Excel can sort records according to any column. Now you are supposed to imitate this function.

Input Specification:

Each input file contains one test case. For each case, the first line contains two integers N (≤10

​5

​​ ) and C, where N is the number of records and C is the column that you are supposed to sort the records with. Then N lines follow, each contains a record of a student. A student's record consists of his or her distinct ID (a 6-digit number), name (a string with no more than 8 characters without space), and grade (an integer between 0 and 100, inclusive).

Output Specification:

For each test case, output the sorting result in N lines. That is, if C = 1 then the records must be sorted in increasing order according to ID's; if C = 2 then the records must be sorted in non-decreasing order according to names; and if C = 3 then the records must be sorted in non-decreasing order according to grades. If there are several students who have the same name or grade, they must be sorted according to their ID's in increasing order.

Sample Input 1:

3 1

000007 James 85

000010 Amy 90

000001 Zoe 60

Sample Output 1:

000001 Zoe 60

000007 James 85

000010 Amy 90

Sample Input 2:

4 2

000007 James 85

000010 Amy 90

000001 Zoe 60

000002 James 98

Sample Output 2:

000010 Amy 90

000002 James 98

000007 James 85

000001 Zoe 60

Sample Input 3:

4 3

000007 James 85

000010 Amy 90

000001 Zoe 60

000002 James 90

Sample Output 3:

000001 Zoe 60

000007 James 85

000002 James 90

000010 Amy 90

开始技术总结:

  • 主要就是cmp函数的编写,可以通过编写三个cmp函数来分别对应于三种排序的情况,然后根据输入得到的C值来选择哪个cmp函数应用,我使用的是通过定义一个全局变量C,然后编写一个cmp函数,在cmp函数里面区别三种排序情况。注意如果要使用C来判断,必须把C定义为全局变量。这个函数的参考代码如下:
bool cmp(Student a, Student b) {
if (C == 1) {
return a.id < b.id;
}
else if (C == 2) {
if (strcmp(a.name, b.name) == 0) {
return a.id < b.id;
}
else {
return strcmp(a.name, b.name) < 0;
} }
else if (C == 3) {
if (a.grade == b.grade) {
return a.id < b.id;
}
else {
return a.grade < b.grade;
}
}
}

所有部分的代码:

//在VS2017上编写,通过PAT测试满分25
#define _CRT_SECURE_NO_WARNINGS
#include <cstdio>
#include <cstring>
#include <cstdlib>
#include <algorithm>
using namespace std; struct Student {
int id;
char name[10];
int grade;
}stu[100010]; int C;//全局变量用来在cmp函数使用,判定排序方式 bool cmp(Student a, Student b) {
if (C == 1) {
return a.id < b.id;
}
else if (C == 2) {
if (strcmp(a.name, b.name) == 0) {
return a.id < b.id;
}
else {
return strcmp(a.name, b.name) < 0;
} }
else if (C == 3) {
if (a.grade == b.grade) {
return a.id < b.id;
}
else {
return a.grade < b.grade;
}
}
}
int main() {
int N;//分别记录人数N
scanf("%d%d", &N, &C);
for (int i = 0; i < N; i++) {
scanf("%d%s%d", &stu[i].id, stu[i].name, &stu[i].grade);
}
sort(stu, stu + N, cmp);
for (int i = 0; i < N; i++) {
printf("%06d %s %d\n", stu[i].id, stu[i].name, stu[i].grade);
} system("pause");
return 0;
}

PATA1028 List Sorting的更多相关文章

  1. HDU Cow Sorting (树状数组)

    题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2838 Cow Sorting Problem Description Sherlock's N (1  ...

  2. 1306. Sorting Algorithm 2016 12 30

    1306. Sorting Algorithm Constraints Time Limit: 1 secs, Memory Limit: 32 MB Description One of the f ...

  3. 算法:POJ1007 DNA sorting

    这题比较简单,重点应该在如何减少循环次数. package practice; import java.io.BufferedInputStream; import java.util.Map; im ...

  4. U3D sorting layer, sort order, order in layer, layer深入辨析

    1,layer是对游戏中所有物体的分类别划分,如UIlayer, waterlayer, 3DModelLayer, smallAssetsLayer, effectLayer等.将不同类的物体划分到 ...

  5. WebGrid with filtering, paging and sorting 【转】

    WebGrid with filtering, paging and sorting by Jose M. Aguilar on April 24, 2012 in Web Development A ...

  6. ASP.NET MVC WebGrid – Performing true AJAX pagination and sorting 【转】

    ASP.NET MVC WebGrid – Performing true AJAX pagination and sorting FEBRUARY 27, 2012 14 COMMENTS WebG ...

  7. poj 1007:DNA Sorting(水题,字符串逆序数排序)

    DNA Sorting Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 80832   Accepted: 32533 Des ...

  8. ural 1252. Sorting the Tombstones

    1252. Sorting the Tombstones Time limit: 1.0 secondMemory limit: 64 MB There is time to throw stones ...

  9. CF#335 Sorting Railway Cars

    Sorting Railway Cars time limit per test 2 seconds memory limit per test 256 megabytes input standar ...

随机推荐

  1. 『Norma 分治』

    Norma Description Input Format 第1行,一个整数N: 第2~n+1行,每行一个整数表示序列a. Output Format 输出答案对10^9取模后的结果. Sample ...

  2. WPF 精修篇 倾斜 SkewTransform

    原文:WPF 精修篇 倾斜 SkewTransform 倾斜 SkewTransform AngleX 倾斜X角度 AngleY 倾斜Y角度 CenterX CenterY 中心点 <Stack ...

  3. window.postMessage()实现跨域消息传递

    window.postMessage() 方法可以安全地实现跨源通信.通常,对于两个不同页面的脚本,只有当执行它们的页面位于具有相同的协议(通常为https), 端口号(443为https的默认值), ...

  4. Javascript 日历插件

    1. The Coolest Calendar 界面非常漂亮的一款日期选择插件,有详细的使用文档,最新版本 1.5. 点击下载    查看示例 2. DatePicker 这款日期插件支持单选.多选和 ...

  5. php中,5行代码实现无限级分类

    <?php /** * 此方法由@Tonton 提供 * http://my.oschina.net/u/918697 * @date 2012-12-12 */function genTree ...

  6. VirtualBox安装Ubuntu-18.04-Server笔记

    准备 安装'Windows Terminal' 安装WSL 安装VirtualBox 安装 虚拟磁盘映像文件选择创建在SSD(如果有) 选择openssh,公钥从GitHub获取,前提是GitHub已 ...

  7. 一般处理程序ashx输出XML

    首先构建自己的xmldocument,方式很多例如: XmlDocument xmldoc = new XmlDocument(); XmlDeclaration xmldecl = xmldoc.C ...

  8. 记录Mac OS下编译Thrift库

    方法一:brew管理工具安装Homebrew是Mac开发包管理工具,类似于Linux的apt-get之类的,实它相当于开发软件界的 Appstore.借助该管理工具,可以自动化地安装软件包,它会自动安 ...

  9. 面试官:优化代码中大量的if/else,你有什么方案?

    一个快速迭代的项目,时间久了之后,代码中可能会充斥着大量的if/else,嵌套6.7层,一个函数几百行,简!直!看!死!人! 这个无限循环嵌套,只是总循环的一部分...我已经绕晕在黄桷湾立交 仔细数了 ...

  10. Kafka Manager几个指标含义

    记忆早退 Brokers Spread:看作broker使用率,如kafka集群9个broker,某topic有7个partition,则broker spread: 7 / 9 = 77% Brok ...