传送门:http://acm.hdu.edu.cn/showproblem.php?pid=1250 Hat's Fibonacci Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 12952    Accepted Submission(s): 4331 Problem Description A Fibonacci sequence…
题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=1250 Hat's Fibonacci Description A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1.$F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n >…
题目 java做大数的题,真的是神器,来一道,秒一道~~~ import java.io.*; import java.util.*; import java.math.*; public class Main { /** * @xqq */ public BigInteger an(int n) { BigInteger e; BigInteger a = BigInteger.valueOf(1); BigInteger b = BigInteger.valueOf(1); BigInteg…
Hat's Fibonacci Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 14776    Accepted Submission(s): 4923   Problem Description A Fibonacci sequence is calculated by adding the previous two members…
Problem Description A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1. F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4) Your task is to take…
//  继续大数,哎.. Problem Description A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1. F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4) Your tas…
Problem Description A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1. F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4) Your task is to take…
pid=1250">点击此处就可以传送hdu 1250 Problem Description A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1. F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n…
将斐波那契的前100000个,每个的前40位都插入到字典树里(其他位数删掉),然后直接查询字典树就行. 此题坑点在于 1.字典树的深度不能太大,事实上,超过40在hdu就会MLE…… 2.若大数加法时,保存的位数过少,就会导致低位误差,累积起来就可能导致前40位产生错误,解决办法是提高精度. #include<iostream> #include<cstring> #include<string> #include<cstdio> using namespa…
题目 //BigInteger 和 BigDecimal 是在java.math包中已有的类,前者表示整数,后者表示浮点数 import java.io.*; import java.util.*; import java.math.*; public class Main { /** * @xqq */ public BigInteger an(BigInteger a, BigInteger b, int n) { if(n == 1) { return a; } for(int i = 2…