hdoj 4883 TIANKENG’s restaurant【贪心区间覆盖】

【hdoj 4883 TIANKENG’s restaurant【贪心区间覆盖】】的更多相关文章

hdoj 4883 TIANKENG’s restaurant【贪心区间覆盖】

TIANKENG’s restaurant Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/65536 K (Java/Others)Total Submission(s): 1360 Accepted Submission(s): 545 Problem Description TIANKENG manages a restaurant after graduating from ZCMU, and tens…

HDOJ 4883 TIANKENG’s restaurant

称号: TIANKENG's restaurant Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/65536 K (Java/Others) Total Submission(s): 249 Accepted Submission(s): 125 Problem Description TIANKENG manages a restaurant after graduating from ZCMU, and t…

hdoj 1050 Moving Tables【贪心区间覆盖】

Moving Tables Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 24316 Accepted Submission(s): 8053 Problem Description The famous ACM (Advanced Computer Maker) Company has rented a floor of a b…

高效算法——E - 贪心-- 区间覆盖

E - 贪心-- 区间覆盖题目链接:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=85904#problem/E 解题思路: 贪心思想,将问题转化为区间覆盖问题,将草地的上边界作为要覆盖的区间,计算出每个洒水器覆盖的区间范围,不能覆盖的舍去,然后将洒水器按覆盖范围的左边界升序排列. 要覆盖的最右边的点right的初始值为0,遍历洒水器,找一个能覆盖住right且覆盖范围的右边界最大的洒水器,然后将该洒水器覆盖的右边界作为新的righ…

【题解】Cut the Sequence(贪心区间覆盖)

[题解]Cut the Sequence(贪心区间覆盖) POJ - 3017 题意: 给定一大堆线段,问用这些线段覆盖一个连续区间1-x的最小使用线段的数量. 题解考虑一个这样的贪心: 先按照左端点排序,若左端点一样则谁长谁在前.现在判无解就方便了,记录一下前缀max即可.然后现在要最小化选择. 记录一个最右端点\(R\),一个暴力的办法是暴力循环判断所有线段是否满足条件,这样显然超时,你决定优化一下常数,所以你记录一下从哪个线段开始才\(l_i \ge R\).你以为你是常数优化,其实你复…

UVA 10382 - Watering Grass【贪心+区间覆盖问题+高精度】

UVa 10382 - Watering Grass n sprinklers are installed in a horizontal strip of grass l meters long and w meters wide. Each sprinkler is installed at the horizontal center line of the strip. For each sprinkler we are given its position as the distance…

南阳OJ-12-喷水装置（二）贪心+区间覆盖

题目链接: http://acm.nyist.edu.cn/JudgeOnline/problem.php?pid=12 题目大意: 有一块草坪,横向长w,纵向长为h,在它的橫向中心线上不同位置处装有n(n<=10000)个点状的喷水装置,每个喷水装置i喷水的效果是让以它为中心半径为Ri的圆都被润湿.请在给出的喷水装置中选择尽量少的喷水装置,把整个草坪全部润湿. 传送门:喷水装置(一) 思路: 区间覆盖问题,每个点有一段喷水区间,按照左端点排序即可,设置两变量begin, end,依次扫过去,每…