Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the absolute difference between i and j is at most k. Example 1: Input: nums = [1,2,3,1], k = 3 Output:…

Given an array of integers, find out whether there are two distinct indices i and j in the array such that the absolute difference between nums[i] and nums[j] is at most t and the absolute difference between i and j is at most k. Example 1: Input: nu…

Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. 题目标签:Array, Hash Table 题目给了我们一个nums arr…

Given an array of integers, find out whether there are two distinct indices i and j in the array such that the difference between nums[i] and nums[j] is at most t and the difference between i and j is at most k. 这道题跟之前两道Contains Duplicate 包含重复值和Conta…

Given an array of integers and an integer k, return true if and only if there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference between i and j is at most k. (Old Version) Given an array of integers and an i…

题目标签: 题目给了我们一个 email 的表格,让我们删除重复的. 建立Person p1,Person p2,当email 相同时,而且 p1 id 要大于 p2 id 时候,删除这一行. Java Solution: Runtime:  869 ms, faster than 33 % Memory Usage: N/A 完成日期:06/01/2019 关键点:p1.Id > p2.Id # Write your MySQL query statement below DELETE p1…

每天一算:Contains Duplicate II 描述 给出1个整形数组nums和1个整数k,是否存在索引i和j,使得nums[i] == nums[j] 且i和j之间的差不超过k Example 1: Input: nums = [1,2,3,1], k = 3 Output: true. Example 2: Input: nums = [1,0,1,1], k = 1 Output: true Example 3: Input: nums = [1,2,3,1,2,3], k = 2…

核心思想是:序列化树 序列化后,用String可以唯一的代表一棵树,其实就是前序遍历改造一下(空节点用符号表示): 一边序列化,一边用哈希表记录有没有重复的,如果有就添加,注意不能重复添加. 重点就是序列化树,序列化得到的String可以唯一的代表一棵树,这个思想很多题都用到了 并不是只是前序遍历就能唯一表示一棵树,加上结构信息就可以了. Map<String,TreeNode> map = new HashMap<>(); List<TreeNode> res = n…

题意: 有一个含有n+1个元素的数组,元素值是在1-n之间的整数,请找出其中出现超过1次的数.(保证仅有1个出现次数是超过1的数) 思路: 方法一:O(nlogn).根据鸽笼原理及题意,每次如果<=k的数超过了k个,那么答案必定在[1,k].可以用二分枚举答案来解决. bool left(vector<int>& nums,int tar)//是否在左边 { ; ; i<nums.size(); i++) if(nums[i]<=tar) cnt++; return…

Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. Example 1: Input: [1,2,3,1] Output: tru…

Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. 这道题不算难题,就是使用一个哈希表,遍历整个数组,如果哈希表里存在,返回fal…

Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the absolute difference between i and j is at most k. 题目标签:Array, Hash Table 题目给了我们一个nums array 和一个 k, 让…

博客搬至blog.csgrandeur.com,cnblogs不再更新. 新的题解会更新在新博客:http://blog.csgrandeur.com/2014/01/15/LeetCode-OJ-Solution/ ———————————————————————————————————————— ———————————————————————————————————————— LeetCode OJ 题解 LeetCode OJ is a platform for preparing tech…

一直没有系统地学习过算法,不过算法确实是需要系统学习的.大二上学期,在导师的建议下开始学习数据结构,零零散散的一学期,有了链表.栈.队列.树.图等的概念.又看了下那几个经典的算法——贪心算法.分治算法.动态规划以及回溯算法.不过,都是知其一不知其二的一知半解.到最后,发现学到了一堆的一知半解,在学校课程开这门课时,却又是不得不再学一遍.学一样东西,又不全心全意地主动去把它学好,到最后只是花费了时间,却没真真学到东西.所以,不求学识有多广,但求所学的都精. 一个偶然的机会,让我在网上找到了一本社区…

Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another comput…

LeetCode:Combinations这篇博客中给出了不包含重复元素求组合的5种解法.我们在这些解法的基础上修改以支持包含重复元素的情况.对于这种情况,首先肯定要对数组排序,以下不再强调 修改算法1:按照求包含重复元素集合子集的方法LeetCode:Subsets II算法1的解释,我们知道:若当前处理的元素如果在前面出现过m次,那么只有当前组合中包含m个该元素时,才把当前元素加入组合 class Solution { public: void combine(vector<int> &a…

题目: Given a 2D binary matrix filled with 0's and 1's, find the largest square containing all 1's and return its area. For example, given the following matrix: 1 0 1 0 0 1 0 1 1 1 1 1 0 0 1 0 Return 4. 题目链接:https://leetcode.com/problems/maximal-square…

验证JS中是否包含重复元素,有重复返回true:否则返回false 方案一. function isRepeat(data) { var hash = {}; for (var i in data) { if (hash[data[i]]) { return true; } // 不存在该元素,则赋值为true,可以赋任意值,相应的修改if判断条件即可 hash[data[i]] = true; } return false; } 方案二. function isRepeat(arrs) { i…

xcode引入第三方静态类库 duplicate symbol _OBJC_XXX 重复编译错误 一:场景 xcode 同时引入了 libA.a, libB.a 两个静态类库,如果 这两个静态类库之中,都打包了,相同的库,方法之类的, 且 xcode 的 other link flag 为 -all_load 时,就会出现 上述 静态类库,重复编译错误: 二:解决方法 1:把xcode 的 other link flag 里面的 -all_load 去掉:有 force-load 的也去掉: 2…

Problem Link: http://oj.leetcode.com/problems/interleaving-string/ Given s1, s2, s3, find whether s3 is formed by the interleaving of s1 and s2. For example, Given: s1 = "aabcc", s2 = "dbbca", When s3 = "aadbbcbcac", return t…

Problem link: http://oj.leetcode.com/problems/reverse-words-in-a-string/ Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". LeetCode OJ supports Python now! The s…

题目要求 Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. 题目分析及思路 给出一个整数数组,判断这个数组是否包含重复值.若有任…

本内容是LeetCode第三道题目:无重复字符的最大子串 # -*- coding: utf-8 -*- """ Created on Sun Mar 10 20:14:53 2019 @author: Administrator Given a string, find the length of the longest substring without repeating characters. Example 1: Input: "abcabcbb"…

常泡LC的朋友知道LC是不提供代码打包下载的,不像一般的OJ,可是我不备份代码就感觉不舒服- 其实我想说的是- 我自己写了抓取个人提交代码的小工具,放在GitCafe上了- 不知道大家有没有兴趣 https://gitcafe.com/aaronzhou/ ... ssion 拿Java写的,也打了一个包,本地有JRE环境就能运行,欢迎拍砖 抓取 LeetCode OJ 个人提交的代码 Gradle 构建项目 HttpClient.jsoup 抓取.解析网页 使用说明 进入release文件夹…

题目:Given an array of size n, find the majority element. The majority element is the element that appears more than ⌊ n/2 ⌋ times. You may assume that the array is non-empty and the majority element always exist in the array. int majorityElement(vecto…

Given an integer, convert it to a roman numeral. Input is guaranteed to be within the range from 1 to 3999. 给定一个整数,将他转换到罗马字符.同样这里的罗马字符不会超过1000(M),PS:关于罗马字符的介绍看我的这篇文章 :LeetCode OJ:Roman to Integer(转换罗马字符到整数) 这里的大体思路是这样的,例如对于罗马字符952来说,起答题的可以分成三个组成部分, 就…

Serialization is the process of converting a data structure or object into a sequence of bits so that it can be stored in a file or memory buffer, or transmitted across a network connection link to be reconstructed later in the same or another comput…

LeetCode:删除排序数组中的重复项||[80] 题目描述 给定一个排序数组,你需要在原地删除重复出现的元素,使得每个元素最多出现两次,返回移除后数组的新长度. 不要使用额外的数组空间,你必须在原地修改输入数组并在使用 O(1) 额外空间的条件下完成. 示例 1: 给定 nums = [1,1,1,2,2,3], 函数应返回新长度 length = 5, 并且原数组的前五个元素被修改为 1, 1, 2, 2, 3 . 你不需要考虑数组中超出新长度后面的元素. 示例 2: 给定 nums =…

LeetCode 第 3 题:无重复字符的最长子串 (滑动窗口) 方法:滑动窗口 滑动窗口模板问题:右指针先走,满足了一定条件以后,左指针向前走,直到不满足条件. 特点:左右指针的方向是一致的,并且是不回头的. C++ 代码: #include <iostream> #include <string> using namespace std; class Solution { public: int lengthOfLongestSubstring(string s) { int…

Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct. 判断数组里面是否有重复的,很简单: class Solution { publ…