914. X of a Kind in a Deck of Cards
In a deck of cards, each card has an integer written on it.
Return
true
if and only if you can chooseX >= 2
such that it is possible to split the entire deck into 1 or more groups of cards, where:
- Each group has exactly
X
cards.- All the cards in each group have the same integer
Example 1:
- Input: [1,2,3,4,4,3,2,1]
- Output: true
- Explanation: Possible partition [1,1],[2,2],[3,3],[4,4]
Example 2:
- Input: [1,1,1,2,2,2,3,3]
- Output: false
- Explanation: No possible partition.
Example 3:
- Input: [1]
- Output: false
- Explanation: No possible partition.
Example 4:
- Input: [1,1]
- Output: true
- Explanation: Possible partition [1,1]
Example 5:
- Input: [1,1,2,2,2,2]
- Output: true
- Explanation: Possible partition [1,1],[2,2],[2,2]
Note:
1 <= deck.length <= 10000
0 <= deck[i] < 10000
Approach #1: Array + GCD. [Java]
- class Solution {
- public boolean hasGroupsSizeX(int[] deck) {
- int res = 0;
- Map<Integer, Integer> map = new HashMap<>();
- for (int d : deck) map.put(d, map.getOrDefault(d, 0) + 1);
- for (int m : map.values()) res = gcd(res, m);
- return res > 1;
- }
- public int gcd(int x, int y) {
- return y > 0 ? gcd(y, x % y) : x;
- }
- }
Reference:
https://leetcode.com/problems/x-of-a-kind-in-a-deck-of-cards/discuss/175845/C%2B%2BJavaPython-Greatest-Common-Divisor
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