一.基础内容 0.官方文档说明 (1)org.apache.lucene.index provides two primary classes: IndexWriter, which creates and adds documents to indices; and IndexReader, which accesses the data in the index. (2)涉及的两个主要包有: org.apache.lucene.index:Code to maintain and acces
Heros and Swords Time Limit: 6000/3000MS (Java/Others) Memory Limit: 128000/64000KB (Java/Others) Submit Statistic Next Problem Problem Description There are n swords of different weights Wi and n heros of power Pi. Your task is to find out how many
Lunch Time Time Limit: 2 Seconds Memory Limit: 65536 KB The 999th Zhejiang Provincial Collegiate Programming Contest will be held in Marjar University. The canteen of Marjar University is making preparations for this grand competition. The canteen pr
select * from (select a.*,rownum as rn from tetm_ad_type a) b where b.rn<30 --表名不能用as 字段取别名,直接在表名后面跟一个newName 就算别名了.字段 名能够用as 取别名. 事实上我都是乱写的. oralce
Sub test()'updateby Extendoffice 20151030 Dim xRng As Range Dim xTxt As String On Error Resume Next xTxt = Application.ActiveWindow.RangeSelection.Address Sheets("Data").Select Columns("A:W").Select Set xRng = Colu
#include <cstdio> #include <iostream> #include <cstring> #include <queue> #include <vector> using namespace std; #define INF 0x7fffffff struct edge { int t; long long d; }; vector<edge> g[20005]; int n, m, p, q; void Sp
这题目看一眼以为难度评级出错了,只是一个求余数的题目,,后来才发现,位数小于百万位,,,我还以为是大小小于百万呢,所以借鉴了另一大神的代码, 用大数,重点是同余定理: (a+b)mod m=((a mod m)+(b mod m))mod m; a*b mod m=(a mod m)*(b mod m) mod m; a^b mod m=(a mod m)^b mod m; #include<stdio.h> #include<string.h> #include<stdli
