth,s_sex) –学生编号,学生姓名, 出生年月,学生性别 –.课程表 Course(c_id,c_name,t_id) ...
- MySQL经典练习题及答案，常用SQL语句练习50题
表名和字段 –1.学生表 Student(s_id,s_name,s_birth,s_sex) –学生编号,学生姓名, 出生年月,学生性别 –2.课程表 Course(c_id,c_name,t_id ...
- 经典SQL语句基础50题
很全面的sql语句大全.都是很基础性的,今天特意整理了下.大家互相学习.大家有好的都可以分享出来, 分享也是一种快乐. --创建数据库 create database SQL50 --打开SQL50 ...
- [转载]sql语句练习50题
Student(Sid,Sname,Sage,Ssex) 学生表 Course(Cid,Cname,Tid) 课程表 SC(Sid,Cid,score) 成绩表 Teacher(Tid,Tname) ...
- sql语句练习50题
Student(Sid,Sname,Sage,Ssex) 学生表 Course(Cid,Cname,Tid) 课程表 SC(Sid,Cid,score) 成绩表 Teacher(Tid,Tname) ...
- PHP如何通过SQL语句将数据写入MySQL数据库呢？
1,php和MySQL建立连接关系 2,打开 3,接受页面数据,PHP录入到指定的表中 1.2两步可直接使用一个数据库链接文件即可:conn.php <?phpmysql_connect(&qu ...
- 解决乱码的方法是，在执行SQL语句之前，将MySQL以下三个系统参数设置为与服务器字符集character-set-server相同的字符集
character-set-server/default-character-set:服务器字符集,默认情况下所采用的. character-set-database:数据库字符集. characte ...
随机推荐
- web自动化测试—selenium游览器多窗口操作
# coding=utf-8'''web游览器多窗口操作: 获取当前窗口句柄 current_window_handle 获取所有窗口句柄 window_handles 切换窗口 switch_to_ ...
- python/shell脚本报异常^M: bad interpreter: No such file or directory
问题:在Windows写了一python脚本,上传Linux服务器执行,报异常*****^M: bad interpreter: No such file or directory 原因:window ...
- 洛谷 P1880 [NOI1995]石子合并
题目描述 在一个圆形操场的四周摆放N堆石子,现要将石子有次序地合并成一堆.规定每次只能选相邻的2堆合并成新的一堆,并将新的一堆的石子数,记为该次合并的得分. 试设计出1个算法,计算出将N堆石子合并成1 ...
- ASP.NET MVC5 之 分部页
1.分部页 _PartialPage.cshtml @model List<string> <a>完美世界</a> @foreach (var item in Mo ...
- jQuery图片区域选择控件_imgAreaSelect
软考报名时发现可以进行头像区域裁剪功能,F12了一下,发现使用了imgAreaSelect控件. 控件官网: http://odyniec.net/projects/imgareaselect/ 控件 ...
- 一个Velocity Template Language学习的框架
Velocity Template Language(VTL)使得数据展示和后台代码的开发分离开来,最初用在基于servlet的网站开发上,它的这一特性使得它在应付MVC Web开发模式时显得尤其合适 ...
- javascript异步下载 Promise实现
一般下载都是直接打开一个链接就行.var URL = 'XXXX';window.open(URL)其实这样会有些问题:1. 浏览器禁止打开新窗口,导致无法下载 那么怎么解决呢?这样: <a h ...
- (转)中国电信友华PT921、PT921G光猫设置路由，无线WIFI设置
中国电信友华PT921.PT921G光猫设置路由,无线WIFI设置. 第一步,用管理员帐号密码登陆,打开浏览器,输入http://192.168.1.1 登陆帐号:telecomadmin登陆密码:n ...
- RocketMQ学习笔记（16）----RocketMQ搭建双主双从（异步复制）集群
1. 修改RocketMQ默认启动端口 由于只有两台机器,部署双主双从需要四个节点,所以只能修改rocketmq的默认启动端口,从官网下载rocketmq的source文件,解压后使用idea打开,全 ...
- Java基础(七)--Exception异常处理
发现错误的理想时机是程序运行之前(编译期),然后不太现实,很多异常无法被发现(特别是业务上的数据),需要在运行时解决. 错误恢复机制保证代码健壮性的方式,异常处理在程序中很常见,也是必须的,必须考虑有 ...