Integer Inquiry Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 11678    Accepted Submission(s): 2936 Problem Description One of the first users of BIT's new supercomputer was Chip Diller. He ex…

Integer Inquiry Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 27730   Accepted: 10764 Description 题目链接:http://poj.org/problem?id=1503 One of the first users of BIT's new supercomputer was Chip Diller. He extended his exploration of pow…

 Integer Inquiry  One of the first users of BIT's new supercomputer was Chip Diller. He extended his exploration of powers of 3 to go from 0 to 333 and he explored taking various sums of those numbers. ``This supercomputer is great,'' remarked Chip.…

/* Integer Inquiry Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 15874 Accepted Submission(s): 4079 Problem Description One of the first users of BIT's new supercomputer was Chip Diller. He exte…

Integer Inquiry Time Limit:1000MS     Memory Limit:10000KB     64bit IO Format:%I64d & %I64u Submit Status Description One of the first users of BIT's new supercomputer was Chip Diller. He extended his exploration of powers of 3 to go from 0 to 333 a…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=1047 Integer Inquiry Description One of the first users of BIT's new supercomputer was Chip Diller. He extended his exploration of powers of 3 to go from 0 to 333 and he explored taking various sums of t…

之前杭电上也做过a + b的高精度的题,不过这道题的区别是有多组数据. 之前做的时候开了3个字符数组a,b,c,在计算的时候还要比较a,b长度,短的那个还要加'0',还设置了一个add来存放进位. 现在看来这种算法确实很繁琐. 而这次只用了两个字符数组,一个放加数,一个放和. 相比之前程序更短小了,而且可读性也提高了. 果然办法都是逼出来的. 没有了add,在判断进位的时候就看那一位的ASCII码是否>'9',然后进位. 尤其需要注意的一点是可能会出现连续进位的情况,比如99999 + 1.解决…

1.链接地址: http://poj.org/problem?id=1503 2.题目: Integer Inquiry Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 28115   Accepted: 10925 Description One of the first users of BIT's new supercomputer was Chip Diller. He extended his explorati…

Integer Inquiry Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 15221    Accepted Submission(s): 3912 Problem Description One of the first users of BIT's new supercomputer was Chip Diller. He ex…

Problem D: Integer InquiryTime Limit: 1 Sec Memory Limit: 128 MBSubmit: 41 Solved: 12[Submit][Status][Web Board]DescriptionOne of the first users of BIT’s new supercomputer was Chip Diller. He extended his exploration of powers of 3 to go from 0 to 3…

Integer Inquiry Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 22451    Accepted Submission(s): 6099 Problem Description One of the first users of BIT's new supercomputer was Chip Diller. He e…

Integer Inquiry Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 9196    Accepted Submission(s): 2354 Problem Description One of the first users of BIT's new supercomputer was Chip Diller. He ext…

解题思路:因为给定的数据是多组,所以我们只需要多次做加法就可以了,将上一次的和又作为下一次加法运算的一个加数. 反思:还是题意理解不够清楚,最开始以为只是算三个大数相加,后来才发现是多个,然后注意到当输入a的第一个字符为0的时候结束运算,输出结果.  Integer Inquiry  One of the firstusers of BIT's new supercomputer was Chip Diller. He extended his explorationof powers of 3…

Integer Inquiry 1 import java.util.*; 2 import java.math.*; 3 import java.io.*; 4 import java.text.*; 5 6 public class Main 7 { 8 public static void main(String[] args) 9 { 10 // 对于大量输入,下面方式可能会快一些. 11 Scanner cin=new Scanner(new BufferedInputStream(S…

Problem Description Oneof the first users of BIT's new supercomputer was Chip Diller. He extended hisexploration of powers of 3 to go from 0 to 333 and he explored taking varioussums of those numbers.  ``This supercomputer is great,'' remarked Chip.…

转载请注明出处:http://blog.csdn.net/u012860063 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1047 Problem Description One of the first users of BIT's new supercomputer was Chip Diller. He extended his exploration of powers of 3 to go from 0 to 333 and he e…

题目本身属于简单题,但是注意在输出的时候,题目很变态的对格式做了很多要求: 1.输入的N与下面的block有一个空行 2.每次输出与下一个输入的block有一个空行 3.但是特别注意,当是最后一个输出时不需要输出空行 见代码: #include <stdio.h> #include <string.h> void invert(char *a) { int l=strlen(a); ,j=l-;i<j;i++,j--) { char t; t=a[i]; a[i]=a[j];…

#include"stdio.h" #include"stdlib.h" #include"string.h" #define N 105 int a[N]; int main() { int i,j,n,n1,flag; char ch[N]; scanf("%d",&n); while(n--) { memset(a,,sizeof(a)); //数组初始化为零 ]!=') //输入零结束 { n1=strlen(…

作为最简单的高精度加法,要注意的是如下几点, 第一,因为是数位达到上百位的大数,所以只能用字符串数组来存贮. 第二,为了方便之后的相加操作,应该把字符串数组逆序转化为一个整型数组. 第三,在控制进位的时候,应该用一个工具变量,假设为h,则h初始值为0.之后在循环体里h是等于对应位的两个数相加之后/10,使得下一次循环时,高位可以进位. 第四,因为已经把原来读取的大数用字符数组读入后又逆序复制到一个新的整型数组里,所以此时下标小的保存的就是低位,这个时候再控制循环变量从低位一直加到高位,多余的位都…

题目链接:http://poj.org/problem?id=1503 import java.io.*; import java.math.BigInteger; import java.util.Scanner; public class Main { public static void main(String []args) throws IOException{ Scanner scanner=new Scanner(System.in); BigInteger a=BigIntege…

题目 我要开始练习一些java的简单编程了^v^ import java.io.*; import java.util.*; import java.math.*; public class Main { /** * @param args */ public static void main(String[] args) throws Exception { // 定义并打开输入文件 Scanner cin = new Scanner(System.in); BigInteger a, sum…

#include<iostream> #include<cstring> using namespace std; string sum; ; string tool(string a){ int dif = max_len - a.length(); string s = ""; ;i<dif;i++){ s += '; } s+=a; return s; } void solve(string a){ a = tool(a); sum = tool(s…

Description One of the first users of BIT's new supercomputer was Chip Diller. He extended his exploration of powers of 3 to go from 0 to 333 and he explored taking various sums of those numbers. This supercomputer is great,'' remarked Chip.I only wi…

Description One of the first users of BIT's new supercomputer was Chip Diller. He extended his exploration of powers of 3 to go from 0 to 333 and he explored taking various sums of those numbers. ``This supercomputer is great,'' remarked Chip. ``I on…

题目链接:http://poj.org/problem?id=1503 思路分析: 基本的高精度问题,使用字符数组存储然后处理即可. 代码如下: #include <iostream> #include <string> using namespace std; + ; char input[M]; int A[M], sum[M]; void Reverse(int A[], const char str[]) { int len = strlen(str); ; ; i >…

String 大数加法模板 #include<stdio.h> #include<string> #include<iostream> using namespace std; //高精度加法 //只能是两个正数相加 string add(string str1,string str2)//高精度加法 { string str; int len1=str1.length(); int len2=str2.length(); //前面补0,弄成长度相同 if(len1&l…

一.Description One of the first users of BIT's new supercomputer was Chip Diller. He extended his exploration of powers of 3 to go from 0 to 333 and he explored taking various sums of those numbers. ``This supercomputer is great,'' remarked Chip. ``I…

时间限制:1 秒 内存限制:32 兆 特殊判题:否 提交:679 解决:357 题目描述: One of the first users of BIT's new supercomputer was Chip Diller.     He extended his exploration of powers of 3 to go from 0 to 333 and he explored taking various sums of those numbers.      "This super…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1047 题目意思:就是求大整数加法.有多个案例,每个案例之间要输出一个空格. #include <iostream> #include <cstdio> #include <cstdlib> #include <cstring> using namespace std; + ; char t[maxn]; int s[maxn], ans[maxn]; int m…

题意:整数大数加法 思路:大数模板 #include<iostream> #include<stdio.h> #include<stdlib.h> #include<string.h> using namespace std; #define MAXN 9999//万进制 #define DLEN 4//4位 class BigNum{ private: ];//可以控制大数位数(500*4) int len;//大数长度 public: BigNum(){…