732. 我的日程安排表 III 实现一个 MyCalendar 类来存放你的日程安排,你可以一直添加新的日程安排. MyCalendar 有一个 book(int start, int end)方法.它意味着在start到end时间内增加一个日程安排,注意,这里的时间是半开区间,即 [start, end), 实数 x 的范围为, start <= x < end. 当 K 个日程安排有一些时间上的交叉时(例如K个日程安排都在同一时间内),就会产生 K 次预订. 每次调用 MyCalenda
Implement a MyCalendarThree class to store your events. A new event can always be added. Your class will have one method, book(int start, int end). Formally, this represents a booking on the half open interval [start, end), the range of real numbers
请点击页面左上角 -> Fork me on Github 或直接访问本项目Github地址:LeetCode Solution by Swift 说明:题目中含有$符号则为付费题目. 如:[Swift]LeetCode156.二叉树的上下颠倒 $ Binary Tree Upside Down 请下拉滚动条查看最新 Weekly Contest!!! Swift LeetCode 目录 | Catalog 序 号 题名Title 难度 Difficulty 两数之
[1]LeetCode 136 Single Number 题意:奇数个数,其中除了一个数只出现一次外,其他数都是成对出现,比如1,2,2,3,3...,求出该单个数. 解法:容易想到异或的性质,两个相同的数异或为0,那么把这串数从头到尾异或起来,最后的数就是要求的那个数. 代码如下: class Solution { public: int singleNumber(vector<int>& nums) { ; ;i<nums.size();i++) sum ^= nums[i
SPOJ - GSS3 Can you answer these queries III Description You are given a sequence A of N (N <= 50000) integers between -10000 and 10000. On this sequence you have to apply M (M <= 50000) operations: modify the i-th element in the sequence or for giv
F. Heroes of Making Magic III time limit per test:3 seconds memory limit per test:256 megabytes input:standard input output:standard output I’m strolling on sunshine, yeah-ah! And doesn’t it feel good! Well, it certainly feels good for our Heroes of
问题: Say you have an array for which the ith element is the price of a given stock on day i. Design an algorithm to find the maximum profit. You may complete at most two transactions. 依旧还是那个熟悉的味道,如果II是I的另一个版本,那么III就是他们的一个升级版. 在这个版本中只能交易两次,也就是买卖各两次,其它条
1. Given an array of integers, return indices of the two numbers such that they add up to a specific target. 问题: 1.数组是否有序 2. 数组排序 // sorting array Arrays.sort(iArr) 方法1:O(n^2) public class Solution { public int[] twoSum(int[] nums, int target) { int[
Single Number I : Given an array of integers, every element appears twice except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? Solution: 解法不少,贴一种: class
英雄无敌三简介(Heroes of Might and Magic III) 英3是1999年由New World Computing在Windows平台上开发的回合制策略魔幻游戏,其出版商是3DO.是一款经典的战棋类游戏,也是我接触最早和玩的时间最多的一款游戏.官方的最新资料片版本是<<死亡阴影:The Shadow Of Death>>,程序最高版本是3.2. 英雄无敌三现有非官方Mod介绍 一,神之苏醒(Wake Of God),老毛子(GrayFAce)作品,首款非官方Mo
Ignatius and the Princess III Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 11810 Accepted Submission(s): 8362 Problem Description "Well, it seems the first problem is too easy. I will let
Given an array of integers, every element appears twice except for one. Find that single one. 本题利用XOR的特性, X^0 = X, X^X = 0, 并且XOR满足交换律. class Solution(object): def singleNumber(self, nums): """ :type nums: List[int] :rtype: int ""
Given an array of integers, find out whether there are two distinct indices i and j in the array such that the difference between nums[i] andnums[j] is at most t and the difference between i and j is at most k. public class Solution { public boolean
Ferry Loading IIITime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 463 Accepted Submission(s): 110 Problem DescriptionBefore bridges were common, ferries were used to transport cars across rivers. Ri
