POJ-1080 Human Gene Functions---类似LCS

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poj 1080 Human Gene Functions（lcs，较难）

Human Gene Functions Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 19573 Accepted: 10919 Description It is well known that a human gene can be considered as a sequence, consisting of four nucleotides, which are simply denoted by four…

poj 1080 ——Human Gene Functions——————【最长公共子序列变型题】

Human Gene Functions Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 17805 Accepted: 9917 Description It is well known that a human gene can be considered as a sequence, consisting of four nucleotides, which are simply denoted by four…

POJ 1080 Human Gene Functions -- 动态规划(最长公共子序列)

题目地址:http://poj.org/problem?id=1080 Description It is well known that a human gene can be considered as a sequence, consisting of four nucleotides, which are simply denoted by four letters, A, C, G, and T. Biologists have been interested in identifyi…

poj 1080 Human Gene Functions(dp)

题目:http://poj.org/problem?id=1080 题意:比较两个基因序列,测定它们的相似度,将两个基因排成直线,如果需要的话插入空格,使基因的长度相等,然后根据那个表格计算出相似度. 题解: 考虑f[i][j]: ① s1取第i个,s2取第j个, f[i][j] = f[i-1][j-1]+value[m(s1[i])][m(s2[j])]; ② s1取第i个,s2用’-’, f[i][j] = f[i][j-1]+value[m(s1[i])][m(‘-’)];…

dp poj 1080 Human Gene Functions

题目链接: http://poj.org/problem?id=1080 题目大意: 给两个由A.C.T.G四个字符组成的字符串,可以在两串中加入-,使得两串长度相等. 每两个字符匹配时都有个值,求怎样安排使得总的值最大,两个-不能匹配. 解题思路: 这题转化一下就是一个裸的最长公共子串问题,只不过要求匹配时长度一样. dp[i][j]表示第一串的第前i个字符和第二串的前j个字符匹配时,能达到的最大值. 初始化时注意dp[0][j]和dp[j][0]不能为零,为相应字符与-匹配时的总和. 代码:…