And Then There Was One Time limit: 3.000 seconds Let’s play a stone removing game. Initially, n stones are arranged on a circle and numbered 1,...,n clockwise (Figure 1). You are also given two numbers k and m. From this state, remove stones one by o
And Then There Was One UVALive - 3882 Sample Input Sample Output //设f[i]为(原约瑟夫问题)第i次要删除的标号 #include<cstdio> using namespace std; ; int n,m,k,f[N]; int main(){ &&n){ //f[1]=0; //for(int i=2;i<=n;i++) f[i]=(f[i-1]+k)%i; //int ans=(m-k+f[n
Joseph Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 47657 Accepted: 17949 Description The Joseph's problem is notoriously known. For those who are not familiar with the original problem: from among n people, numbered 1, 2, . . ., n,
Integers 1, 2, 3,..., n are placed on a circle in the increasing order as in the following figure. We want to construct a sequence from these numbers on a circle. Starting with the number 1, we continually go round by picking out each k-th number and
题目链接:http://poj.org/problem?id=3517 And Then There Was One Time Limit: 5000MS Memory Limit: 65536K Total Submissions: 5014 Accepted: 2685 Description Let’s play a stone removing game. Initially, n stones are arranged on a circle and numbered 1, …
Description Recently you must have experienced that when too many people use the BBS simultaneously, the net becomes very, very slow.To put an end to this problem, the Sysop has developed a contingency scheme for times of peak load to cut off net acc
/* * POJ_1591_2.cpp * * Created on: 2013年10月31日 * Author: Administrator */ #include <iostream> #include <cstdio> using namespace std; const int maxn = 55; int cards[25]; bool position[maxn]; int main(){ int participants,lucky; int counter = 1;
Description Let’s play a stone removing game. Initially, n stones are arranged on a circle and numbered 1, …, n clockwise (Figure 1). You are also given two numbers k and m. From this state, remove stones one by one following the rules explained belo
