「SPOJ1487」Query on a tree III 传送门 把树的 \(\text{dfs}\) 序抠出来,子树的节点的编号位于一段连续区间,然后直接上建主席树区间第 \(k\) 大即可. 参考代码: #include <algorithm> #include <cstdio> #define rg register #define file(x) freopen(x".in", "r", stdin), freopen(x"…

[BZOJ1803]Spoj1487 Query on a tree III Description You are given a node-labeled rooted tree with n nodes. Define the query (x, k): Find the node whose label is k-th largest in the subtree of the node x. Assume no two nodes have the same labels. Input…

「luogu2633」Count on a tree 传送门 树上主席树板子. 每个节点的根从其父节点更新得到,查询的时候差分一下就好了. 参考代码: #include <algorithm> #include <cstdio> #define rg register #define file(x) freopen(x".in", "r", stdin), freopen(x".out", "w", s…

SP1487 PT07J - Query on a tree III 题意翻译 你被给定一棵带点权的n个点的有根数,点从1到n编号. 定义查询 query(x,k): 寻找以x为根的k大点的编号(从小到大排序第k个点) 假设没有两个相同的点权. 输入格式: 第一行为整数n,第二行为点权,接下来n-1行为树边,接下来一行为整数m,下面m行为两个整数x,k,代表query(x,k) 输出格式: m行,输出每次查询的结果. Translated by @vegacx 题目描述 You are give…

PT07J - Query on a tree III #tree You are given a node-labeled rooted tree with n nodes. Define the query (x, k): Find the node whose label is k-th largest in the subtree of the node x. Assume no two nodes have the same labels. Input The first line c…

「SPOJ10707」Count on a tree II 传送门 树上莫队板子题. 锻炼基础,没什么好说的. 参考代码: #include <algorithm> #include <cstdio> #include <cmath> #define rg register #define file(x) freopen(x".in", "r", stdin), freopen(x".out", "w…

Description You are given a node-labeled rooted tree with n nodes. Define the query (x, k): Find the node whose label is k-th largest in the subtree of the node x. Assume no two nodes have the same labels. Input The first line contains one integer n…

题目描述 You are given a node-labeled rooted tree with n nodes. Define the query (x, k): Find the node whose label is k-th largest in the subtree of the node x. Assume no two nodes have the same labels. 输入 The first line contains one integer n (1 <= n <…

题意 你被给定一棵带点权的n个点的有根数,点从1到n编号. 定义查询 query(x,k): 寻找以x为根的k大点的编号(从小到大排序第k个点) 假设没有两个相同的点权. 输入格式: 第一行为整数n,第二行为点权,接下来n-1行为树边,接下来一行为整数m,下面m行为两个整数x,k,代表query(x,k) 输出格式: m行,输出每次查询的结果. 题解 先一遍dfs,然后建个主席树,带上去直接跑一跑就好了 我忘了注意dfs序的位置和原来的编号……结果调了半天啥都调不出来…… //minamoto…

基本等同这个,只是询问的东西不大一样而已. http://www.cnblogs.com/autsky-jadek/p/4159897.html #include<cstdio> #include<algorithm> #include<cmath> using namespace std; int Num,CH[12],f,c; inline void R(int &x){ c=0;f=1; for(;c<'0'||c>'9';c=getchar(…