cf486A Calculating Function】的更多相关文章

A. Calculating Function time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output For a positive integer n let's define a function f: f(n) =  - 1 + 2 - 3 + .. + ( - 1)nn Your task is to calculate f(n…
A. Calculating Function Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/486/problem/A Description For a positive integer n let's define a function f: f(n) =  - 1 + 2 - 3 + .. + ( - 1)nn Your task is to calculate f(n) for a…
Calculating Function time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output For a positive integer n let's define a function f: f(n) =  - 1 + 2 - 3 + .. + ( - 1)nn Your task is to calculate f(n) f…
A. Calculating Function   For a positive integer n let's define a function f: f(n) =  - 1 + 2 - 3 + .. + ( - 1)nn Your task is to calculate f(n) for a given integer n. Input The single line contains the positive integer n (1 ≤ n ≤ 1015). Output Print…
Problem description For a positive integer n let's define a function f: f(n) =  - 1 + 2 - 3 + .. + ( - 1)nn Your task is to calculate f(n) for a given integer n. Input The single line contains the positive integer n (1 ≤ n ≤ 1015). Output Print f(n) …
#include<iostream> #include<cstring> #include<cstdio> /* 题意:计算f(n) = -1 + 2 -3 +4.....+(-1)^n *n的值 思路:偶数和 - 奇数和(或者用等差数列计算化简得到结果) */ #include<algorithm> #define N 10000 using namespace std; int main(){ long long n; cin>>n; ==)…
题目链接:www.codeforces.com/problemset/problem/486/A题意:求表达式f(n)的值.(f(n)的表述见题目)C++代码: #include <iostream> using namespace std; long long f(long long n) { == ) ; else - n; } int main() { long long n; cin >> n; cout << f(n) << endl; ; } C…
拉了CF583和CF486的两套div2题目 还是先贴宏定义部分 #define MAXN 1000000+5#define MOD 1000000007#define PI (acos(-1.0))#define EPS 1e-6#define MMT(s,a) memset(s, a, sizeof s)#define GO(i,a,b) for(int i = (a); i < (b); ++i)#define GOE(i,a,b) for(int i = (a); i <= (b);…
A. Calculating Function time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output For a positive integer n let's define a function f: f(n) =  - 1 + 2 - 3 + .. + ( - 1)nn Your task is to calculate f(n…
A. Calculating Function 水题,分奇数偶数处理一下就好了 #include<stdio.h> #include<iostream> using namespace std; int main() { long long n;scanf("%lld",&n); ==) printf("%lld\n",(n-1LL)/2LL - n); else printf("%lld\n",n/2LL); }…
题目地址:http://codeforces.com/contest/486 A题.Calculating Function 奇偶性判断,简单推导公式. #include<cstdio> #include<iostream> using namespace std; int main() { long long n; cin>>n; ==) { cout<<(-)*((n-)/+)+n<<endl; } else cout<<((n-…
转载请注明出处: http://www.cnblogs.com/fraud/          ——by fraud A. Calculating Function 水题,判个奇偶即可 #include <iostream> #include <sstream> #include <ios> #include <iomanip> #include <functional> #include <algorithm> #include &…
Codeforces Round #277 (Div. 2) A. Calculating Function time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output For a positive integer n let's define a function f: f(n) =  - 1 + 2 - 3 + .. + ( - 1)n…
之所以在codeforces上找这100道水题的原因是为了巩固我对最近学的编程语言的掌握程度. 找的方式在codeforces上的PROBLEMSET中过的题最多的那些题里面出现的最前面的10个题型,它们是: math(数学) brute force(暴力) strings(字符串) implementation(模拟) greedy(贪心) sortings(排序) number theory(数论) constructive algorithm dp(动态规划) shortest path(…
门户:Codeforces Round #277 (Div. 2) 486A. Calculating Function 裸公式= = #include <cstdio> #include <cstring> #include <algorithm> using namespace std ; typedef long long LL ; LL n ; int main () { while ( ~scanf ( "%I64d" , &n )…
现在我们在工作中,在开发中都会或多或少的用到图表统计数据显示给用户.通过图表可以很直观的,直接的将数据呈现出来.这里我就介绍说一下利用百度开源的echarts图表技术实现的具体功能. 1.对于不太理解echarts是个怎样技术的开发者来说,可以到echarts官网进行学习了解,官网有详细的API文档和实例供大家参考学习. 2.以下是我在工作中实现整理出来的实例源码: 公用的支持js文件 echarts.js.echarts.min.js,还有其他的图表需要支持的js文件也可以到官网下载 echa…
Calculating Stereo Pairs Written by Paul BourkeJuly 1999 Introduction The following discusses computer based generation of stereo pairs as used to create a perception of depth. Such depth perception can be useful in many fields, for example, scientif…
The System Catalogs of PostgreSQLscott=# \dS List of relations Schema | Name | Type | Owner ------------+---------------------------------+----------+---------- pg_catalog | pg_aggregate | table | postgres pg_catalog | pg_am | table | postgres pg_cat…
General Purpose Hash Function Algorithms post@: http://www.partow.net/programming/hashfunctions/index.html       Description Hashing Methodologies Hash Functions and Prime Numbers Bit Biases Various Forms Of Hashing String Hashing Cryptographic Hashi…
c++ virturn function -- 虚函数 pure irtual function  -- 纯虚函数   先看例子 #include <iostream> using namespace std; class Polygon { protected: int width, height; public: void set_values (int a, int b) { width=a; height=b; } virtual int area() = 0 ;//{return 0…
http://codeforces.com/problemset/problem/837/E   题意: f(a, 0) = 0; f(a, b) = 1 + f(a, b - gcd(a, b)) 输出f(a,b) a=A*gcd(a,b)    b=B*gcd(a,b) 一次递归后,变成了 f(A*gcd(a,b),(B-1)*gcd(a,b)) 若gcd(A,(B-1))=1,那么 这一层递归的gcd(a,b)仍等于上一层递归的gcd(a,b) 也就是说,b-gcd(a,b),有大量的时间…
Vasya is studying number theory. He has denoted a function f(a, b) such that: f(a, 0) = 0; f(a, b) = 1 + f(a, b - gcd(a, b)), where gcd(a, b) is the greatest common divisor of a and b. Vasya has two numbers x and y, and he wants to calculate f(x, y).…
Discription Vasya is studying number theory. He has denoted a function f(a, b) such that: f(a, 0) = 0; f(a, b) = 1 + f(a, b - gcd(a, b)), where gcd(a, b) is the greatest common divisor of a and b. Vasya has two numbers x and y, and he wants to calcul…
题目链接 Jane loves string more than anything. She made a function related to the string some days ago and forgot about it. She is now confused about calculating the value of this function. She has a string T with her, and value of string S over function…
在使用Myeclipse10部署完项目后,原先不出错的项目,会有红色的叉叉,JSP页面会提示onclick函数错误 Cannot return from outside a function or method. 释义:无法从外部返回函数或方法. 如下图所示: 为此我在百度上了解后找到了下面的解决方案: 方法:window -->preferences -->myeclipse -->validation -->javascript validator for Js files 然…
本篇主要介绍普通函数.匿名函数.闭包函数 目录 1. 普通函数:介绍普通函数的特性:同名覆盖.arguments对象.默认返回值等. 2. 匿名函数:介绍匿名函数的特性:变量匿名函数.无名称匿名函数. 3. 闭包函数:介绍闭包函数的特性. 1. 普通函数 1.1 示例 function ShowName(name) { alert(name); } 1.2 Js中同名函数的覆盖 在Js中函数是没有重载,定义相同函数名.不同参数签名的函数,后面的函数会覆盖前面的函数.调用时,只会调用后面的函数.…
1.问题: 测试php7.0 链接mysql数据库的时候发生错误: Fatal error: Uncaught Error: Call to undefined function mysqli_connect() 即使把 /etc/php/7.0/apache2/php.ini 中的行: ;extension=php_mysql.dll 修改成(即:取消行前面的分号";"): extension=php_mysql.dll 问题依然没解决. 测试文件: require_once __D…
当文档载入时执行function函数里的代码, 这部分代码主要声明,页面加载后 "监听事件" 的方法.例如: $(document).ready( $("a").click(function(){alert('你点我干嘛')}); ): 这句的意思是:页面加载成功后,页面内的所有链接在"点击"事件的时候,提示"你点我干嘛"…
Function.prototype.toString这个原型方法可以帮助你获得函数的源代码, 比如: function hello ( msg ){ console.log("hello") } console.log( hello.toString() ); 输出: 'function hello( msg ){ \ console.log("hello") \ }' 这个方法真是碉堡了-, 通过合适的正则, 我们可以从中提取出丰富的信息. 函数名 函数形参列表…
转:ORA-15186: ASMLIB error function = [asm_open], error = [1], 2009-05-24 13:57:38http://space.itpub.net/471666/viewspace-406996ORA-15186: ASMLIB error function = [asm_open], error = [1], mesg = [Operation not permitted]参考 Metalink   Note:398622.1Subj…