在sql中怎么查看一个字符的ascii编码或Unicode编码: SELECT ASCII('a') AS [AsciiNum]--字符获取ASCII码 SELECT UNICODE(N'a') AS [UnicodeNum]--字符获取UNICODE编码 ) AS [返回类型为CHAR(1)]--ASCII码转字符类型CHAR(1) ) AS [返回类型为NVARCHAR(1)]--ASCII码转字符类型NVARCHAR(1) 结果如下: 还有一点,Unicode编码只编码第一个 ) ) ')
CREATE function [dbo].[Func_GetPY](@str nvarchar(4000))returns nvarchar(4000)asbegin set @str=RTRIM(@str) declare @word nchar(1),@PY nvarchar(4000) set @PY='' while len(@str)>0 begin --处理常用多音字 if len(@str)>=2 begin if left(@str,2)='重庆' begin set @PY
create function fun_getPY(@str nvarchar(4000)) returns nvarchar(4000) as begin declare @word nchar(1),@PY nvarchar(4000) set @PY=''while len(@str)>0 begin set @word=left(@str,1) --如果非汉字字符,返回原字符 set @PY=@PY+(case when unicode(@word) between 19968 and
IF OBJECT_ID('[fn_GetPinyin]') IS NOT NULL DROP FUNCTION [fn_GetPinyin] GO create function [dbo].[fn_GetPinyin](@words nvarchar(2000)) returns varchar(8000) as begin declare @word nchar(1) declare @pinyin varchar(8000) declare @i int declare @words_l
USE Test go IF OBJECT_ID('Fn_GetQuanPin','Fn') IS NOT NULL DROP FUNCTION fn_GetQuanPin go create function [dbo].[fn_GetQuanPin](@str varchar(100)) returns varchar(8000) as begin declare @re varchar(8000),@crs varchar(10) declare @strlen int select @s
create function fn_Getquanpin (@str varchar(100)) returns varchar(8000) as begin declare @re varchar(8000),@crs varchar(10) declare @strlen int select @strlen=len(@str),@re='' while @strlen>0 begin set @crs= substring(@str,@strlen,1) select @re= case