题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1213 有关系(直接或间接均可)的人就坐在一张桌子,我们要统计的是最少需要的桌子数. 并查集的入门题,什么优化都无用到就可以直接过.实质上就是统计总共有多少个不相交的集合.比较可恶的是,题目中 There will be a blank line between two cases 是骗人的!!! #include <iostream> using namespace std; + ; int p[…

[九度OJ]题目1445:How Many Tables 解题报告 标签(空格分隔): 九度OJ 原题地址:http://ac.jobdu.com/problem.php?pid=1445 题目描述: Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1213 How Many Tables Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 13787    Accepted Submission(s): 6760 Problem Description Today is Ignatius' b…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1213 Problem Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the frie…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1050 这道题目隔了很久才做出来的.一开始把判断走廊有重叠的算法都想错了.以为重叠只要满足,下一次moving的起始room小于或等于上一次moving的结束room则证明有重复.这样只能保证局部不能同时进行moving,但是根本得不出其他moving哪些是可以同时进行搬动的. 正确的思路是,统计最大的重叠数,再乘以10即可.具体做法:把每个房间之间的走廊作为一个统计单位,当所有的办公桌都搬运完成之后…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=1213 Problem Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the fri…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1213 Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the friends know each other,…

http://acm.hdu.edu.cn/showproblem.php?pid=1213 题意: 这个问题的一个重要规则是,如果我告诉你A知道B,B知道C,这意味着A,B,C知道对方,所以他们可以留在一个桌子. 例如:如果我告诉你A知道B,B知道C,D知道E,所以A,B,C可以留在一个桌子中,D,E必须留在另一个桌子中.所以Ignatius至少需要2个桌子. 思路: 并查集模板题. #include<iostream> using namespace std; ]; int find(in…

题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=1213 题意 给出N个人 M对关系 找出共有几对连通块 思路 并查集 AC代码 #include <cstdio> #include <cstring> #include <ctype.h> #include <cstdlib> #include <cmath> #include <climits> #include <ctime&g…

解题思路:和畅通工程类似,问最后还剩下几个不连通的区域. How Many Tables Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 15086    Accepted Submission(s): 7364 Problem Description Today is Ignatius' birthday. He invites a…