class Solution { public: int strStr(string haystack, string needle) { ; //needle empty ; //haystack empty , j = ; i+j < haystack.size();) { ; //no equal needle index to 0, haystack index move to next. else j++; //equal both move to next if(j == needl…

Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. Update (2014-11-02): The signature of the function had been updated to return the index instead of the pointer. If you still…

Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. 1 class Solution(object): def strStr(self, haystack, needle): """ :type haystack: str :type needle: str :rtype: in…

Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. 注:直接看题目可能会有些偏差,因为容易认为 needle是一个字符,那就也太容易了,实则,haystack和needle都是字符串(注意是字符串不是数组) 解法思路: 暴力搜索: public class Solution { public int…

1 题目: Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. Update (2014-11-02):The signature of the function had been updated to return the index instead of the pointer. If you…

Brute Force算法,时间复杂度 O(mn) def strStr(haystack, needle): m = len(haystack) n = len(needle) if n == 0: return 0 if m < n: return -1 for i in range(m - n - 1): for j in range(n): if haystack[i + j] != needle[j]: break elif j == n - 1: return i return -1…

Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. 思路: 注意,在for循环中条件有计算得到的负数时, 一定要把计算括起来转换为int, 否则会默认转换为uchar 负数就会被误认为是一个很大的数字. ; i < - ); ++i) 实现很常规: int strStr(string haystac…

Implement strStr(). Returns a pointer to the first occurrence of needle in haystack, or null if needle is not part of haystack. I wrote that function before in practice without knowing anything about strStr(), so I have a pretty clear brute-force sol…

Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if needle is not part of haystack. Update (2014-11-02): The signature of the function had been updated to return the index instead of the pointer. If you still…

Implement strStr(). Returns a pointer to the first occurrence of needle in haystack, or null if needle is not part of haystack. Summary: be careful about the corner case, haystack = "", needle = "" char *strStr(char *haystack, char *ne…