GO --判断表是否存在方式1 if object_id(N'EF_User',N'U') is null --判断表是否存在方式2 --if not exists (select * from dbo.SysObjects WHERE id = object_id(N'[EF_User]') AND OBJECTPROPERTY(ID, 'IsTable') = 1) begin --直接创建自增且指定主键约束的表 CREATE TABLE [dbo].[EF_User]( ,) not nu
问: In SQL Server , I got this error -> "There are no primary or candidate keys in the referenced table 'BookTitle' that match the referencing column list in the foreign key 'FK_BookCopy_Title__2F10007B'." I first created a relation called the
SELECT oSub.name AS [子表名称] , fk.name AS [外键名称] , SubCol.name AS [子表列名] , oMain.name AS [主表名称] , MainCol.name AS [主表列名] FROM sys.foreign_keys fk JOIN sys.all_objects oSub ON ( fk.parent_object_id = oSub.object_id ) JOIN sys.all_objects oMain ON ( fk.r
SELECT ROW_NUMBER() over(partition by a.yngrbsh order by a.SFRQ desc ) RN, c.' and a.LSH not in(select SFLSH from JB_NCZ_GW_ZZD b) 在结果中根据yngrbsh进行分组,然后可以取出RN等于1的数据.
-- SQL SERVER 判断是否存在某个触发器.储存过程 -- 判断储存过程,如果存在则删除IF (EXISTS(SELECT * FROM sysobjects WHERE name='procedurename' AND type='P')) DROP PROCEDURE procedurename -- 判断触发器,如果存在则删除IF (EXISTS(SELECT * FROM sysobjects WHERE id=object_id(N'[dbo].[triggername]')
原文:SQL Server判断某个字段是否包含中文/英文字符/数字 因最近在清理系统中的脏数据,需要查询某个字段是否包含中文/英文字符/数字的数据, 比较简单,仅以此篇博客做一个简单总结,方便以后查阅. 1.判断某个字段是否包含中文字符 SELECT * FROM dbo.Channel_ShopCommodity AND StoreCode LIKE '%[吖-座]%'; 2.判断某个字段是否包含英文字符 SELECT * FROM dbo.Channel_ShopCommodity AND
Sql Server: What is the benefit of using “Enforce foreign key constraint” when it's set to “NO”? 问 I know the purpose of "Enforce foreign key constraint" in RDBMS. But is there any benefit when it's set to "NO" ? 答 In normal production
最近公司项目要升级新版本,涉及到数据库升级中各种约束.亦是整理出如下脚本方便以后查询. --删除全文索引 DECLARE c0 cursor for SELECT'DROP FULLTEXT INDEX ON '+tab.name+';'FROM sys.fulltext_indexes idx JOIN sys.tables tab ON (idx.object_id = tab.object_id);open c0declare @c0 varchar(8000)fetch next fro
主键约束 SELECT tab.name AS [表名], idx.name AS [主键名称], col.name AS [主键列名] FROM sys.indexes idx JOIN sys.index_columns idxCol ON (idx.object_id = idxCol.object_id AND idx.index_id = idxCol.index_id AND idx.is_primary_k