1084 Broken Keyboard (20 分)   On a broken keyboard, some of the keys are worn out. So when you type some sentences, the characters corresponding to those keys will not appear on screen. Now given a string that you are supposed to type, and the string…

1084 Broken Keyboard (20 分) On a broken keyboard, some of the keys are worn out. So when you type some sentences, the characters corresponding to those keys will not appear on screen. Now given a string that you are supposed to type, and the string t…

1084 Broken Keyboard(20 分) On a broken keyboard, some of the keys are worn out. So when you type some sentences, the characters corresponding to those keys will not appear on screen. Now given a string that you are supposed to type, and the string th…

题目信息 1084. Broken Keyboard (20) 时间限制200 ms 内存限制65536 kB 代码长度限制16000 B On a broken keyboard, some of the keys are worn out. So when you type some sentences, the characters corresponding to those keys will not appear on screen. Now given a string that…

1084 Broken Keyboard (20 分) On a broken keyboard, some of the keys are worn out. So when you type some sentences, the characters corresponding to those keys will not appear on screen. Now given a string that you are supposed to type, and the string t…

题目 On a broken keyboard, some of the keys are worn out. So when you type some sentences, the characters corresponding to those keys will not appear on screen.Now given a string that you are supposed to type, and the string that you actually type out,…

On a broken keyboard, some of the keys are worn out. So when you type some sentences, the characters corresponding to those keys will not appear on screen. Now given a string that you are supposed to type, and the string that you actually type out, p…

简单题. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<queue> #include<stack> #include<algorithm> using namespace std; ; char s[maxn],t[maxn],u[maxn]; ]; int main() {…

题意: 输入两行字符串,输出第一行有而第二行没有的字符(对大小写不敏感且全部以大写输出). AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; string s1,s2; ]; vector<char>ans; int main(){ ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL)…

#include <iostream> #include <cstdio> #include <string.h> #include <algorithm> using namespace std; ; char str1[maxn]; char str2[maxn]; ]; int main() { scanf("%s %s",str1,str2); memset(vis,,sizeof(vis)); int len1=strlen(s…