Implement an iterator to flatten a 2d vector. For example,Given 2d vector = [ [1,2], [3], [4,5,6] ] By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,2,3,4,5,6]. Hint: How many variables do y
Implement an iterator to flatten a 2d vector. For example,Given 2d vector = [ [1,2], [3], [4,5,6] ] By calling next repeatedly until hasNext returns false, the order of elements returned by next should be: [1,2,3,4,5,6]. Hint: How many variables do y
本文原创,转载请注明出处,本人Q1273314690(交流学习) 总结: 就是MARGIN决定了你的FUN调用几次,每次传递给你的是什么维度的内容,而...是传递给FUN的(每次调用的时候都会被传递给FUN).apply的返回值结果可能是向量,数组(含矩阵)或列表(具体要根据条件分类讨论,但实际上我们没有必要,直接看一下返回的结果就知道是什么类型了) apply {base} Description Returns a vector or array or list of values
http://www.lydsy.com/JudgeOnline/problem.php?id=2115 题意:给出一个n个点m条边的无向连通边加权图,求1-n的某条路径使得异或值最大(可以重复点可以重复边)(n<=50000, m<=100000) #include <bits/stdc++.h> using namespace std; const int N=50005, M=100015; typedef long long ll; struct E { int next,