题意:给出考生id(分为乙级、甲级和顶级),取得的分数和所属学校。计算各个学校的所有考生的带权总成绩,以及各个学校的考生人数。最后对学校进行排名。

思路:本题的研究对象是学校,而不是考生!因此,建立学校的结构体Record,记录学校的校名,考生人数,排名,成绩等信息。利用map<校名,该学校对应的结构体>构造映射,然后在读入数据的时候就可以更新该学校的分数,学生人数。数据读入完毕后,根据计算规则求出各个学校的带权总成绩,再把结构体放到vector中排序一下,确定排名,就好了。

代码:

#include <cstdio>
#include <cctype>
#include <string>
#include <vector>
#include <map>
#include <iostream>
#include <algorithm>
#include <fstream>
using namespace std;

struct Record{
    int rank;
    string sch;
    int ScoreB,ScoreA,ScoreT,tws;
    int cnt;
    Record():rank(),sch(),ScoreA(),ScoreT(),tws(),cnt(){}
};
map<string,Record> mp;
vector<Record> vec;

bool cmp(Record a,Record b)
{
    if(a.tws!=b.tws) return a.tws>b.tws;
    else if(a.cnt!=b.cnt) return a.cnt<b.cnt;
    else return a.sch<b.sch;
}

int main()
{
    //ifstream cin("pat.txt");
    int n;
    cin>>n;
    string sch,id;
    int score;
    ;i<n;i++){
        cin>>id>>score>>sch;
        ;i<sch.size();i++)
            sch[i]=tolower(sch[i]);
        mp[sch].cnt++;
        mp[sch].sch=sch;
        ]=='B') mp[sch].ScoreB+=score;
        ]=='A') mp[sch].ScoreA+=score;
        else mp[sch].ScoreT+=score;
    }
    for(auto it:mp){
        Record rec=it.second;
        rec.tws=rec.ScoreB/1.5 + rec.ScoreA + rec.ScoreT*1.5;
        vec.push_back(rec);
    }
    sort(vec.begin(),vec.end(),cmp);
    ;i<vec.size();i++){
        ) vec[i].rank=;
        ].tws) vec[i].rank=vec[i-].rank;
        ;
    }
    cout<<vec.size()<<'\n';
    for(auto it:vec)
        cout<<it.rank<<' '<<it.sch<<' '<<it.tws<<' '<<it.cnt<<'\n';
    ;
}

1141 PAT Ranking of Institutions的更多相关文章

  1. 1141 PAT Ranking of Institutions[难]

    1141 PAT Ranking of Institutions (25 分) After each PAT, the PAT Center will announce the ranking of ...

  2. PAT 甲级 1141 PAT Ranking of Institutions

    https://pintia.cn/problem-sets/994805342720868352/problems/994805344222429184 After each PAT, the PA ...

  3. [PAT] 1141 PAT Ranking of Institutions(25 分)

    After each PAT, the PAT Center will announce the ranking of institutions based on their students' pe ...

  4. 1141 PAT Ranking of Institutions (25 分)

    After each PAT, the PAT Center will announce the ranking of institutions based on their students' pe ...

  5. PAT 1141 PAT Ranking of Institutions

    After each PAT, the PAT Center will announce the ranking of institutions based on their students' pe ...

  6. PAT_A1141#PAT Ranking of Institutions

    Source: PAT A1141 PAT Ranking of Institutions (25 分) Description: After each PAT, the PAT Center wil ...

  7. A1141. PAT Ranking of Institutions

    After each PAT, the PAT Center will announce the ranking of institutions based on their students' pe ...

  8. PAT A1141 PAT Ranking of Institutions (25 分)——排序,结构体初始化

    After each PAT, the PAT Center will announce the ranking of institutions based on their students' pe ...

  9. PAT Ranking (排名)

    PAT Ranking (排名) Programming Ability Test (PAT) is organized by the College of Computer Science and ...

随机推荐

  1. JSP导入包

    1. <%@page import="java.util.Date, mianBao.*, z_utils.*"%> 2. 3.

  2. Python 导出数据from Mysql

    环境 Anaconda3 Python 3.6, Window 64bit 目的 从MySQL数据库读取目标表数据,并处理 代码 # -*- coding: utf-8 -*- import pand ...

  3. mysql中的左连接右连接内连接

    一. 初始化SQL语句 /*join 建表语句*/ drop database if exists test; create database test; use test; /* 左表t1*/ dr ...

  4. Educational Codeforces Round 23D

    给n个数求每个子区间的价值,区间的价值是最大值-最小值 套路题= =,分别算最大值和最小值的贡献,用并查集维护,把相邻点连一条边,然后sort,求最大是按边价值(两个点的最大价值)小的排,求最小是按最 ...

  5. MailUtils 测试邮件是否发送

    import java.util.Properties; import javax.mail.Message; import javax.mail.Session; import javax.mail ...

  6. ndk+opencv安装+各种错误分析(新版安装,编译不需要Cygwin 和Sequoyah了)

    鼓捣了两三天,终于成功算跑通了一个简单的程序.下面说说具体的安装: 因为从同学那里拷过来的eclipse 就有adt cdt 的插件.所以这两个就不用再安装了.(需要的话自己安装) 具体说下安装过程: ...

  7. 【51nod-1596】搬货物

    现在有n个货物,第i个货物的重量是 2wi .每次搬的时候要求货物重量的总和是一个2的幂.问最少要搬几次能把所有的货物搬完. 样例解释: 1,1,2作为一组. 3,3作为一组. Input 单组测试数 ...

  8. NGUI 学习使用

    http://www.tasharen.com/forum/index.php?board=12.0

  9. BasicExcel的使用

    from:http://www.cnblogs.com/paullam/p/3705924.html   使用的平台:vs2013 控制台 创建时需要注意, 安全开发生命周期(SDL)检查 不能勾选( ...

  10. c printf打印格式

    关于小数点位数的举例:  <pre lang="c" escaped="true">#include <stdio.h> /* 当fah ...