136 Single Number(找唯一数Medium)

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136 Single Number(找唯一数Medium)

题目意思:一个int数组,有一个数只出现一次,其他数均出现两次,找到这个唯一数知识普及:~:非运算,单目运算符1为0,0为1; &:与运算,都为1则为1,否则为0 |:或运算,全为0则为0,否则为1 ^:异或运算,相同为0,不同为1 思路:将数组中元素进行异或运算,则只剩下0和唯一数,异或得到的是唯一数 class Solution { public: int singleNumber(vector<int>& nums) { ; ;i<nums.si…

137 Single Number II(找唯一数Medium)

题目意思:一个int数组,有一个数只出现一次,其他数均出现三次,找到这个唯一数思路: 1.将所有数用2进制表示,计算每一位的数字和 1*3*n1+0*3*n2+c 唯一数对应位的数字(0或者1) 要求具有牢固的位运算基础 eg 10001010 10001010 10001010 10101001 10101001 10101001 11001010 7,1,3,0,7,0,4,3 则唯一数为1,1,0,0,1,0,1,0 class So…

[LeetCode] 136. Single Number 单独数

Given a non-empty array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? Example 1: Input: [2,2,1] Output:…

leetcode 136. Single Number 、 137. Single Number II 、 260. Single Number III(剑指offer40 数组中只出现一次的数字)

136. Single Number 除了一个数字,其他数字都出现了两遍. 用亦或解决,亦或的特点:1.相同的数结果为0,不同的数结果为1 2.与自己亦或为0,与0亦或为原来的数 class Solution { public: int singleNumber(vector<int>& nums) { if(nums.empty()) ; ; ;i < nums.size();i++) res ^= nums[i]; return res; } }; 137. Single N…

[LeetCode] 260. Single Number III 单独数 III

Given an array of numbers nums, in which exactly two elements appear only once and all the other elements appear exactly twice. Find the two elements that appear only once. Example: Input: [1,2,1,3,2,5] Output: [3,5] Note: The order of the result is…

LeetCode 136. Single Number C++ 结题报告

136. Single Number -- Easy 解答相同的数,XOR 等于 0,所以,将所有的数字 XOR 就可以得到只出现一次的数 class Solution { public: int singleNumber(vector<int>& nums) { int s = 0; for(int i = 0; i < nums.size(); i++) { s = s ^ nums[i]; } return s; } }; 参考 LeetCode Problems' So…

leetcode 136 Single Number, 260 Single Number III

leetcode 136. Single Number Given an array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 解题思路: 如果以线性复杂度和…