代码

import pandas as pd
import numpy as np left=pd.DataFrame({'key':['K0','K1','K2','K3'],
'A':['A0','A1','A3','A3'],
'B':['B0','B1','B2','B3'],}) right=pd.DataFrame({'key':['K0','K1','K2','K3'],
'C':['C0','C1','C3','C3'],
'D':['D0','D1','D2','D3'],}) print('-1-')
print(left)
print(right) res = pd.merge(left,right,on='key')
print(res) left=pd.DataFrame({'key1':['K0','K0','K1','K2'],
'key2':['K0','K1','K0','K1'],
'A':['A0','A1','A3','A3'],
'B':['B0','B1','B2','B3'],}) right=pd.DataFrame({'key1':['K0','K1','K1','K2'],
'key2':['K0','K0','K0','K0'],
'C':['C0','C1','C3','C3'],
'D':['D0','D1','D2','D3'],}) print('-2-')
res = pd.merge(left,right,on=['key1','key2'])
print(left)
print(right)
print(res) # default
print('-3-')
res = pd.merge(left,right,on=['key1','key2'],how='inner')
print(left)
print(right)
print(res) print('-4-')
res = pd.merge(left,right,on=['key1','key2'],how='outer')
print(left)
print(right)
print(res) print('-5-')
res = pd.merge(left,right,on=['key1','key2'],how='right')
print(left)
print(right)
print(res) print('-6-')
res = pd.merge(left,right,on=['key1','key2'],how='left')
print(left)
print(right)
print(res) print('-7-')
df1 = pd.DataFrame({'col1':[0,1],'col_left':['a','b']})
df2 = pd.DataFrame({'col1':[1,2,2],'col_right':[2,2,2]})
print(df1)
print(df2)
res = pd.merge(df1,df2,on='col1',how='outer',indicator=True)
print(res) res = pd.merge(df1,df2,on='col1',how='outer',indicator=True)
print(res) res = pd.merge(df1,df2,on='col1',how='outer',indicator='indicator_column')
print(res) df1 = pd.DataFrame({'A':['A0','A1','A2'],
'B':['B0','B1','B2']},
index=['K0','K1','K2']) df2 = pd.DataFrame({'C':['C0','C1','C2'],
'D':['D0','D1','D2']},
index=['K0','K1','K2']) print(df1)
print(df2) print('-8-')
res=pd.merge(left,right,left_index=True,right_index=True,how='outer')
print(res) print('-9-')
res=pd.merge(left,right,left_index=True,right_index=True,how='inner')
print(res) boys = pd.DataFrame({'k':['K0','K1','K2'],'age':[1,2,3]})
girls = pd.DataFrame({'k':['K0','K0','K3'],'age':[4,5,6]}) print('-10-')
print(boys)
print(girls) res = pd.merge(boys, girls, on='k', suffixes=['_boy','_girl'],how='inner')
print(res) res = pd.merge(boys, girls, on='k', suffixes=['_boy','_girl'],how='outer')
print(res)

  

输出

-1-
key A B
0 K0 A0 B0
1 K1 A1 B1
2 K2 A3 B2
3 K3 A3 B3
key C D
0 K0 C0 D0
1 K1 C1 D1
2 K2 C3 D2
3 K3 C3 D3
key A B C D
0 K0 A0 B0 C0 D0
1 K1 A1 B1 C1 D1
2 K2 A3 B2 C3 D2
3 K3 A3 B3 C3 D3
-2-
key1 key2 A B
0 K0 K0 A0 B0
1 K0 K1 A1 B1
2 K1 K0 A3 B2
3 K2 K1 A3 B3
key1 key2 C D
0 K0 K0 C0 D0
1 K1 K0 C1 D1
2 K1 K0 C3 D2
3 K2 K0 C3 D3
key1 key2 A B C D
0 K0 K0 A0 B0 C0 D0
1 K1 K0 A3 B2 C1 D1
2 K1 K0 A3 B2 C3 D2
-3-
key1 key2 A B
0 K0 K0 A0 B0
1 K0 K1 A1 B1
2 K1 K0 A3 B2
3 K2 K1 A3 B3
key1 key2 C D
0 K0 K0 C0 D0
1 K1 K0 C1 D1
2 K1 K0 C3 D2
3 K2 K0 C3 D3
key1 key2 A B C D
0 K0 K0 A0 B0 C0 D0
1 K1 K0 A3 B2 C1 D1
2 K1 K0 A3 B2 C3 D2
-4-
key1 key2 A B
0 K0 K0 A0 B0
1 K0 K1 A1 B1
2 K1 K0 A3 B2
3 K2 K1 A3 B3
key1 key2 C D
0 K0 K0 C0 D0
1 K1 K0 C1 D1
2 K1 K0 C3 D2
3 K2 K0 C3 D3
key1 key2 A B C D
0 K0 K0 A0 B0 C0 D0
1 K0 K1 A1 B1 NaN NaN
2 K1 K0 A3 B2 C1 D1
3 K1 K0 A3 B2 C3 D2
4 K2 K1 A3 B3 NaN NaN
5 K2 K0 NaN NaN C3 D3
-5-
key1 key2 A B
0 K0 K0 A0 B0
1 K0 K1 A1 B1
2 K1 K0 A3 B2
3 K2 K1 A3 B3
key1 key2 C D
0 K0 K0 C0 D0
1 K1 K0 C1 D1
2 K1 K0 C3 D2
3 K2 K0 C3 D3
key1 key2 A B C D
0 K0 K0 A0 B0 C0 D0
1 K1 K0 A3 B2 C1 D1
2 K1 K0 A3 B2 C3 D2
3 K2 K0 NaN NaN C3 D3
-6-
key1 key2 A B
0 K0 K0 A0 B0
1 K0 K1 A1 B1
2 K1 K0 A3 B2
3 K2 K1 A3 B3
key1 key2 C D
0 K0 K0 C0 D0
1 K1 K0 C1 D1
2 K1 K0 C3 D2
3 K2 K0 C3 D3
key1 key2 A B C D
0 K0 K0 A0 B0 C0 D0
1 K0 K1 A1 B1 NaN NaN
2 K1 K0 A3 B2 C1 D1
3 K1 K0 A3 B2 C3 D2
4 K2 K1 A3 B3 NaN NaN
-7-
col1 col_left
0 0 a
1 1 b
col1 col_right
0 1 2
1 2 2
2 2 2
col1 col_left col_right _merge
0 0 a NaN left_only
1 1 b 2.0 both
2 2 NaN 2.0 right_only
3 2 NaN 2.0 right_only
col1 col_left col_right _merge
0 0 a NaN left_only
1 1 b 2.0 both
2 2 NaN 2.0 right_only
3 2 NaN 2.0 right_only
col1 col_left col_right indicator_column
0 0 a NaN left_only
1 1 b 2.0 both
2 2 NaN 2.0 right_only
3 2 NaN 2.0 right_only
A B
K0 A0 B0
K1 A1 B1
K2 A2 B2
C D
K0 C0 D0
K1 C1 D1
K2 C2 D2
-8-
key1_x key2_x A B key1_y key2_y C D
0 K0 K0 A0 B0 K0 K0 C0 D0
1 K0 K1 A1 B1 K1 K0 C1 D1
2 K1 K0 A3 B2 K1 K0 C3 D2
3 K2 K1 A3 B3 K2 K0 C3 D3
-9-
key1_x key2_x A B key1_y key2_y C D
0 K0 K0 A0 B0 K0 K0 C0 D0
1 K0 K1 A1 B1 K1 K0 C1 D1
2 K1 K0 A3 B2 K1 K0 C3 D2
3 K2 K1 A3 B3 K2 K0 C3 D3
-10-
k age
0 K0 1
1 K1 2
2 K2 3
k age
0 K0 4
1 K0 5
2 K3 6
k age_boy age_girl
0 K0 1 4
1 K0 1 5
k age_boy age_girl
0 K0 1.0 4.0
1 K0 1.0 5.0
2 K1 2.0 NaN
3 K2 3.0 NaN
4 K3 NaN 6.0

  

17-numpy笔记-莫烦pandas-5的更多相关文章

  1. 16-numpy笔记-莫烦pandas-4

    代码 import pandas as pd import numpy as np dates = pd.date_range('20130101', periods=6) df=pd.DataFra ...

  2. 15-numpy笔记-莫烦pandas-3

    代码 import pandas as pd import numpy as np dates = pd.date_range('20130101', periods=6) df=pd.DataFra ...

  3. 14-numpy笔记-莫烦pandas-2

    代码 import pandas as pd import numpy as np dates = pd.date_range('20130101', periods=6) df=pd.DataFra ...

  4. 18-numpy笔记-莫烦pandas-6-plot显示

    代码 import pandas as pd import numpy as np import matplotlib.pyplot as plt data = pd.Series(np.random ...

  5. 13-numpy笔记-莫烦pandas-1

    代码 import pandas as pd import numpy as np s = pd.Series([1,3,6,np.nan, 44,1]) print('-1-') print(s) ...

  6. 11-numpy笔记-莫烦基础操作1

    代码 import numpy as np array = np.array([[1,2,5],[3,4,6]]) print('-1-') print('数组维度', array.ndim) pri ...

  7. 12-numpy笔记-莫烦基本操作2

    代码 import numpy as np A = np.arange(3,15) print('-1-') print(A) print('-2-') print(A[3]) A = np.aran ...

  8. Python pandas & numpy 笔记

    记性不好,多记录些常用的东西,真·持续更新中::先列出一些常用的网址: 参考了的 莫烦python pandas DOC numpy DOC matplotlib 常用 习惯上我们如此导入: impo ...

  9. tensorflow学习笔记-bili莫烦

    bilibili莫烦tensorflow视频教程学习笔记 1.初次使用Tensorflow实现一元线性回归 # 屏蔽警告 import os os.environ[' import numpy as ...

随机推荐

  1. BZOJ4027/LG4107 「HEOI2015」兔子与樱花 树形DP+贪心

    问题描述 LG4107 题解 首先,我们可以直接令结点 \(x\) 的权值为 \(c[x]+son_x\) ,发现将 \(x,y\) 合并,相当于增加 \(c[x]+c[y]-1\) 的重量. 容易想 ...

  2. echarts使用------地图生成----省市地图的生成及其他相关细节调整

    为使用多种业务场景,百度echarts地图示例只有中国地图,那么在使用省市地图的时候,就需要我们使用省市的地图数据了 以下为陕西西安市的地图示例: 此页面引用echarts的js:http://ech ...

  3. Python高级应用程序设计任务期末作业

    Python高级应用程序设计任务要求 用Python实现一个面向主题的网络爬虫程序,并完成以下内容:(注:每人一题,主题内容自选,所有设计内容与源代码需提交到博客园平台) 一.主题式网络爬虫设计方案( ...

  4. OpenDaylight开发hello-world项目之开发环境搭建

    OpenDaylight开发hello-world项目之开发环境搭建 OpenDaylight开发hello-world项目之开发工具安装 OpenDaylight开发hello-world项目之代码 ...

  5. 解决Warning: Permanently added ' 192.168.1.230'(RSA) to the list of known hosts.

    前提 当我在刚安装的Red Hat Linux5.x系统中进行ssh 192.168.1.230 远程时,出现以下错误: Warning: Permanently added ' 192.168.1. ...

  6. 'GL_EXT_shader_framebuffer_fetch' : extension is not supported

    在使用安卓模拟器加载Flutter应用时, 提示'GL_EXT_shader_framebuffer_fetch' : extension is not supported: D/skia (1404 ...

  7. oracle简单查询单词

    单词 释义 select 查询 from 从... where 条件查询 as 别名 not 取反 and 和 or 或者 between...and... 范围取值,包含边界 like 模糊查询 e ...

  8. poj-3404 Bridge over a rough river Ad Hoc

    Bridge over a rough river POJ - 3404 Bridge over a rough river Time Limit: 1000MS   Memory Limit: 65 ...

  9. maven项目配置使用jdk1.8进行编译的插件

    在使用Maven插件编译Maven项目的时候报了这样一个错:[Java source1.5不支持diamond运算符,请使用source 7或更高版本以启用diamond运算符],这里记录下出现这个错 ...

  10. 通信与io:io是通信的端点机制

    通信与io:io是通信的端点机制: io可以是连接到文件系统的: 也可以是连接到对等端点的: