hdu 3374 String Problem 最小表示法 view code#include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #include <map> #include <string> using namespace std; const int N = 10010; int n; char s[105]; map<…

题目链接:https://vjudge.net/problem/HDU-3374 String Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3646    Accepted Submission(s): 1507 Problem Description Give you a string with length N,…

#include <iostream> #include <cstring> #include <cstdio> using namespace std; int nxt[1000005], len; char a[1000005]; void mknxt(){ int i=0, j; nxt[0] = j = -1; while(i<len){ if(j==-1 || a[i]==a[j]) nxt[++i] = ++j; else j = nxt[j]; }…

Give you a string with length N, you can generate N strings by left shifts. For example let consider the string “SKYLONG”, we can generate seven strings: String Rank SKYLONG 1 KYLONGS 2 YLONGSK 3 LONGSKY 4 ONGSKYL 5 NGSKYLO 6 GSKYLON 7 and lexicograp…

String Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4828    Accepted Submission(s): 1949 Problem Description Give you a string with length N, you can generate N strings by left shifts…

Give you a string with length N, you can generate N strings by left shifts. For example let consider the string “SKYLONG”, we can generate seven strings:String Rank SKYLONG 1KYLONGS 2YLONGSK 3LONGSKY 4ONGSKYL 5NGSKYLO 6GSKYLON 7and lexicographically…

链接: https://vjudge.net/problem/HDU-3374 题意: Give you a string with length N, you can generate N strings by left shifts. For example let consider the string "SKYLONG", we can generate seven strings: String Rank SKYLONG 1 KYLONGS 2 YLONGSK 3 LONGS…

地址:http://acm.hdu.edu.cn/showproblem.php?pid=3374 题目: String Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3029    Accepted Submission(s): 1230 Problem Description Give you a string wi…

一开始没太看懂什么意思,拿笔反复推了一遍才大概知道最大最小表示法是怎么求的,感觉太神奇了... #include <iostream> #include <cstdio> #include <string.h> #pragma warning ( disable : 4996 ) using namespace std; inline int Max(int a,int b) { return a>b?a:b; } inline int Min(int a,int…

传送门:https://ac.nowcoder.com/acm/contest/887/A 题意:大意就是给你一个只含有0和1的字符串,找出一种分割方法,使得每个分割出的字符串都是在该字符串自循环节中最小 思路: 一: 最小表示法的模板题了,数据范围比较小.每次枚举字符串的最长长度,用最小表示法进行判断即可. 最小表示法的介绍:https://oi-wiki.org/string/minimal-string/ 代码: #include<bits/stdc++.h> using namespa…