https://vjudge.net/problem/UVA-11582 首先明确,斐波那契数列在模c的前提下是有循环节的.而f[i] = f[i-1]+f[i-2](i>=2)所以只要有两个连续的值和开头的一样,后面就开始循环,两两组合共有c*c种. 找到循环节之后 #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<cstdlib…

#include<cstdio> #include<iostream> #include<cstring> #include<algorithm> using namespace std; ; //如果是1005就会RE,当不确定时,最好取大点. int A[maxn]; #define LL unsigned long long // 注意不能用long long, 因为long long // 最大值只能取到2 ^63 - 1 LL a, b; int…

这是个开心的题目,因为既可以自己翻译,代码又好写ヾ(๑╹◡╹)ﾉ" The i’th Fibonacci number f(i) is recursively defined in the following way: • f(0) = 0 and f(1) = 1 • f(i + 2) = f(i + 1) + f(i) for every i ≥ 0 Your task is to compute some values of this sequence. Input Input begins…

思路是按紫书上说的来. 参考了:https://blog.csdn.net/qwsin/article/details/51834161  的代码: #include <cstdio> #include <iostream> #include <cmath> using namespace std; typedef unsigned long long ll; +; ll a, b; int n,M; int f[MAXN*MAXN]; int pow_mod(ll p…

/** 题目:Colossal Fibonacci Numbers! UVA 11582 链接:https://vjudge.net/problem/UVA-11582 题意:f[0] = 1, f[1] = 1; 给定一个n,求f[a^b]%n的结果.a,b达到2^64 - 1大. 思路:a,b很大,用无符号长整型;我还是太菜了,自己没想出来.这道题很显然是找循环节的题.但我不知怎么找. lrj P316 思路就是,由于fibonacci数是由前两个数相加得来,又%n;所以所有fibonacc…

Colossal Fibonacci Numbers 想先说下最近的状态吧,已经考完试了,这个暑假也应该是最后刷题的暑假了,打完今年acm就应该会退了,但是还什么都不会呢? +_+ 所以这个暑假,一定要竭尽全力地去刷题,当然,也是能好好刷题的最后时间了. [题目链接]Colossal Fibonacci Numbers [题目类型]数学 &题意: 求Fi(f(a^b)%n) Fi()是斐波那契 &题解: 注意:unsigned时 要把%d全换成%u 数学大法好. 首先你要能看出来这是有循环…

巨大的斐波那契数 The i'th Fibonacci number f (i) is recursively defined in the following way: f (0) = 0 and f (1) = 1 f (i+2) = f (i+1) + f (i)  for every i ≥ 0 Your task is to compute some values of this sequence. Input begins with an integer t ≤ 10,000, th…

评测地址:http://acm.hust.edu.cn/vjudge/problem/41990 The i'th Fibonacci number f (i) is recursively de ned in the following way: f () = and f () = f (i + ) = f (i + ) + f (i) Your task is to compute some values of this sequence. Input Input begins with a…

题目链接:https://cn.vjudge.net/problem/UVA-11582 /* 问题 输入a,b,n(0<a,b<2^64(a and bwill not both be zero) and 1<n<1000) 计算并输出f(a^b)%n的结果 其中f(i)是斐波那契数列 解题思路 所有的结果都是f(i)对n取模,不妨设F(i)=f(i)%n.不难发现当F(i),F(i+1)出现重复的时候,整个序列就开始出现重复. 所以设周期为mod,计算出一个循环周期F(0)~f…

Problem Description The i’th Fibonacci number f(i) is recursively defined in the following way: •f(0) = 0 and f(1) = 1 •f(i + 2) = f(i + 1) + f(i) for every i ≥ 0 Your task is to compute some values of this sequence Input Input begins with an integer…