【leetcode 190】的更多相关文章

[LeetCode] 190. Reverse Bits 颠倒二进制位

Reverse bits of a given 32 bits unsigned integer. Example 1: Input: 00000010100101000001111010011100 Output: 00111001011110000010100101000000 Explanation: The input binary string 00000010100101000001111010011100 represents the unsigned integer 432615…

leetcode 190

190. Reverse Bits Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000). Follow up…

LeetCode 190. Reverse Bits （反转位）

Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000). 题目标签: Bit Manipulation 这道题目…

LeetCode 190. Reverse Bits (算32次即可)

题目: 190. Reverse Bits Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000). Follo…

[LeetCode] 190. Reverse Bits 翻转二进制位

Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000). Follow up:If this function…

Java实现 LeetCode 190 颠倒二进制位

190. 颠倒二进制位 颠倒给定的 32 位无符号整数的二进制位. 示例 1: 输入: 00000010100101000001111010011100 输出: 00111001011110000010100101000000 解释: 输入的二进制串 00000010100101000001111010011100 表示无符号整数 43261596, 因此返回 964176192,其二进制表示形式为 00111001011110000010100101000000. 示例 2: 输入:11111…

Leetcode 190 Reverse Bits 位运算

反转二进制 class Solution { public: uint32_t reverseBits(uint32_t n) { uint32_t ans = ; ; i<; ++i,n >>=){ ans = (ans<< )|(n & ); } return ans; } };…

Java for LeetCode 190 Reverse Bits

Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000). JAVA实现如下: public int revers…

Java [Leetcode 190]Reverse Bits

题目描述: everse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000). 解题思路: 移位操作. 代码如下: publi…

Leetcode 190. Reverse Bits（反转比特数）

Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000). Follow up: If this function…

Leetcode 190.颠倒二进制位 By Python

颠倒给定的 32 位无符号整数的二进制位. 示例: 输入: 43261596 输出: 964176192 解释: 43261596 的二进制表示形式为 00000010100101000001111010011100 , 返回 964176192,其二进制表示形式为 00111001011110000010100101000000 . 思路 用python内置的bin()函数转为为二进制数,并用zfill()方法补足到32位,最后将字符串反转,转换为整型即可 代码 class Solution:…

[LeetCode] 190. Reverse Bits_Easy tag: Bit Manipulation

Reverse bits of a given 32 bits unsigned integer. Example: Input: 43261596 Output: 964176192 Explanation: 43261596 represented in binary as 00000010100101000001111010011100,   return 964176192 represented in binary as 00111001011110000010100101000000…

leetcode 190. 颠倒二进制位(c++)

颠倒给定的 32 位无符号整数的二进制位. 示例 1: 输入: 00000010100101000001111010011100输出: 00111001011110000010100101000000解释: 输入的二进制串 00000010100101000001111010011100 表示无符号整数 43261596, 因此返回 964176192,其二进制表示形式为 00111001011110000010100101000000.示例 2: 输入:11111111111111111111…

[LeetCode] All questions numbers conclusion 所有题目题号

Note: 后面数字n表明刷的第n + 1遍, 如果题目有**, 表明有待总结 Conclusion questions: [LeetCode] questions conclustion_BFS, DFS LeetCode questions conclustion_Path in Tree [LeetCode] questions conlusion_InOrder, PreOrder, PostOrder traversal [LeetCode] questions for Dynamic…

leetcode算法总结

算法思想 二分查找 贪心思想 双指针 排序 快速选择 堆排序 桶排序 搜索 BFS DFS Backtracking 分治 动态规划 分割整数 矩阵路径 斐波那契数列 最长递增子序列 最长公共子系列 0-1 背包 数组区间 字符串编辑 其它问题 数学 素数 最大公约数 进制转换 阶乘 字符串加法减法 相遇问题 多数投票问题 其它 数据结构相关 栈和队列 哈希表 字符串 数组与矩阵 1-n 分布 有序矩阵 链表 树 递归 层次遍历 前中后序遍历 BST Trie 图 位运算 参考资料 算法思想 二…

[LeetCode] 191. Number of 1 Bits 二进制数1的个数

Write a function that takes an unsigned integer and returns the number of ’1' bits it has (also known as the Hamming weight). For example, the 32-bit integer ’11' has binary representation 00000000000000000000000000001011, so the function should retu…

【LeetCode】190 & 191 - Reverse Bits & Number of 1 Bits

190 - Reverse Bits Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000). Follow up…

【一天一道Leetcode】#190.Reverse Bits

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 我的个人博客已创建,欢迎大家持续关注! 一天一道leetcode系列依旧在csdn上继续更新,除此系列以外的文章均迁移至我的个人博客 另外,本系列文章已整理并上传至gitbook,网址:点我进 欢迎转载,转载请注明出处! (一)题目 Reverse bits of a given 32 bits unsigned integer. For examp…

【LeetCode】190. Reverse Bits 解题报告（Python & C++）

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 解题方法 二进制字符串翻转 位运算 日期 题目地址:https://leetcode.com/problems/reverse-bits/description/ 题目描述 Reverse bits of a given 32 bits unsigned integer. Example: Input: 43261596 Output: 964176192 Explan…

【leetcode❤python】 190. Reverse Bits

#-*- coding: UTF-8 -*- class Solution:    # @param n, an integer    # @return an integer    def reverseBits(self, n):        tmp=str(bin(n))[2:][::-1]                for i in xrange(32-len(tmp)):            tmp+='0'               return int(tmp,base=…

LeetCode 【190. Reverse Bits】

Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000). Follow up:If this function…

【LeetCode】190. Reverse Bits

题目: Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000). Follow up:If this funct…

LeetCode（190） Reverse Bits

题目 Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000). Follow up: If this funct…

【刷题-LeetCode】190 Reverse Bits

Reverse Bits Reverse bits of a given 32 bits unsigned integer. Example 1: Input: 00000010100101000001111010011100 Output: 00111001011110000010100101000000 Explanation: The input binary string 00000010100101000001111010011100 represents the unsigned i…

LeetCode All in One 题目讲解汇总(持续更新中...)

终于将LeetCode的免费题刷完了,真是漫长的第一遍啊,估计很多题都忘的差不多了,这次开个题目汇总贴,并附上每道题目的解题连接,方便之后查阅吧~ 477 Total Hamming Distance 44.10% Meidum 475 Heaters  30.20% Easy 474 Ones and Zeroes  34.90% Meidum 473 Matchsticks to Square  31.80% Medium 472 Concatenated Words 29.20% Hard…

[LeetCode] Reverse Bits 翻转位

Reverse bits of a given 32 bits unsigned integer. For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as00111001011110000010100101000000). Follow up:If this function i…

leetcode bugfree note

463. Island Perimeterhttps://leetcode.com/problems/island-perimeter/就是逐一遍历所有的cell,用分离的cell总的的边数减去重叠的边的数目即可.在查找重叠的边的数目的时候有一点小技巧,就是沿着其中两个方向就好,这种题目都有类似的规律,就是可以沿着上三角或者下三角形的方向来做.一刷一次ac,但是还没开始注意codestyle的问题,需要再刷一遍. class Solution { public: int islandPerime…

【算法之美】你可能想不到的归并排序的神奇应用 — leetcode 327. Count of Range Sum

又是一道有意思的题目,Count of Range Sum.(PS:leetcode 我已经做了 190 道,欢迎围观全部题解 https://github.com/hanzichi/leetcode) 题意非常简单,给一个数组,如果该数组的一个子数组,元素之和大于等于给定的一个参数值(lower),小于等于一个给定的参数值(upper),那么这为一组解,求总共有几组解. 一个非常容易想到的解法是两层 for 循环遍历子数组首尾,加起来判断,时间复杂度 O(n^2). /** * @param…

【算法之美】求解两个有序数组的中位数 — leetcode 4. Median of Two Sorted Arrays

一道非常经典的题目,Median of Two Sorted Arrays.(PS:leetcode 我已经做了 190 道,欢迎围观全部题解 https://github.com/hanzichi/leetcode) 题意非常简单,给定两个有序的数组,求中位数,难度系数给的是 Hard,希望的复杂度是 log 级别.回顾下中位数,对于一个有序数组,如果数组长度是奇数,那么中位数就是中间那个值,如果长度是偶数,就是中间两个数的平均数. O(nlogn) 最容易想到的解法是 O(nlogn) 的解…

leetcode学习笔记--开篇

1 LeetCode是什么? LeetCode是一个在线的编程测试平台,国内也有类似的Online Judge平台.程序开发人员可以通过在线刷题,提高对于算法和数据结构的理解能力,夯实自己的编程基础.对于找工作的小伙伴十分有好处. 这是leetcode官网的简介: LeetCode OJ is a platform for preparing technical coding interviews. Pick from an expanding library of more than 190 …