A video by 3Blue1Brown in Bilibili\text{A video by 3Blue1Brown in Bilibili}A video by 3Blue1Brown in Bilibili I don't have a systematic face to Derivatives before, but now I do.\text{I don't have a systematic face to Derivatives before, but now I do.
今天推导公式,发现居然有对矩阵的求导,狂汗--完全不会.不过还好网上有人总结了.吼吼,赶紧搬过来收藏备份. 基本公式:Y = A * X --> DY/DX = A'Y = X * A --> DY/DX = AY = A' * X * B --> DY/DX = A * B'Y = A' * X' * B --> DY/DX = B * A' 1. 矩阵Y对标量x求导: 相当于每个元素求导数后转置一下,注意M×N矩阵求导后变成N×M了 Y = [y(ij)] --> dY/
转载自: http://blog.csdn.net/txwh0820/article/details/46392293 矩阵的迹求导法则 1. 复杂矩阵问题求导方法:可以从小到大,从scalar到vector再到matrix 2. x is a column vector, A is a matrix d(A∗x)/dx=A d(xT∗A)/dxT=A d(xT∗A)/dx=AT d(xT∗A∗x)/dx=xT(AT+A) 3. Practice: 4. 矩阵求导计算法则 求导公式(撇号为
cr:http://blog.csdn.net/txwh0820/article/details/46392293 一.矩阵的迹求导法则 1. 复杂矩阵问题求导方法:可以从小到大,从scalar到vector再到matrix 2. x is a column vector, A is a matrix d(A∗x)/dx=A d(xT∗A)/dxT=A d(xT∗A)/dx=AT d(xT∗A∗x)/dx=xT(AT+A) 3. Practice: 4. 矩阵求导计算法则 求导公式(撇号为
该文件是APM的主文件. #define SCHED_TASK(func, rate_hz, max_time_micros) SCHED_TASK_CLASS(Copter, &copter, func, rate_hz, max_time_micros) /* scheduler table for fast CPUs - all regular tasks apart from the fast_loop() should be listed here, along with how of