Tennis Championship】的更多相关文章

C. Tennis Championship 题目链接 http://codeforces.com/contest/735/problem/C 题面 Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There will be n players participating, and the tournament will fo…
C. Tennis Championship time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There w…
Tennis Championship time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There will…
Tennis Championship 题目链接:http://codeforces.com/problemset/problem/735/C ——每天在线,欢迎留言谈论. 题目大意: 给你一个 n (2≤n≤10^18),代表一共有n位参加比赛的选手. 游戏规则: ①每次比赛,输的选手将离开赛场 ②相互比赛的选手 他们的获胜的次数相差不能超过1(获胜4次的选手只能跟3或5次的选手比赛) 问题:最终赢得比赛的选手,胜场最多能为多少. 思路: 贪心:①选一名选手让他一直获胜且优先让他参加比赛 ②当…
C. Tennis Championship time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There w…
C. Tennis Championship time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There w…
http://codeforces.com/contest/735/problem/C C. Tennis Championship time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Ben…
time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard output Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There will be n players participat…
http://codeforces.com/problemset/problem/735/C 题意:有n个人打锦标赛,淘汰赛制度,即一个人和另一个人打,输的一方出局.问这n个人里面冠军最多能赢多少场,其中一个人和另一个人能打比赛当且仅当这两个人赢的局数相差不超过1. 思路:比赛的时候不会做..直接log2(n)交,果断错了.看题解:因为限制条件两个人能比赛当且仅当他们赢得局数相差不超过1,设F[x]为冠军赢x盘的时候需要的总人数,那么有这样的递推式:F[x] = F[x-1] + F[x-2].…
题目链接 http://codeforces.com/contest/735/problem/C 题意:给你一个数n表示有几个人比赛问最多能赢几局,要求两个比赛的人得分不能相差超过1即得分为2的只能和得分为3,1的比赢一局 得一分. 由题意可得得分为i的人最少由最少的得分为i-1与i-2的人比赛得到所以我们设dp[i]表示得分为i的最少比赛人是多少 所以dp[i]=dp[i-1]+dp[i-2]只要(dp[i - 1]<=n<dp[i])那么结果就是i-1. #include <iost…