CF Theatre Square
Theatre Square
2 seconds
64 megabytes
standard input
standard output
Theatre Square in the capital city of Berland has a rectangular shape with the size n × m meters. On the occasion of the city's anniversary, a decision was taken to pave the Square with square granite flagstones. Each flagstone is of the size a × a.
What is the least number of flagstones needed to pave the Square? It's allowed to cover the surface larger than the Theatre Square, but the Square has to be covered. It's not allowed to break the flagstones. The sides of flagstones should be parallel to the sides of the Square.
The input contains three positive integer numbers in the first line: n, m and a (1 ≤ n, m, a ≤ 109).
Write the needed number of flagstones.
6 6 4
4 易知,n/a即为需要多少块a,每一块a都能完全用完,又知,n%a若不零,那么还需要再添加一块,若为零则不需要。
所以总的块数即为(n / a + (n % a) ? 1 : )) * (m / a + (m % a) ? 1 : 0)
#include <iostream>
#include <cstdio>
using namespace std; int main(void)
{
long long n,m,a;
long long ans; scanf("%lld%lld%lld",&n,&m,&a);
ans = (n / a + ((n % a) ? : )) * (m / a + ((m % a) ? : ));
printf("%lld\n",ans); return ;
}
CF Theatre Square的更多相关文章
- codeforce 1A Theatre Square
A. Theatre Square Theatre Square in the capital city of Berland has a rectangular shape with the siz ...
- cf--------(div1)1A. Theatre Square
A. Theatre Square time limit per test 2 seconds memory limit per test 64 megabytes input standard in ...
- Theatre Square
http://codeforces.com/problemset/problem/1/A Theatre Square time limit per test 2 seconds memory lim ...
- CodeForces 1A Theatre Square
A - Theatre Square Time Limit:2000MS Memory Limit:65536KB 64bit IO Format:%I64d & %I64u ...
- A. Theatre Square(math)
A. Theatre Square time limit per test 1 second memory limit per test 256 megabytes input standard in ...
- Educational Codeforces Round 88 (Rated for Div. 2) B、New Theatre Square C、Mixing Water
题目链接:B.New Theatre Square 题意: 你要把所有"." 都变成"*",你可以有两个选择,第一种就是一次铺一个方块(1*1),第二种就是同一 ...
- [CF 612E]Square Root of Permutation
A permutation of length n is an array containing each integer from 1 to n exactly once. For example, ...
- CF 50E. Square Equation Roots
思路:这题的关键就是重复根只可能是整数. 这样先求出所有的根的数目,在减去重复的根. 代码如下: #include <iostream> #include <cstring> ...
- 1A Theatre Square
题目大意; 有一个广场,广场的大小是n*m, 有a*a的石砖,石砖铺广场可以比广场大,石砖不能切割.问最少需要多少个石砖. ===================================== ...
随机推荐
- JSF 2 multiple select listbox example
In JSF, <h:selectManyListbox /> tag is used to render a multiple select listbox – HTML select ...
- 通过源码学Java基础:InputStream、OutputStream、FileInputStream和FileOutputStream
1. InputStream 1.1 说明 InputStream是一个抽象类,具体来讲: This abstract class is the superclass of all classes r ...
- MD5验证工具:md5sum
linux 下 shell命令 ,制作md5码 也用于软件的md5校验 MD5算法常常被用来验证网络文件传输的完整性,防止文件被人篡改.MD5 全称是报文摘要算法(Message-Digest ...
- Elasticsearch和mysql数据同步(logstash)
1.版本介绍 Elasticsearch: https://www.elastic.co/products/elasticsearch 版本:2.4.0 Logstash: https://www ...
- MVC4学习过程记录
终于决定开始尝试Web开发,即是为了工作也是为了自己的兴趣,决定还是从MS的MVC4开始. 首先从Asp.Net MVC4入门指南这个系列开始学习(http://www.cnblogs.com/pow ...
- Posting data to a HttpHandler greater then ~29MB gives a 404 error
1down votefavorite 1 I am testing a HttpHandler that accepts XML. It works fine when a small amount ...
- Codeforces Gym 100650C The Game of Efil DFS
The Game of EfilTime Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hust.edu.cn/vjudge/contest/v ...
- Maven3.2创建webapp项目过程中问题以及解决方案
用maven组件来创建web项目,maven的好处一大堆,但是在创建项目的时候问题也很多,诸多不顺,网上找了很多资料,貌似都没能解决问题. 环境:jdk1.7.0_80,eclipse4.4,mave ...
- tomcat配置虚拟主机
在眼下,非常多server都是一台server对外能够訪问非常多个javaEE的项目,这样的实现方式就须要在tomcat里面配置虚拟主机了!以下就说说怎样配置虚拟主机: 找到tomcat的安装文件夹, ...
- 设计模式奠基石——UML关系转化为代码
1.继承关系(泛化关系) [说明]:继承关系是子类(派生类)继承父类(基类),或者子接口继承父接口的关系.即子类对象"is a" 父类对象,比方鸟是动物. [UML图]: 图解:A ...