HDU 6140 Hybrid Crystals】的更多相关文章

Hybrid Crystals Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 322    Accepted Submission(s): 191 Problem Description > Kyber crystals, also called the living crystal or simply the kyber, and k…
题目链接 Problem Description Kyber crystals, also called the living crystal or simply the kyber, and known as kaiburr crystals in ancient times, were rare, Force-attuned crystals that grew in nature and were found on scattered planets across the galaxy.…
题目传送: Hybrid Crystals Problem Description > Kyber crystals, also called the living crystal or simply the kyber, and known as kaiburr crystals in ancient times, were rare, Force-attuned crystals that grew in nature and were found on scattered planets…
[Link]:http://acm.hdu.edu.cn/showproblem.php?pid=6140 [Description] 等价于告诉你有n个物品,每个物品的价值为-a[i]或a[i],或者这个物品可以看成两个物品一个为a[i]另外一个为-a[i]; 问你能不能达到物品价值k [Solution] 爆搜. 加个看起来不是很有用的剪枝就能过. (记录某个位置后面所有的整数的和) 大数据的背包好像都能这样做. (这题数据比较水??) [另解]: 题目描述的上面有说a1=1,b1='N'…
题解:这道题中的数能组成的数构成了一个连续区间. 一开始只有 a1​​ 的时候能够构成 [-1, 1][−1,1] 中的所有整数. 如果一堆数能够构成 [-a, b][−a,b] 中的所有整数, 这时候来了一个数 x. 如果 x 只能取正值的话, 如果有 x<b 那么就能够构成 [-a, b+x][−a,b+x] 的所有整数. 如果 x 只能取负值, 如果有 x<|a| 那么就能构成 [-a-x, b][−a−x,b] 的所有整数. 如果 x 可正可负, 如果有 x<min(|a|,b)…
Hybrid Crystals Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 300    Accepted Submission(s): 179 Problem Description > Kyber crystals, also called the living crystal or simply the kyber, and k…
HDU6140 Hybrid Crystals 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=6140 题目意思:这场多校是真的坑,题目爆长,心态爆炸,题目意思就是给定一个序列.序列的每个值都有属性,N代表可加可减,L代表只能加,D代表只能减,当然这些都可以用或者不用.给定一个k,问k是否可能用这个序列构成. 思路: 源头都来自这个奇怪的式子 解释一下这个式子什么意思: 如果b[i]是N那么所有b[j](j<i)属性是N的和大于b[i]. 如果b[…
度度熊的交易计划 Time Limit: 12000/6000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1111    Accepted Submission(s): 403 Problem Description 度度熊参与了喵哈哈村的商业大会,但是这次商业大会遇到了一个难题: 喵哈哈村以及周围的村庄可以看做是一共由n个片区,m条公路组成的地区. 由于生产能力的区别,第i…
小小粉丝度度熊 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1572    Accepted Submission(s): 513 Problem Description 度度熊喜欢着喵哈哈村的大明星——星星小姐. 为什么度度熊会喜欢星星小姐呢? 首先星星小姐笑起来非常动人,其次星星小姐唱歌也非常好听. 但这都不是最重要的,最重要的是…
Chess Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 513    Accepted Submission(s): 319 Problem Description 車是中国象棋中的一种棋子,它能攻击同一行或同一列中没有其他棋子阻隔的棋子.一天,小度在棋盘上摆起了许多車……他想知道,在一共N×M个点的矩形棋盘中摆最多个数的車使其互不攻…