Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought through this! If the integer's…

class Solution { public: int reverse(int x) { ;//long 是怕中间过程溢出 <<,max=-min-){ ans=ans*+x%; x=x/; } if(ans>max||ans<min) ; return ans; } }; 注释: 这是进制转换问题. 转化过程中一定要考虑溢出. 清楚各种类型的表示范围. 附 32位平台: unsigned   int   0-4294967295   int    -2147483648-214…

题目如下: Given an integer number n, return the difference between the product of its digits and the sum of its digits. Example 1: Input: n = 234 Output: 15 Explanation: Product of digits = 2 * 3 * 4 = 24 Sum of digits = 2 + 3 + 4 = 9 Result = 24 - 9 = 1…

两种方法翻转一个整数.顺序翻转和递归翻转 这里没考虑overflow的情况 递归的作用是使得反向处理.即从递归栈的最低端開始处理.通过绘图可得. 假设是rec(num/10): 12345 1234 123 12 1         <-- 递归使得这个最先处理 package recursion; public class Reverse_digits_of_a_number { public static void main(String[] args) { int num = 123; S…

class Solution { public int subtractProductAndSum(int n) { int productResult = 1; int sumResult = 0; do { int currentval = n % 10; productResult *= currentval; sumResult += currentval; n /= 10; }while(n > 0); return productResult - sumResult; } }…

Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought through this! If the integer'…

Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 click to show spoilers. Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought throu…

Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 public class Solution { public int reverse(int x) { if(x==Integer.MIN_VALUE) return 0; long result = 0; int i = 0; int temp = (x>0)?1:0; x = Math.abs(x); while…

问题: Reverse digits of an integer.Example1:x = 123, return 321Example2:x = -123, return -321 官方难度: Easy 翻译: 将一个整数倒转输出. 例子: 整数:123,倒转输出:321. 整数:-123,倒转输出:-321. 给定例子中,存在负数情况,将负数的输入转化成整数统一讨论,同时记录负数标志位,在返回时使用. 优先获取整数的位数,有两种方法:第一种是根据定义出发,循环将输入数字除以10,累加次数.这…

Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 public class Solution { public int reverse(int x) { boolean isPositive = true; ) { x = -x; isPositive = false; } ; ) { reversedValue = reversedValue * + x % ;…

[Question] Reverse digits of an integer. Example: x = 123, return 321 x = -123, return -321 [My Solution] class Solution(object): def reverse(self, x): """ :type x: int :rtype: int """ neg = 1 if x < 0: neg = -1 if x == 0:…

Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 总结:处理整数溢出的方法 ①用数据类型转换long  或 long long ②在每次循环时先保存下数字变化之前的值,处理后单步恢复看是否相等 (比③好) ③整体恢复,看数字是否相等. 思路:注意30000这样以0结尾的数字,注意越界时返回0. 我检查越界是通过把翻转的数字再翻转回去,看是否相等. int rever…

题目描述: Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 很简单的题目其实用个数组就能解决了,不过用了一下queue,注意负数的情况. class Solution { public: int reverse(int x) { bool flg=false; ){ flg=true; x=-x; } queue<int> a; ){ a.push(x%); x…

问题: Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return –321   Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought through this! If the in…

Reverse digits of an integer. Returns 0 when the reversed integer overflows (signed 32-bit integer). Have you met this question in a real interview?     Example Given x = 123, return 321 Given x = -123, return -321 LeetCode上的原题,请参见我之前的博客Reverse Integ…

Reverse Integer Reverse digits of an integer. Example1: x =  123, return  321 Example2: x = -123, return -321 click to show spoilers. Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have alr…

题目来源:https://leetcode.com/problems/reverse-integer/ Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 解题思路: 其实这道题看起来非常简单,要实现也是几行代码的事.但是有个小问题容易被忽略,就是边界问题.什么意思呢?如果我们输入的整数超出了int的表达范围,这个问题要怎么解决呢? 用比int更大的数据类型存储我们转…

Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 解题思路:将数字翻转并不难,可以转成String类型翻转,也可以逐位翻转,本题涉及到的主要是边界和溢出问题,使用Long或者BigInteger即可解决. 题目不难: JAVA实现如下: public class Solution { static public int reverse(int x) { if(x=…

Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 click to show spoilers. Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought throug…

Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 Solution 1: class Solution { public: int reverse(int x) { ; ) { && result > (INT_MAX - x % ) / || x < && result < (INT_MIN - x % ) / ) ; re…

Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 代码如下: public class Solution { public int reverse(int n) { long sum=0; int flag=1; if(n<0) { flag=-1; n=n*(-1); } try{ String s=Integer.toString(n); s=new Strin…

题目: Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 思路:不断取最低位加到先前值得后面,如下: while(x!=0){ res=res*10+x%10; x/=10; } 还要注意反转后可能会出现溢出的情况. public class Solution { public int reverse(int x) { long res=0; while(x!=0…

7. Reverse Integer Total Accepted: 153147 Total Submissions: 644103 Difficulty: Easy Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 思路: 本题思路很简单,有多种方法:要注意的就是判断反转之后的结果是否超出了int类型的范围. 第一种是直接对10取余和除,然后每加一位,就将原先…

7 - Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 Notice: 1.If the integer's last digit is 0, what should the output be? ie, cases such as 10, 100. 2.Did you notice that the reversed integer might overflow…

Question:Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought through this! If the…

Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 click to show spoilers. Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought throug…

问题描述: Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought through this! If the in…

题目描述: Reverse digits of an integer. Example1: x = 123, return 321Example2: x = -123, return -321 解题思路: 这道题比较简单,只要注意两个问题:1,输入可能有123,-123两种情况.2,可能会出现值溢出的情况,所以先用long类型处理,决定没有溢出后再转换为int 具体代码: public static int reverse(int x) { String s =""+x; char[]…

Reverse Integer Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 time=272ms accepted public class Solution { public int reverse(int x) { long recv=0; int mod=0; int xabs=Math.abs(x); while(xabs>0){ mod=xabs%…

problem: Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 thinking: (1)整型反转直观非常easy理解. 如正负,尾数为0等问题还优点理. (2)反转溢出问题要细致处理. code: class Solution { public: int reverse(int x) { long long int y=x; bool flag=true;…