#include<cstdio> int lb,rb,data; long long sum[5000000],extra[5000000]; void add(int l,int r,int now) {     if(lb<=l&&rb>=r){         extra[now]+=data;         sum[now]+=data*(r-l+1);         return;     }     int mid=(l+r)/2,nl=2*now,…

题目链接:poj3468 题意:给定一段数组,有两种操作,一种是给某段区间加c,另一种是查询一段区间的和 思路:暴力的方法是每次都给这段区间的点加c,查询也遍历一遍区间,复杂度是n*n,肯定过不去,另一种思路是用线段树记录区间的和,每次查询的复杂度是lgn,修改不必更新到每个点,当某个区间全被修改时,我们可以给它加一个懒惰标记,表示这个区间的所有下面节点都需要更新,只是因为现在不需要使用而暂时没有更新.这样修改的复杂度也降到了lgn ac代码: #include <iostream> #inc…

A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 97196   Accepted: 30348 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of…

A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 92921   Accepted: 28910 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of…

我的线段树真的没救了......还是多练几道吧....... You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each number in a given interval. The other is to ask for the sum of numbers in a…

A Simple Problem with Integers Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 85502   Accepted: 26556 Case Time Limit: 2000MS Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of…

题目链接: http://poj.org/problem?id=3468 题意: 输入 n, m表初始有 n 个数, 接下来 m 行输入, Q x y 表示询问区间 [x, y]的和: C x y z 表示区间 [x, y] 内所有数加上 z : 思路: 线段树区间更新&区间求和模板: 代码: #include <iostream> #include <stdio.h> #define ll long long #define lson l, mid, rt <<…

A Simple Problem With Integers POJ-3468 这题是区间更新的模板题,也只是区间更新和区间查询和的简单使用. 代码中需要注意的点我都已经标注出来了,容易搞混的就是update函数里面还需要计算sum数组.因为这里查询的时候是直接用sum查询结点. //区间更新,区间查询 #include<iostream> #include<cstdio> #include<algorithm> #include<cstring> #inc…

#include<map> #include<set> #include<list> #include<cmath> #include<queue> #include<stack> #include<vector> #include<cstdio> #include<cstring> #include<iostream> #include<algorithm> #define…

https://vjudge.net/problem/POJ-3468 线段树区间更新(lazy数组)模板题 #include<iostream> #include<cstdio> #include<queue> #include<cstring> #include<algorithm> #include<cmath> #include<map> #define lson l, m, rt<<1 #define…