COURSES POJ1469(模板)】的更多相关文章

Description Consider a group of N students and P courses. Each student visits zero, one or more than one courses. Your task is to determine whether it is possible to form a committee of exactly P students that satisfies simultaneously the conditions:…
COURSES Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 18454   Accepted: 7275 Description Consider a group of N students and P courses. Each student visits zero, one or more than one courses. Your task is to determine whether it is poss…
书籍出处:https://www.packtpub.com/web-development/django-example 原作者:Antonio Melé (译者注:翻译本章过程中几次想放弃,但是既然都到第十章了,怎么能放弃!) 第十章 创建一个在线学习平台(e-Learning Platform) 在上一章,你添加国际化到你的在线商店项目中.你还构建了一个优惠券系统和一个商品推荐引擎.在这章中,你会创建一个新项目.你将构建一个在线学习平台创建一个定制内容管理系统. 在这章中,你会学习以下操作:…
题目链接: http://poj.org/problem?id=1469 Description Consider a group of N students and P courses. Each student visits zero, one or more than one courses. Your task is to determine whether it is possible to form a committee of exactly P students that sat…
http://poj.org/problem?id=1469 COURSES Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 19419   Accepted: 7642 Description Consider a group of N students and P courses. Each student visits zero, one or more than one courses. Your task is…
原文链接http://www.cnblogs.com/zhouzhendong/p/8232649.html 题目传送门 - POJ1469 题意概括 在一个大矩阵中,有一些障碍点. 现在让你用1*2的小矩形覆盖非障碍点,要求不覆盖到障碍点并且不重复覆盖,问是否可以覆盖所有非障碍点. 题解 本题几乎是裸题. 首先注意读入的表示障碍点的二元组(x,y)中y是行,x是列. 这个毒性深重<差评> 然后考虑算法.读者可以参考笔者的前一篇博客. 对于相邻的非障碍点我们来回都建边.然后我们给原图按照到某一…
题目链接:http://acm.split.hdu.edu.cn/showproblem.php?pid=1083 Time Limit: 20000/10000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Problem Description Consider a group of N students and P courses. Each student visits zero, one or more than…
COURSES Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 17777   Accepted: 7007 Description Consider a group of N students and P courses. Each student visits zero, one or more than one courses. Your task is to determine whether it is poss…
题目大意:一共有N个学生跟P门课程,一个学生可以任意选一门或多门课,问是否达成: 1.每个学生选的都是不同的课(即不能有两个学生选同一门课) 2.每门课都有一个代表(即P门课都被成功选过) 输入为: P N(课程数跟学生数) 接着有P行,格式为Count studenti studenti+1 --studentcount (Count表示对课程1感兴趣的学生数,接着有Count个学生) 如第一行3 1 2 3表示学生1跟学生2跟学生3对课程1感兴趣 输出为: 若能满足上面两个要求这输出"YES…
http://poj.org/problem?id=2239 这里要处理的是构图问题p (1 <= p <= 7), q (1 <= q <= 12)分别表示第i门课在一周的第p天的第q节课上 其中二分图的X集合里表示课程i,那么我们要解决的就是Y集合了 将第i门课在一周的第p天的第q节课上进行编号,这样Y集合就是 上课时间的编号了 #include<stdio.h> #include<string.h> #include<math.h> #in…