贪心+stack Codeforces Beta Round #5 C. Longest Regular Bracket Sequence

【贪心+stack Codeforces Beta Round #5 C. Longest Regular Bracket Sequence】的更多相关文章

贪心+stack Codeforces Beta Round #5 C. Longest Regular Bracket Sequence

题目传送门 /* 题意:求最长括号匹配的长度和它的个数贪心+stack:用栈存放最近的左括号的位置,若是有右括号匹配,则记录它们的长度,更新最大值,可以在O (n)解决详细解释:http://blog.csdn.net/taoxin52/article/details/26012167 */ #include <cstdio> #include <algorithm> #include <cstring> #include <cmath> #includ…

Codeforces Beta Round #5 C. Longest Regular Bracket Sequence 栈/dp

C. Longest Regular Bracket Sequence Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/problemset/problem/5/C Description This is yet another problem dealing with regular bracket sequences. We should remind you that a bracket sequence…

Codeforces Beta Round #3 D. Least Cost Bracket Sequence 优先队列

D. Least Cost Bracket Sequence 题目连接: http://www.codeforces.com/contest/3/problem/D Description This is yet another problem on regular bracket sequences. A bracket sequence is called regular, if by inserting "+" and "1" into it we get a…

【Codeforces】CF 5 C Longest Regular Bracket Sequence（dp）

题目传送门:QWQ 分析洛谷题解里有一位大佬讲的很好. 就是先用栈预处理出可以匹配的左右括号在数组中设为1 其他为0 最后求一下最长连续1的数量. 代码 #include <bits/stdc++.h> using namespace std; ; char s[maxn]; int vis[maxn], Stack[maxn], top; int main(){ scanf(); ); ;i<=n;i++){ if(s[i]=='('){ Stack[++top]=i; } els…

（CodeForces - 5C）Longest Regular Bracket Sequence（dp+栈）（最长连续括号模板）

(CodeForces - 5C)Longest Regular Bracket Sequence time limit per test:2 seconds memory limit per test:256 megabytes input:standard input output:standard output This is yet another problem dealing with regular bracket sequences. We should remind you t…

Codeforces 5C Longest Regular Bracket Sequence(DP+括号匹配)

题目链接:http://codeforces.com/problemset/problem/5/C 题目大意:给出一串字符串只有'('和')',求出符合括号匹配规则的最大字串长度及该长度的字串出现的次数.解题思路:设dp[i]为到i的最大括号匹配,我们每次遇到一个'('就将其下标存入栈中,每次遇到')'就取出当前栈中里它最近的'('下标即栈顶t.不能直接dp[i]=i-t+1,比如(()()())这样的例子就会出错,应为dp[i]=dp[i-1]+i-t+1. 代码 #include<bits/…