Girls' research Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 537    Accepted Submission(s): 199 Problem Description One day, sailormoon girls are so delighted that they intend to research abo…

Girls' research Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others) Total Submission(s): 1160    Accepted Submission(s): 448 Problem Description One day, sailormoon girls are so delighted that they intend to research a…

Girls' researchTime Limit: 3000/1000 MS (Java/Others) Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 4401 Accepted Submission(s): 1642 Problem Description One day, sailormoon girls are so delighted that they intend to research about pa…

http://acm.hdu.edu.cn/showproblem.php?pid=3294 Girls' research Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 3294 Description One day, sailormoon girls are so delighted that they intend to res…

题目链接:https://vjudge.net/problem/HDU-3294 Girls' research Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 3209    Accepted Submission(s): 1228 Problem Description One day, sailormoon girls are so…

题目链接: Hdu 3294  Girls' research 题目描述: 给出一串字符串代表暗码,暗码字符是通过明码循环移位得到的,比如给定b,就有b == a,c == b,d == c,.......,a == z. 问最长回文串所在区间,以及最长回文串所表示的明码. 解题思路: 字符串长度[1,200000],用manacher算法很轻松就搞定了. get√新技能请点击me #include <cstdio> #include <string> #include <c…

HDU   3294 Problem Description One day, sailormoon girls are so delighted that they intend to research about palindromic strings. Operation contains two steps:First step: girls will write a long string (only contains lower case) on the paper. For exa…

Problem Description One day, sailormoon girls are so delighted that they intend to research about palindromic strings. Operation contains two steps:First step: girls will write a long string (only contains lower case) on the paper. For example, "abcd…

One day, sailormoon girls are so delighted that they intend to research about palindromic strings. Operation contains two steps:First step: girls will write a long string (only contains lower case) on the paper. For example, "abcde", but 'a' ins…

One day, sailormoon girls are so delighted that they intend to research about palindromic strings. Operation contains two steps: First step: girls will write a long string (only contains lower case) on the paper. For example, "abcde", but 'a' in…

本文版权归ljh2000和博客园共有,欢迎转载,但须保留此声明,并给出原文链接,谢谢合作. 本文作者:ljh2000 作者博客:http://www.cnblogs.com/ljh2000-jump/转载请注明出处,侵权必究,保留最终解释权!   Problem Description One day, sailormoon girls are so delighted that they intend to research about palindromic strings. Operati…

文章目录 思路如下 Manachar代码注释 题解如下 Problem Description One day, sailormoon girls are so delighted that they intend to research about palindromic strings. Operation contains two steps: First step: girls will write a long string (only contains lower case) on…

After an uphill battle, General Li won a great victory. Now the head of state decide to reward him with honor and treasures for his great exploit. One of these treasures is a necklace made up of 26 different kinds of gemstones, and the length of the…

变形的求最大回文子串,要求输出两个端点. 我觉得把'b'定义为真正的'a'是件很无聊的事,因为这并不会影响到最大回文子串的长度和位置,只是在输出的时候设置了一些不必要的障碍. 另外要注意一下原字符串s1中的字符在预处理以后的字符串s2中对应的坐标关系,这样输出的时候就可以照着这个关系转化. 轻松1A,嘿嘿 //#define LOCAL #include <iostream> #include <cstdio> #include <cstring> using name…

hdu3294:http://acm.hdu.edu.cn/showproblem.php?pid=3294 题意:就是给你一个串,然后求一个最长的回文串,输出起点及串,但是这里在之前要转化一下. 题解:转化一下,就是简单的Manacher算法. #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> using namespace std; ; ]; int rad…

题目大意:给以一个字符串,求出来这个字符串的最长回文串,不过这个字符串不是原串,而是转换过的,转换的原则就是先给一个字符 例如 'b' 意思就是字符把字符b转换成字符 a,那么c->b, d->c.....a->z,大致就是这么个意思,然后求出最大回文串就行(回文串至少长度也得等于2).   分析:字符转换没什么可说的,求回文串可以使用Manacher算法,主要说一下怎么用 p数组保存的信息求原来的区间,因为p保存的是扩展串的匹配数目,p[i]就是保存的最大匹配值,我们可以先求出来它的最…

题目地址 manacher #include<cstdio> #include<string.h> #include<algorithm> using namespace std; ; char s[Nmax]; +]; +]; +]; int id; int maxlen; int len; int start; int endd; void init() { id=; maxlen=; int n=strlen(s); str[]='$'; str[]='#'; ;…

BUPT2017 wintertraining(15) #5F HDU - 3294 题意 给定字母x,字符串变换一下: 'x'-1 -> 'z', 'x'->'a', 'x'+1->'b', ..., 求对应的字符串的最长的回文串. 题解 求最长回文串的O(n)的算法:Manacher算法 算法过程: 用'#'号把每个字符分隔开,且开头结尾都是'#'. RL[i]为以i为中心的最长回文最右的字符与i的距离. 已经求过的回文串中,右端点最大的回文串的中心为p. 求当前的RL[i]时,若…

题意: 求最长回文串 长度要大于等于2  且输出起点和终点  输出回文串字符 这个字符还是要以给出的字符为起点a 输出 解析: 分析一下s_new串就好了 #include <iostream> #include <cstdio> #include <sstream> #include <cstring> #include <map> #include <set> #include <vector> #include &l…

本文原创:http://www.cnblogs.com/BigBallon/p/3816890.html只为了记录学习,不为抄袭!http://www.felix021.com/blog/read.php?2040 对于Manacher算法,主要的作用是用来求一个字符串的最长回文子串.这个算法的时间复杂度书线性的,即O(n)下面我分两个部分来讲1)预处理这个算法的精妙之处在于巧妙地避免了考虑回文子串的长度是奇数还是偶数(如果你还不知道什么是回文数,回文串,请自行baidu)在Manacher算法…

传送门:Girls' research 题意:求最长回文串并输出位置及转换后的字符串. 分析:manacher算法算出最长回文串后记录中心位置,然后再转换回原字符串的起始和结束位置. #pragma comment(linker,"/STACK:1024000000,1024000000") #include <cstdio> #include <cstring> #include <string> #include <cmath> #i…

KUANGBIN带你飞 全专题整理 https://www.cnblogs.com/slzk/articles/7402292.html 专题一 简单搜索 POJ 1321 棋盘问题    //2019.3.18 POJ 2251 Dungeon Master POJ 3278 Catch That Cow  //4.8 POJ 3279 Fliptile POJ 1426 Find The Multiple  //4.8 POJ 3126 Prime Path POJ 3087 Shuffle…

1.POJ 3974 Palindrome 题意:求一个长字符串的最长回文子串. 思路:Manacher模板. #include<iostream> #include<algorithm> using namespace std; ; char s[maxn]; * maxn + ]; * maxn + ]; int Manacher(char *s,char *tmp,int *p, int &start) {////s原字符串,tmp转换后的字符串,p记录长度 //ch…

一. KMP 1 找字符串x是否存在于y串中,或者存在了几次 HDU1711 Number Sequence HDU1686 Oulipo HDU2087 剪花布条 2.求多个字符串的最长公共子串 POJ3080 Blue Jeans HDU1238 Substrings 3.next数组的应用 1) 求循环节 HDU3746 Cyclic Nacklace HDU1358 Period POJ2406 Power Strings HDU3374 String Problem 2) 利用next…

[kuangbin带你飞]专题1-23 专题一 简单搜索 POJ 1321 棋盘问题POJ 2251 Dungeon MasterPOJ 3278 Catch That CowPOJ 3279 FliptilePOJ 1426 Find The MultiplePOJ 3126 Prime PathPOJ 3087 Shuffle'm UpPOJ 3414 PotsFZU 2150 Fire GameUVA 11624 Fire!POJ 3984 迷宫问题HDU 1241 Oil Deposit…

来刷kuangbin字符串了,字符串处理在ACM中是很重要的,一般比赛都会都1——2道有关字符串处理的题目,而且不会很难的那种,大多数时候都是用到一些KMP的性质或者找规律. 点击标题可跳转至VJ比赛题目链接. A - Number Sequence 题意就是让你去找在串A找串B首次出现的位置,现在串不是字符串,而是数字串,所以用int数组存储即可,然后就是裸KMP. 代码: #include <string> #include <algorithm> #include <i…

http://acm.hdu.edu.cn/showproblem.php?pid=3294 Girls' research Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)Total Submission(s): 5711    Accepted Submission(s): 2117 Problem Description One day, sailormoon girls…

专题一 简单搜索 POJ 1321 棋盘问题POJ 2251 Dungeon MasterPOJ 3278 Catch That CowPOJ 3279 FliptilePOJ 1426 Find The MultiplePOJ 3126 Prime PathPOJ 3087 Shuffle'm UpPOJ 3414 PotsFZU 2150 Fire GameUVA 11624 Fire!POJ 3984 迷宫问题HDU 1241 Oil DepositsHDU 1495 非常可乐HDU 26…

题意: 给一个字符x代表真实的a 然后输出的时候转换 然后就是求最长回文子串的串是什么 长度要大于1 思路: 就是裸的manacher,弄清楚下标的转换关系就好了 代码: #include"cstdlib" #include"cstdio" #include"cstring" #include"cmath" #include"queue" #include"algorithm" #inc…

#include<stdio.h> #include<string.h> #define MAX 200020 char s[MAX],ss[MAX*2],str[2]; int p[MAX*2]; int chance(char s) { return (s- str[0] + 26) % 26 + 'a'; } int min(int a,int b){return a>b? b:a;} int main() { int i,id,mx,max,n,j,ans,m; wh…