转载请注明出处:http://blog.csdn.net/a1dark 分析:找规律 #include<stdio.h> int main(){ int m,n; while(scanf("%d%d",&m,&n)!=EOF){ if(m==1)printf("%d\n",n+2); else if(m==2)printf("%d\n",2*n+3); else{ int s=5; for(int i=1;i<=…

- Eddy's research II Time Limit:2000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Description As is known, Ackermann function plays an important role in the sphere of theoretical computer science. However, in the other h…

题意:给定一个表达式,然后让你求表达式的值. 析:多写几个就会发现规律. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <cmath> #include <iostream> #include <cstring>…

题意:已知,求A(m, n). 分析:根据样例模拟一下过程就可以找出递推关系. #include<cstdio> #include<cstring> #include<cstdlib> #include<cctype> #include<cmath> #include<iostream> #include<sstream> #include<iterator> #include<algorithm>…

题目:http://acm.hdu.edu.cn/showproblem.php?pid=1165 果断不擅长找规律啊,做这种题静不下心来. Ackermann function can be defined recursively as follows: 递推如上图, 0<m<=3,0<=n<=1000000,,当m==3时,n>=0&&n<=24. 首先发现a(0,i)=i+1; 另外n==0时,a(1,0)=a(0,1)=2; 当m==1,n>…

Eddy's research II Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2706    Accepted Submission(s): 985 Problem Description As is known, Ackermann function plays an important role in the sphere o…

Eddy's research I Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7389    Accepted Submission(s): 4472 Problem Description Eddy's interest is very extensive, recently he is interested in prime n…

Eddy's research I Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5793    Accepted Submission(s): 3459 Problem Description Eddy's interest is very extensive, recently he is interested in prime n…

题目链接:https://www.luogu.com.cn/problem/P1028 题目描述 我们要求找出具有下列性质数的个数(包含输入的自然数 \(n\) ): 先输入一个自然数 \(n(n \le 1000)\) ,然后对此自然数按照如下方法进行处理: 不作任何处理; 在它的左边加上一个自然数,但该自然数不能超过原数的一半; 加上数后,继续按此规则进行处理,直到不能再加自然数为止. 输入格式 1个自然数 \(n(n \le 1000)\) 输出格式 1个整数,表示具有该性质数的个数. 问…

// Eddy 继续 Problem Description As is known, Ackermann function plays an important role in the sphere of theoretical computer science. However, in the other hand, the dramatic fast increasing pace of the function caused the value of Ackermann function…