Alice has a magic array. She suggests that the value of a interval is equal to the sum of the values in the interval, multiplied by the smallest value in the interval. Now she is planning to find the max value of the intervals in her array. Can you h…
The Preliminary Contest for ICPC China Nanchang National Invitational 题目一览表 考察知识点 I. Max answer 单调栈+暴力?? J. Distance on the tree 树链剖分 M. Subsequence 思维??…
Distance on the tree DSM(Data Structure Master) once learned about tree when he was preparing for NOIP(National Olympiad in Informatics in Provinces) in Senior High School. So when in Data Structure Class in College, he is always absent-minded about…
目录 Contest Info Solutions A. PERFECT NUMBER PROBLEM D. Match Stick Game G. tsy's number H. Coloring Game' I. Max answer J. Distance on the tree K. MORE XOR M. Subsequence Contest Info Practice Link Solved A B C D E F G H I J K L M 8/13 O - - O - - O…
题目链接:https://nanti.jisuanke.com/t/38228 题目大意:一个区间的值等于该区间的和乘以区间的最小值.给出一个含有n个数的序列(序列的值有正有负),找到该序列的区间最大值. 样例输入: 5 1 2 3 4 5 样例输出: 36 解题思路:如果序列的值全部为正值的话,可以说很简单,用一个单调栈加前缀和就可以了直接a.但是区间中存在负值,这个问题就变得复杂多了. 首先我们可以用两次单调栈,在O(n)的时间内,对于每个a[i]找到一个最大区间[ l[i] , r[i]…
打网络赛 比赛前的准备工作要做好 确保 c++/java/python的编译器能用 打好模板,放在桌面 A. PERFECT NUMBER PROBLEM #include <cstdio> #include <cstdlib> #include <cmath> #include <cstring> #include <string> #include <algorithm> #include <set> #include…
Alice has a magic array. She suggests that the value of a interval is equal to the sum of the values in the interval, multiplied by the smallest value in the interval. Now she is planning to find the max value of the intervals in her array. Can you h…
题面 题意:一个5e5的数组,定义一个区间的值为 这个区间的和*这个区间的最小值,注意数组值有负数有正数,求所有区间中最大的值 题解:如果全是正数,那就是原题 POJ2796 单调栈做一下就ok 我们现在有负数,考虑这段区间,他的和必须是负数,由于导致和为负数,最小值一定也是负数, 那对于这样一个和为负的区间进行扩展的时候,遇见下一个数,是负数,我们一定会扩展,无论这个负数大小 遇见下一个是正数,如果和没有变正,那就可以继续扩展下去(不更新答案罢了) 所以我们对于那些和为负的区间,单独统计一下答…
A. PERFECT NUMBER PROBLEM 题目链接:https://nanti.jisuanke.com/t/38220 题意: 输出前五个完美数 分析: 签到.直接百度完美数输出即可 #include<bits/stdc++.h> #define ios std::ios::sync_with_stdio(false) , std::cin.tie(0) , std::cout.tie(0) #define sd(n) scanf("%d",&n) #d…
Max answer Alice has a magic array. She suggests that the value of a interval is equal to the sum of the values in the interval, multiplied by the smallest value in the interval. Now she is planning to find the max value of the intervals in her array…