H - Tempter of the Bone DFS】的更多相关文章

小明做了一个很久很久的梦,醒来后他竟发现自己和朋友在一个摇摇欲坠的大棋盘上,他们必须得想尽一切办法逃离这里.经过长时间的打探,小明发现,自己所在的棋盘格子上有个机关,上面写着“你只有一次机会,出发后t秒大门会为你敞开”,而他自己所在的棋盘是大小为 N*M 的长方形,他可以向上下左右四个方向移动(不可走有障碍点).棋盘中有一扇门.根据机关的提示,小明顿时明白了,他和朋友必须在第 t 秒到门口.而这一切,没有回头路!因为一旦他移动了,他刚才所在的点就会消失,并且他不能在一个点上停留超过一秒,不然格子…
HDU 1010 题目大意:给定你起点S,和终点D,X为墙不可走,问你是否能在 T 时刻恰好到达终点D. 参考: 奇偶剪枝 奇偶剪枝简单解释: 在一个只能往X.Y方向走的方格上,从起点到终点的最短步数为T1,并记其他任意走法所需步数为T2,则T2-T1一定为偶数. 即若某一点到终点的最短步数为T1,且T3-T1为奇数,则一定无法话费T3步恰好到达终点. /*HDU 1010 ------ Tempter of the Bone DFS*/ #include <cstdio> #include…
Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 82702    Accepted Submission(s): 22531 Problem Description The doggie found a bone in an ancient maze, which fascinated him a…
Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 92175    Accepted Submission(s): 25051 Problem Description The doggie found a bone in an ancient maze, which fascinated him a…
http://acm.hdu.edu.cn/showproblem.php?pid=1010   //题目链接 http://ycool.com/post/ymsvd2s//一个很好理解剪枝思想的博客 http://blog.csdn.net/chyshnu/article/details/6171758//一个很好举例的博客 Problem Description The doggie found a bone in an ancient maze, which fascinated him…
Tempter of the Bone Time Limit: 2 Seconds      Memory Limit: 65536 KB The doggie found a bone in an ancient maze, which fascinated him a lot. However, when he picked it up, the maze began to shake, and the doggie could feel the ground sinking. He rea…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1010 Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 131057    Accepted Submission(s): 35308 Problem Description The doggie fou…
Tempter of the Bone [从零开始DFS(1)] 从零开始DFS HDOJ.1342 Lotto [从零开始DFS(0)] - DFS思想与框架/双重DFS HDOJ.1010 Tempter of the Bone [从零开始DFS(1)] -DFS四向搜索/奇偶剪枝 HDOJ(HDU).1015 Safecracker [从零开始DFS(2)] -DFS四向搜索变种 HDOJ(HDU).1016 Prime Ring Problem (DFS) [从零开始DFS(3)] -小…
M - Tempter of the Bone Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Description The doggie found a bone in an ancient maze, which fascinated him a lot. However, when he picked it up, the maze began to shake, and the d…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1010 题目大意: 输入 n m t,生成 n*m 矩阵,矩阵元素由 ‘.’ 'S' 'D' 'X' 四类元素组成. S'代表是开始位置: 'D'表示结束位置:'.'表示可以走的路:'X'表示是墙. 问:从‘S’  能否在第 t 步 正好走到 'D'. 解题思路: 平常心态做dfs即可,稍微加个奇偶剪枝,第一次做没经验,做过一次下次就知道怎么做了.最后有代码注释解析. AC Code: #includ…
需要剪枝否则会超时,然后就是基本的深搜了 #include<cstdio> #include<stdio.h> #include<cstdlib> #include<cmath> #include<iostream> #include<algorithm> #include<cstring> #include<vector> #include<queue> #define INF 0x3f3f3f3…
<题目链接> 题目大意:一个迷宫,给定一个起点和终点,以及一些障碍物,所有的点走过一次后就不能再走(该点会下陷).现在问你,是否能从起点在时间恰好为t的时候走到终点. 解题分析:本题恰好要在某一时刻到达,所以需要用到可行性剪枝中的奇偶剪枝,如果在某一点,它所剩的步数与到终点的最短距离之差是偶数,说明这种情况有可能恰好在规定时刻到达终点,否则不可能,将其剪去. #include <bits/stdc++.h> using namespace std; ][]; ][]; int n,…
The doggie found a bone in an ancient maze, which fascinated him a lot. However, when he picked it up, the maze began to shake, and the doggie could feel the ground sinking. He realized that the bone was a trap, and he tried desperately to get out of…
Problem Description The doggie found a bone in an ancient maze, which fascinated him a lot. However, when he picked it up, the maze began to shake, and the doggie could feel the ground sinking. He realized that the bone was a trap, and he tried despe…
The doggie found a bone in an ancient maze, which fascinated him a lot. However, when he picked it up, the maze began to shake, and the doggie could feel the ground sinking. He realized that the bone was a trap, and he tried desperately to get out of…
http://acm.hdu.edu.cn/showproblem.php?pid=1010 这题就是问能不能在t时刻走到门口,不能用bfs的原因大概是可能不一定是最短路路径吧. 但是这题要过除了细心外,还需要强力的剪枝. 奇偶性剪枝:参考 http://www.cppblog.com/Geek/archive/2010/04/26/113615.html #include <iostream> #include <cstring> #include <cstdio>…
题目大意:输入三个整数N,M,T.在接下来的N行.M列会有一系列的字符.其中S表示起点,D表示终点. .表示路 . X表示墙...问狗能有在T秒时到达D.如果能输出YES, 否则输出NO 解题思路:DFS+剪枝 代码如下: /* * 1010_3.cpp * * Created on: 2013年8月16日 * Author: Administrator */ #include <iostream> using namespace std; bool flag; int N, M, T; in…
Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 89317    Accepted Submission(s): 24279 Problem Description The doggie found a bone in an ancient maze, which fascinated him a…
Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 125945    Accepted Submission(s): 33969 Problem Description The doggie found a bone in an ancient maze, which fascinated him a…
题目链接:http://ac.jobdu.com/problem.php?pid=1461 详解链接:https://github.com/zpfbuaa/JobduInCPlusPlus 参考代码: // // 1461 Tempter of the bone.cpp // Jobdu // // Created by PengFei_Zheng on 24/04/2017. // Copyright © 2017 PengFei_Zheng. All rights reserved. //…
Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 135529    Accepted Submission(s): 36393 Problem Description The doggie found a bone in an ancient maze, which fascinated him…
Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 146511    Accepted Submission(s): 39059 Problem Description The doggie found a bone in an ancient maze, which fascinated him…
Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Problem Description The doggie found a bone in an ancient maze, which fascinated him a lot. However, when he picked it up, the maze began to shake…
解题心得: 1.注意审题,此题是在规定的时间达到规定的地点,不能早到也不能晚到.并不是最简单的dfs 2.在规定时间达到规定的地点有几个剪枝: 一.公式:所需的步骤 - x相差行 - y相差列 = 偶数.(这个解释很简单,无论怎么走,都可以把走的总路程分解到x方向和y方向,哪怕反向走,走回来后的步骤+反向走的步骤也一定是偶数,假设运用正交分解走到了终点(上面公式),但是步骤没走够,可以以最终的目标点为起点任选两格来回走消耗步骤,但是减去正交分解的步数后若是奇数,那么在终点来回走将步数消耗完之后必…
Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 58766    Accepted Submission(s): 15983 Problem Description The doggie found a bone in an ancient maze, which fascinated him a…
Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 94669    Accepted Submission(s): 25669 Problem Description The doggie found a bone in an ancient maze, which fascinated him a…
题意  一仅仅狗要逃离迷宫  能够往上下左右4个方向走  每走一步耗时1s  每一个格子仅仅能走一次且迷宫的门仅仅在t时刻打开一次  问狗是否有可能逃离这个迷宫 直接DFS  直道找到满足条件的路径  或者走全然部可能路径都不满足 注意剪枝  当前位置为(r,c)  终点为(ex,ey) 剩下的时间为lt  当前点到终点的直接距离为  d=(ex-r)+(ey-c)   若多走的时间rt=lt-d<0 或为奇数时  肯定是不可能的  能够自己在纸上画一下 每一个点仅仅能走一次的图  走弯路的话多…
Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 102071    Accepted Submission(s): 27649 Problem Description The doggie found a bone in an ancient maze, which fascinated him…
Tempter of the Bone Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 148156    Accepted Submission(s): 39500 Problem Description The doggie found a bone in an ancient maze, which fascinated him a…
Tempter of the Bone Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Description The doggie found a bone in an ancient maze, which fascinated him a lot. However, when he picked it up, the maze began to shake, and the doggi…