problem 687. Longest Univalue Path 参考 1. Leetcode_easy_687. Longest Univalue Path; 2. Grandyang; 完…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 DFS 日期 题目地址:https://leetcode.com/problems/longest-univalue-path/description/ 题目描述 Given a binary tree, find the length of the longest path where each node in the path has the s…

Given a binary tree, find the length of the longest path where each node in the path has the same value. This path may or may not pass through the root. Note: The length of path between two nodes is represented by the number of edges between them. Ex…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址: https://leetcode.com/problems/longest-increasing-path-in-a-matrix/description/ 题目描述: Given an integer matrix, find the length of the longest increasing path. From each cell, you can either…

Given a binary tree, find the length of the longest path where each node in the path has the same value. This path may or may not pass through the root. Note: The length of path between two nodes is represented by the number of edges between them. Ex…

题目: Given a binary tree, find the length of the longest path where each node in the path has the same value. This path may or may not pass through the root. The length of path between two nodes is represented by the number of edges between them. Exam…

problem 720. Longest Word in Dictionary 题意: solution1: BFS; class Solution { public: string longestWord(vector<string>& words) { string res = ""; unordered_set<string> s(words.begin(), words.end()); queue<string> q; for(aut…

problem 674. Longest Continuous Increasing Subsequence solution class Solution { public: int findLengthOfLCIS(vector<int>& nums) { , cnt = , cur = INT_MAX; for(auto num:nums) { if(num>cur) cnt++; ; res = max(res, cnt); cur = num; } return res…

problem 594. Longest Harmonious Subsequence 最长和谐子序列 题意: 可以对数组进行排序,那么实际上只要找出来相差为1的两个数的总共出现个数就是一个和谐子序列的长度了. solution1: 使用hashmap 用 HashMap 来做,先遍历一遍,建立每个数字跟其出现次数之间的映射,然后再遍历每个数字的时候,只需在 HashMap 中查找该数字加1是否存在,存在就更新结果 res. class Solution { public: int findLH…

寻找最长的路径,那么会在左边或者右边或者是从左到跟然后再到右方的路径的. /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: int longestUniva…

/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ static int wing=[]() { std::ios::sync_with_stdio(false); cin.tie(NULL); ; }();…

[SP1812]LCS2 - Longest Common Substring II 题面 洛谷 题解 你首先得会做这题. 然后就其实就很简单了, 你在每一个状态\(i\)打一个标记\(f[i]\)表示状态\(i\)能匹配到最长的子串长度, 显然\(f[i]\)可以上传给\(f[i.fa]\). 然后去每个串和第\(1\)个串\(f\)的最小值的最大值即可. 代码 #include <iostream> #include <cstdio> #include <cstdlib&…

[SP1811]LCS - Longest Common Substring 题面 洛谷 题解 建好后缀自动机后从初始状态沿着现在的边匹配, 如果失配则跳它的后缀链接,因为你跳后缀链接到达的\(Endpos\)集合中的串肯定是当前\(Endpos\)中的后缀,所以这么做是对的. 你感性理解一下,这样显然是最大的是吧... 具体实现看代码: 代码 #include <iostream> #include <cstdio> #include <cstdlib> #inclu…

[LeetCode]522. Longest Uncommon Subsequence II 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/longest-uncommon-subsequence-ii/description/ 题目描述: Given a list of strings, you…

题目如下: Suppose we abstract our file system by a string in the following manner: The string "dir\n\tsubdir1\n\tsubdir2\n\t\tfile.ext"represents: dir subdir1 subdir2 file.ext The directory dir contains an empty sub-directory subdir1 and a sub-direc…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述: 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/longest-absolute-file-path/description/ 题目描述: Suppose we abstract our file system by a string in the following manner: The string "dir\n\…

［抄题］: Given a binary tree, find the length of the longest path where each node in the path has the same value. This path may or may not pass through the root. Note: The length of path between two nodes is represented by the number of edges between th…

这是悦乐书的第290次更新,第308篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第158题(顺位题号是687).给定二叉树,找到路径中每个节点具有相同值的最长路径的长度.此路径可能会也可能不会通过根目录.例如: 输入: 5 / \ 4 5 / \ \ 1 1 5 输出:路径为[5,5,5],边长为2 输入: 1 / \ 4 5 / \ \ 4 4 5 输出:路径为[4,4,4],边长为2 注意: 两个节点之间的路径长度由它们之间的边数表示. 给定的二叉树不超过10…

Difficulty: Hard  More:[目录]LeetCode Java实现 Description Given a string S, find the length of the longest substring T that contains at most two distinct characters.For example,Given S = “eceba”,T is "ece" which its length is 3. Intuition 方法一:假设有一个…

Given a binary tree, find the length of the longest path where each node in the path has the same value. This path may or may not pass through the root. Note: The length of path between two nodes is represented by the number of edges between them. Ex…

Given a binary tree, find the length of the longest path where each node in the path has the same value. This path may or may not pass through the root. Note: The length of path between two nodes is represented by the number of edges between them. Ex…

Given an unsorted array of integers, find the length of longest increasing subsequence. For example, Given [10, 9, 2, 5, 3, 7, 101, 18], The longest increasing subsequence is [2, 3, 7, 101], therefore the length is 4. Note that there may be more than…

本篇文章已授权微信公众号 hongyangAndroid (鸿洋)独家公布 转载请标明出处: http://blog.csdn.net/zxt0601/article/details/53040506 本文出自:[张旭童的CSDN](http://blog.csdn.net/zxt0601) 代码传送门:喜欢的话.随手点个star.多谢 https://github.com/mcxtzhang/PathAnimView 一 概述 原本仅仅是想模仿一下我魂牵梦萦的StoreHouse效果.没想到意…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 动态规划 相似题目 参考资料 日期 题目地址:https://leetcode.com/problems/minimum-falling-path-sum/description/ 题目描述 Given a square array of integers A, we want the minimum sum of a falling path th…

Given a binary tree, find the length of the longest path where each node in the path has the same value. This path may or may not pass through the root. Note: The length of path between two nodes is represented by the number of edges between them. Ex…

Given a binary tree, find the length of the longest path where each node in the path has the same value. This path may or may not pass through the root. Note: The length of path between two nodes is represented by the number of edges between them. Ex…

Binary Tree Maximum Path Sum Given a binary tree, find the maximum path sum. The path may start and end at any node in the tree. For example:Given the below binary tree, 1 / \ 2 3 Return 6.   用递归确定每一个节点作为root时,从root出发的最长的路径 在每一次递归中计算maxPath   /** * D…

Given a binary tree, find the maximum path sum. The path may start and end at any node in the tree. 找树的最大路径和 注意路径可以从任意点起始和结束. 我发现我真的还挺擅长树的题目的,递归不难.就是因为有个需要比较的量(最大和),所以需要再写一个函数. 因为路径可以从任意点起始和结束,所以每次递归的时候左右子树小于等于0的就可以不管了. #include <iostream> #include…

一.绘图路径 A.简单说明 在画线的时候,方法的内部默认创建一个path.它把路径都放到了path里面去. 1.创建路径  cgmutablepathref 调用该方法相当于创建了一个路径,这个路径用来保存绘图信息. 2.把绘图信息添加到路径里边. 以前的方法是点的位置添加到ctx(图形上下文信息)中,ctx 默认会在内部创建一个path用来保存绘图信息. 在图形上下文中有一块存储空间专门用来存储绘图信息,其实这块空间就是CGMutablePathRef. 3.把路径添加到上下文中. 代码示例:…

http://www.spoj.com/problems/LCS2/ 发现了我原来对sam的理解的一个坑233 本题容易看出就是将所有匹配长度记录在状态上然后取min后再对所有状态取max. 但是不要忘记了一点:更新parent树的祖先. 为什么呢?首先如果子树被匹配过了,那么长度一定大于任意祖先匹配的长度(甚至有些祖先匹配长度为0!为什么呢,因为我们在匹配的过程中,只是找到一个子串,可能还遗漏了祖先没有匹配到,这样导致了祖先的记录值为0,那么在对对应状态取min的时候会取到0,这样就wa了.而…