1075 PAT Judge (25分)   The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For eac

1075 PAT Judge (25 分) The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For each

题目地址:http://pat.zju.edu.cn/contests/pat-a-practise/1075 此题主要考察细节的处理,和对于题目要求的正确理解,另外就是相同的总分相同的排名的处理一定要熟练,还有就是编译没有通过为零分,没有提交显示为"-": #include <cstdio> #include <vector> #include <algorithm> using namespace std; ; vector<); int

题目:https://pintia.cn/problem-sets/994805342720868352/problems/994805393241260032 题意: 有m次OJ提交记录,总共有k道题,n个人.每道题有一个最高分. 现在要统计用户的排名,如果总分相同,完整AC的题目数高的排前面,都一样id小的排前面. 如果没有提交记录,或者提交记录都是-1的用户,就不输出. 思路: 根据题意模拟.PAT的题目都要耐心好好读题啊,各种情况都要看清楚. #include<cstdio> #inc

The ranklist of PAT is generated from the status list, which shows the scores of the submittions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For each case, the first line

The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For each case, the first line

题意: 输入三个正整数N,K,M(N<=10000,K<=5,M<=100000),接着输入一行K个正整数表示该题满分,接着输入M行数据,每行包括学生的ID(五位整数1~N),题号和该题得分(-1表示没通过编译).输出排名,学生ID,总分和每一题的得分,第一优先为总分降序,第二优先为题目AC数降序,第三优先为学生ID升序(提交但未通过编译得分为0,未提交得分为-,不输出没有提交或者提交全都未通过编译的学生信息). trick: 测试点4为有学生先交了得到分的程序后该题后来又交了未通过编译

The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For each case, the first line

排序题 #include <stdio.h> #include <string.h> #include <iostream> #include <algorithm> #include <map> using namespace std; const int N = 100005; int score[10]; struct Node { int id; int problem; int get; }person[N]; struct ANS {

简单模拟题. 注意一点:如果一个人所有提交的代码都没编译通过,那么这个人不计排名. 如果一个人提交过的代码中有编译不通过的,也有通过的,那么那份编译不通过的记为0分. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<stack> #include<queue> #include<str

相当于是模拟OJ评测,这里注意最后输出:1.那些所有提交结果都是-1的(即均未通过编译器的),或者从没有一次提交过的用户,不需要输出.2.提交结果为-1的题目,最后输出分数是03.某个题目从没有提交过的,输出'-' #include <iostream> #include <cstdio> #include <algorithm> #include <string.h> #include <cmath> #include <queue>

题目地址 https://pta.patest.cn/pta/test/16/exam/4/question/677 5-15 PAT Judge   (25分) The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Spe

A1075 PAT Judge (25)(25 分) The ranklist of PAT is generated from the status list, which shows the scores of the submittions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For

Source: PAT A1075 PAT Judge (25 分) Description: The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contai

The ranklist of PAT is generated from the status list, which shows the scores of the submittions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For each case, the first line

The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For each case, the first line

原题连接:https://pta.patest.cn/pta/test/16/exam/4/question/677 题目如下: The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each

用了冒泡和插入排序 果然没有什么本质区别..都是运行超时 用库函数sort也超时 The ranklist of PAT is generated from the status list, which shows the scores of the submittions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one

The ranklist of PAT is generated from the status list, which shows the scores of the submissions. This time you are supposed to generate the ranklist for PAT. Input Specification: Each input file contains one test case. For each case, the first line

其中在排名输出上参照了 http://blog.csdn.net/xyzchenzd/article/details/27074665,原先自己写的很繁琐,而且还有一个测试点不通过. #include <iostream> #include <vector> #include <string.h> #include <algorithm> #include <stdio.h> using namespace std; struct PATInfo