POJ 3207 Ikki's Story IV - Panda's Trick liympanda, one of Ikki's friend, likes playing games with Ikki. Today after minesweeping with Ikki and winning so many times, he is tired of such easy games and wants to play another game with Ikki. liympanda…

传送门 题意: 给出一个圆,圆上有\(n\)个点,依次为\(0,1,\cdots,n-1\). 现在要连接\(m\)对点,每次连接时可以直接从里面连,也可以从外面连. 最后问,连完这\(m\)对点后,是否有线相交. 思路: 每次连接时可以直接从里面连,也可以从外面连,那么可以考虑这个问题是一个\(2-sat\)模型.\(2-sat\)模型一般可以表示为:\((x_1\bigvee x_2)\bigwedge (x_3\bigvee x_4)\bigwedge \cdots\).大概就是这样,每个…

http://poj.org/problem?id=3207 Ikki's Story IV - Panda's Trick Time Limit: 1000MS   Memory Limit: 131072K Total Submissions: 7021   Accepted: 2604 Description liympanda, one of Ikki’s friend, likes playing games with Ikki. Today after minesweeping wi…

POJ 3207 Ikki's Story IV - Panda's Trick(2-sat问题) Description liympanda, one of Ikki's friend, likes playing games with Ikki. Today after minesweeping with Ikki and winning so many times, he is tired of such easy games and wants to play another game…

Ikki's Story IV - Panda's Trick Time Limit: 1000MS   Memory Limit: 131072K Total Submissions: 7296   Accepted: 2705 Description liympanda, one of Ikki’s friend, likes playing games with Ikki. Today after minesweeping with Ikki and winning so many tim…

Ikki's Story IV - Panda's Trick Time Limit: 1000MS   Memory Limit: 131072K Total Submissions: 6691   Accepted: 2496 Description liympanda, one of Ikki’s friend, likes playing games with Ikki. Today after minesweeping with Ikki and winning so many tim…

题目 liympanda, one of Ikki's friend, likes playing games with Ikki. Today after minesweeping with Ikki and winning so many times, he is tired of such easy games and wants to play another game with Ikki. liympanda has a magic circle and he puts it on a…

http://poj.org/problem?id=3207 题意:一个圆上顺时针依次排列着标号为1-n的点,这些点之间共有m条边相连,每两个点只能在圆内或者圆外连边.问是否存在这些边不相交的方案.(n<=1000, m<=500) #include <cstdio> #include <cstring> #include <algorithm> #include <cmath> #include <iostream> using n…

注意到相交的点对一定要一里一外,这样就变成了2-SAT模型 然后我建边的时候石乐志,实际上不需要考虑这个点对的边是正着连还是反着连,因为不管怎么连,能相交的总会相交,所以直接判相交即可 然后tarjan缩点,再判是否合法即可 #include<iostream> #include<cstdio> using namespace std; const int N=100005; int n,m,h[N],cnt,l[N],r[N],dfn[N],low[N],tot,s[N],top…

Time Limit: 1000MS   Memory Limit: 131072K Total Submissions: 9426   Accepted: 3465 Description liympanda, one of Ikki’s friend, likes playing games with Ikki. Today after minesweeping with Ikki and winning so many times, he is tired of such easy gam…