Operation the Sequence                                                                     Time Limit: 3000/1500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)                                                                            …
HDU 5063 Operation the Sequence 题目链接 把操作存下来.因为仅仅有50个操作,所以每次把操作逆回去执行一遍,就能求出在原来的数列中的位置.输出就可以 代码: #include <cstdio> #include <cstring> #include <algorithm> using namespace std; typedef long long ll; const int N = 100005; const ll MOD = 1000…
题目链接:pid=5063" target="_blank">http://acm.hdu.edu.cn/showproblem.php?pid=5063 Problem Description You have an array consisting of n integers: a1=1,a2=2,a3=3,-,an=n. Then give you m operators, you should process all the operators in order…
http://acm.hdu.edu.cn/showproblem.php?pid=5063 题目大意: 题目意思还是比较简单.所以就不多少了.注意这句话,对解题有帮助. Type4: Q i query current value of a[i], this operator will have at most 50. 解题思路: 因为给定n和m都是100000,我们每一步都做具体的操作,时间将是O(n*m),肯定超时.最开始的时候 我怎么想都不知道怎么解决.以为是线段树.比赛完了以后,看了解…
若 [i, j] 满足, 则 [i, j+1], [i, j+2]...[i,n]均满足 故设当前区间里个数为size, 对于每个 i ,找到刚满足 size == k 的 [i, j], ans += n - j + 1 . i++ 的时候看看需不需要size-- 就可以更新了. #include <iostream> #include <cstdio> #include <cstring> using namespace std; #define LL long l…
先找相邻差值的最大,第二大,第三大 删去端点会减少一个值, 删去其余点会减少两个值,新增一个值,所以新增和现存的最大的值比较一下取最大即可 #include <iostream> #include <cstdio> #include <cmath> using namespace std; #define LL long long ; int t, n, p1, p2, p3; LL a[N]; LL s1[N], s2[N]; LL sum; int main() {…
http://acm.hdu.edu.cn/showproblem.php?pid=5063 思路:因为3查询最多50,所以可以在查询的时候逆操作找到原来的位置,然后再求查询的值. #include <cstdio> #include <iostream> #include <cstring> #include <algorithm> #define ll long long using namespace std; ; int n,m; ]; ]; ll…
King's Cake Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 736    Accepted Submission(s): 539 Problem Description It is the king's birthday before the military parade . The ministers prepared a…
注意到查询次数不超过50次,那么能够从查询位置逆回去操作,就能够发现它在最初序列的位置,再逆回去就可以求得当前查询的值,对于一组数据复杂度约为O(50*n). Operation the Sequence Time Limit: 3000/1500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 463    Accepted Submission(s): 187 Problem…
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