Feel Good Time Limit: 3000MS   Memory Limit: Unknown   64bit IO Format: %lld & %llu Bill is developing a new mathematical theory for human emotions. His recent investigations are dedicated to studying how good or bad days influent people's memories a…
转:http://www.cnblogs.com/v10258/p/3263939.html JQuery插件繁多,下面是个人在工作和学习中用到感觉不错的,特此记录. UI: jquery UI(官方的UI插件,很好很强大功能完备,灵活性很强,有十几套主题可供选择,但由于其中大量使用了CSS3,可能会对你造成兼容性的困扰) jQuery EasyUI (现在很受欢迎的一套UI,方便集成,但会有一些小问题,灵活性也有所不足,有些地方需要手动调整,前提是你要先从凌乱的代码中找到它的位置) 布局: l…
最近发现docker感觉不错,接下来开始学习docker方面的技术.lxc也可以学学. storm,kafka也要熟悉起来.…
逛csdn看见的一个知识阶梯,感觉不错: 计算机组成原理 →  DOS命令 → 汇编语言 → C语言(不包括C++).代码书写规范 → 数据结构.编译原理.操作系统 → 计算机网络.数据库原理.正则表达式 → 其它语言(包括C++).架构…… 原作者昵称为“赵4老师".…
题目: 思路: 预处理出a[i]在哪个范围区间内是最小的,然后直接遍历a数组求答案就可以了. 这个预处理的技巧巧妙的用了之前的处理结果.(大佬tql) 代码: #include <bits/stdc++.h> #define inf 0x3f3f3f3f #define MAX 1e3 #define FRE() freopen("in.txt","r",stdin) #define FRO() freopen("out.txt",&…
Feel Good   Description Bill is developing a new mathematical theory for human emotions. His recent investigations are dedicated to studying how good or bad days influent people's memories about some period of life. A new idea Bill has recently devel…
最近阿里推出了公共DNS,这对于普通的网友来说估计没什么用处,但对于我们建站人来说,确实是一个不错的消息.一听说阿里出公共DNS,博主就立马换电信的DNS换下了.经过这几天的测试,相当满意! 个人感觉阿里云DNS解析速度并不如本地电信的DNS,但普通网友是感觉不出来的,毕竟DNS解析速度也就那0.0几秒,几乎感觉不出来.而阿里云的真正优势在于稳定性,BGP多线融合,解析生效速度. 阿里云的稳定性大家都有目共睹的,一年下来也不会出现过几次故障,可以说是非常的稳定.像我们普通的本地DNS就不一定了,…
Bill is developing a new mathematical theory for human emotions. His recent investigations are dedicated to studying how good or bad days influent people's memories about some period of life. A new idea Bill has recently developed assigns a non-negat…
Feel Good Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 16786   Accepted: 4627 Case Time Limit: 1000MS   Special Judge Description Bill is developing a new mathematical theory for human emotions. His recent investigations are dedicated…
自己的作业: 1. count = 0 while count <= 9 : count += 1 if count == 7 : continue print (count) 2. count = 1 sum = 0 while count <=100 : sum = sum + count count += 1 print (sum) 3. count = 1 while count <=100 : print (count) count += 2 4. count = 0 whil…