POJ 2502 Subway dij】的更多相关文章

这个题的输入输出注意一下就好 #include<cstdio> #include<cstring> #include<queue> #include<cstdlib> #include<algorithm> #include<vector> #include<cmath> using namespace std; typedef long long LL; ; const int INF=0x3f3f3f3f; struc…
POJ 2502 Subway / NBUT 1440 Subway / SCU 2186 Subway(图论,最短距离) Description You have just moved from a quiet Waterloo neighbourhood to a big, noisy city. Instead of getting to ride your bike to school every day, you now get to walk and take the subway.…
做这道题的动机就是想练习一下堆的应用,顺便补一下好久没看的图论算法. Dijkstra算法概述 //从0出发的单源最短路 dis[][] = {INF} ReadMap(dis); for i = 0 -> n - 1 d[i] = dis[0][i] while u = GetNearest(1 .. n - 1, !been[]) been[u] = 1 for_each edge from u d[edge.v] = min(d[edge.v], d[u] + dis[u][edge.v]…
Subway Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 6692   Accepted: 2177 Description You have just moved from a quiet Waterloo neighbourhood to a big, noisy city. Instead of getting to ride your bike to school every day, you now get…
Subway Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 6689   Accepted: 2176 Description You have just moved from a quiet Waterloo neighbourhood to a big, noisy city. Instead of getting to ride your bike to school every day, you now get…
Subway Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 4928   Accepted: 1602 Description You have just moved from a quiet Waterloo neighbourhood to a big, noisy city. Instead of getting to ride your bike to school every day, you now get…
Subway 题目链接: http://acm.hust.edu.cn/vjudge/contest/122685#problem/L Description You have just moved from a quiet Waterloo neighbourhood to a big, noisy city. Instead of getting to ride your bike to school every day, you now get to walk and take the s…
Description You have just moved from a quiet Waterloo neighbourhood to a big, noisy city. Instead of getting to ride your bike to school every day, you now get to walk and take the subway. Because you don't want to be late for class, you want to know…
题目传送门 题意:列车上行驶40, 其余走路速度10.问从家到学校的最短时间 分析:关键是建图:相邻站点的速度是40,否则都可以走路10的速度.读入数据也很变态. #include <cstdio> #include <cmath> #include <algorithm> #include <cstring> #include <queue> using namespace std; const int N = 2e2 + 5; const i…
<题目链接> 题目大意: 某学生从家到学校之间有N(<200)条地铁,这个学生可以在任意站点上下车,无论何时都能赶上地铁,可以从一条地铁的任意一站到另一条地跌的任意一站,学生步行速度10km/h,地铁速度40km/h,给出学生家和学校以及每条地铁的站点坐标,求学生从家到学校的最短时间. 解题分析:题目的难点在于建图,由于输入的点最多200个,并且所有点之间的距离都要考虑,所以用邻接矩阵存图,注意速度的单位是km/h,而路程的单位是m,并且要将地铁站点之间与普通点之间的距离区分,存好图后,…