Heapify

Given an integer array, heapify it into a min-heap array.

For a heap array A, A[0] is the root of heap, and for each A[i], A[i * 2 + 1] is the left child of A[i] and A[i * 2 + 2] is the right child of A[i].

 public class Solution {
     /**
      * @param A: Given an integer array
      * @return: void
      */
 
     public void heapify(int[] array) {
         int heapSize = array.length;
         for (int i = heapSize /  - ; i >= ; i--) {
             minHeapify(array, i, array.length);
         }
     }
 
     /// MaxHeapify is to build the max heap from the 'position'
     public void minHeapify(int[] array, int position, int heapSize)
     {
         int left = left(position);
         int right = right(position);
         int minPosition = position;
 
         if (left < heapSize && array[left] < array[position]) {
             minPosition = left;
         }
 
         if (right < heapSize && array[right] < array[minPosition]) {
             minPosition = right;
         }
 
         if (position != minPosition) {
             swap(position, minPosition, array);
             minHeapify(array, minPosition, heapSize);
         }
     }
 
     public void swap(int i, int j, int[] A) {
         int temp = A[i];
         A[i] = A[j];
         A[j] = temp;
     }
 
     /// return the left child position
     public int left(int i)
     {
         return  * i + ;
     }
     /// return the right child position
     public int right(int i)
     {
         return  * i + ;
     }
 }