CTF杂项之BubbleBabble加密算法
这题很坑,刚开始我拿到就分析不出来了(/无奈),关键是不知道是什么加密算法,后来看题目描述的bubble,猜测是bubble
这种算法(听都没听说过。。。)
上图
这串编码
xinik-samak-luvag-hutaf-fysil-notok-mepek-vanyh-zipef-hilok-detok-damif-cusol-fezyx
百度也没找到哪里有,后面看到有大佬写的writeup,于是就借鉴一下下,233
这里是这种加密算法的解释(为了方便大家,加密算法我复制到文末),链接传送:http://wiki.yak.net/589/Bubble_Babble_Encoding.txt
附上解题代码,楼主用的python3.7,另外bubblepy这个库需要导入一下,网址附上https://pypi.python.org/pypi/bubblepy/
from bubblepy import BubbleBabble
#导入包bubblepy
str='xinik-samak-luvag-hutaf-fysil-notok-mepek-vanyh-zipef-hilok-detok-damif-cusol-fezyx'
#str是待解密字符
Str=BubbleBabble()
print(Str.decode(str))
最后,get Flag
这里是BubbleBabble加密算法
authors==Huima
status==Experimental
title==The Bubble Babble Binary Data Encoding
number==Internet Draft
date==April 2000
Network Working Group Antti Huima
Internet Draft SSH Communications Security
draft-huima-babble-01.txt April 2000 The Bubble Babble Binary Data Encoding Status of this Memo This memo provides information for the Internet community. It does
not specify an Internet standard of any kind. Distribution of this
memo is unlimited. Copyright Notice Copyright (C) The Internet Society (2000). All Rights Reserved. Abstract This document describes a new encoding method for binary data that is
intended to be used in conjunction with fingerprints of
security-critical data. 1. Introduction Hash values of certificates and public keys, known as fingerprints
or thumbprints, are commonly used for verifying that a received
security-critical datum has been received correctly. Fingerprints
are binary data and typically encoded as series of hexadecimal
digits. However, long strings hexadecimal digits are difficult for
comprehend and cumbersome to translate reliably e.g. over phone. The Bubble Babble Encoding encodes arbitrary binary data into
pseudowords that are more natural to humans and that can be
pronounced relatively easily. The encoding consumes asymptotically
the same amount of space as an encoding of the form HH HH HH HH ... where `H' is a hexadecimal digit, i.e. carries 16 bits in six
characters. However, the Bubble Babble Encoding includes a
checksumming method that can sometimes detect invalid encodings.
The method does not increase the length of the encoded data. 2. Encoding Below, _|X|_ denotes the largest integer not greater than X. Let the data to be encoded be D[1] ... D[K] where K is the length
of the data in bytes; every D[i] is an integer from 0 to 2^8 - 1.
First define the checksum series C[1] ... C[_|K/2|_] where C[1] = 1 C[n] = (C[n - 1] * 5 + (D[n * 2 - 3] * 7 + D[n * 2 - 2])) mod 36 The data is then transformed into _|K/2|_ `tuples'
T[1] ... T[_|K/2|_] and one `partial tuple' P so that T[i] = <a, b, c, d, e> where a = (((D[i * 2 - 3] >> 6) & 3) + C[i]) mod 6
b = (D[i * 2 - 3] >> 2) & 15
c = (((D[i * 2 - 3]) & 3) + _|C[i] / 6|_) mod 6
d = (D[i * 2 - 2] >> 4) & 15; and
e = (D[i * 2 - 3]) & 15. The partial tuple P is P = <a, b, c> where if K is even then a = (C[i]) mod 6
b = 16
c = _|C[i] / 6|_ but if it is odd then a = (((D[K] >> 6) & 3) + C[i]) mod 6
b = (D[K] >> 2) & 15
c = (((D[K]) & 3) + _|C[i] / 6|_) mod 6 The `vowel table' V maps integers between 0 and 5 to vowels as 0 - a
1 - e
2 - i
3 - o
4 - u
5 - y and the `consonant table' C maps integers between 0 and 16 to
consonants as 0 - b
1 - c
2 - d
3 - f
4 - g
5 - h
6 - k
7 - l
8 - m
9 - n
10 - p
11 - r
12 - s
13 - t
14 - v
15 - z
16 - x The encoding E(T) of a tuple T = <a, b, c, d, e> is then the string V[a] C[b] V[c] C[d] `-' C[e] where there are five characters, and `-' is the literal hyphen. The encoding E(P) of a partial tuple P = <a, b, c> is the
three-character string V[a] C[b] V[c]. Finally, the encoding of the whole input data D is obtained as `x' E(T[1]) E(T[2]) ... E(T[_|K/2|_]) E(P) `x' where `x's are literal characters. 3. Decoding Decoding is obviously the process of encoding reversed. To check the checksums, when a tuple <a, b, c, d, e> or partial
tuple <a, b, c> has been recovered from the encoded string, an
implementation should check that ((a - C[i]) mod 6) < 4 and that
((c - C[i]) mod 6) < 4. Otherwise the encoded string is not a valid
encoding of any data and should be rejected. 4. Checksum Strength Every vowel in an encoded string carries 0.58 bits redundancy; thus
the length of the `checksum' in the encoding of an input string
containing K bytes is 0.58 * K bits. 5. Test Vectors ASCII Input Encoding
------------------------------------------------------------------
`' (empty string) `xexax'
`1234567890' `xesef-disof-gytuf-katof-movif-baxux'
`Pineapple' `xigak-nyryk-humil-bosek-sonax' 6. Author's Address Antti Huima
SSH Communications Security, Ltd.
[XXX] 7. Full Copyright Statement Copyright (C) The Internet Society (2000). All Rights Reserved. This document and translations of it may be copied and furnished to
others, and derivative works that comment on or otherwise explain
it or assist in its implementation may be prepared, copied,
published and distributed, in whole or in part, without restriction
of any kind, provided that the above copyright notice and this
paragraph are included on all such copies and derivative works.
However, this document itself may not be modified in any way, such
as by removing the copyright notice or references to the Internet
Society or other Internet organizations, except as needed for the
purpose of developing Internet standards in which case the
procedures for copyrights defined in the Internet Standards process
must be followed, or as required to translate it into languages
other than English. The limited permissions granted above are perpetual and will not be
revoked by the Internet Society or its successors or assigns. This document and the information contained herein is provided on
an "AS IS" basis and THE INTERNET SOCIETY AND THE INTERNET
ENGINEERING TASK FORCE DISCLAIMS ALL WARRANTIES, EXPRESS OR
IMPLIED, INCLUDING BUT NOT LIMITED TO ANY WARRANTY THAT THE USE OF
THE INFORMATION HEREIN WILL NOT INFRINGE ANY RIGHTS OR ANY IMPLIED
WARRANTIES OF MERCHANTABILITY OR FITNESS FOR A PARTICULAR PURPOSE.
CTF杂项之BubbleBabble加密算法的更多相关文章
- CTF杂项思路工具分享————2019/5/30
分享碰到的一些奇奇怪怪的杂项解题方式: 键盘坐标密码: 题目给出一段字符串:11 21 31 18 27 33 34 对照上面的表格,就可以很清晰的看出来密文为:QAZIJCV 猪圈码: 题目为: 一 ...
- CTF杂项之音频隐写
题目来自bugku 二话不说,直接上图 由题目可以看出,这题需要用到一个KEY,加上又是一段音频,很容易联想到一个著名的音频隐写解密软件Mp3stego 直接上工具 ok,成功Get Flag
- 【CTF杂项】常见文件文件头文件尾格式总结及各类文件头
文件头文件尾总结 JPEG (jpg), 文件头:FFD8FF 文件尾:FF D9PNG (png), 文件头:89504E47 文件尾:AE 42 60 82GIF (gif), 文件头:47494 ...
- CTF杂项题解题思路
下载压缩包解压 如果是图片就先查看图片信息 没有有用信息查看图片看是否是一个图片 如果不是图片就将文件进行还原 从还原文件中查找有用信息 例:这是一张单纯的图片 http://123.206.87.2 ...
- ctf杂项之easy_nbt
下载附件查看 除了几个文件之外,没有思路 搜索nbt可知,可以使用nbtexplorer工具 果断下载,然后打开题目下载的目录 crrl+f搜索flag 猜测kflag{Do_u_kN0w_nbt?} ...
- BugKu CTF(杂项篇MISC)-贝斯手
打开是以下内容 先看一下给了哪些提示 1.介绍 没了?不,拉到最底下还有 2.女神剧照 密码我4不会告诉你的,除非你知道我的女神是哪一年出生的(细品) 大致已经明白了,四位数密码,出生年份 文件是以下 ...
- bugku ctf 杂项 旋转跳跃 (熟悉的声音中貌似又隐藏着啥,key:syclovergeek)
做这道题之前先给出工具 MP3Stego 下载地址 链接:https://pan.baidu.com/s/1W2mmGJcrm570EdJ6o7jD7g 提取码:1h1b 题目下载加压后 是一个 ...
- CTF 介绍及杂项
CTF(Capture The Flag)中文一般译作夺旗赛,在网络安全领域中指的是网络安全技术人员之间进行技术竞技的一种比赛形式.CTF起源于1996年DEFCON全球黑客大会,以代替之前黑客们通过 ...
- 实验吧CTF练习题---安全杂项---异性相吸解析
---恢复内容开始--- 实验吧安全杂项之异性相吸 地址:http://www.shiyanbar.com/ctf/1855 flag值:nctf{xor_xor_xor_biubiubiu} ...
随机推荐
- CSS引入本地字体与在线字体
有些时候为了强调某些文字,需要使用一些比较特别的字体,CSS中现在也可以比较方便的引入字体了,如下: /* 定义字体 */ @font-face{ font-family: Arista2; src: ...
- geodocker-geomesa安装指南
最近研究geopyspark原本以为大数据研究能告一段落,因为... 开玩笑的,还要一起建设社会主义呢!! 背景 geotrellis作为一个处理遥感数据的框架,对于遥感数据支 ...
- Chrome启动后打开第一个网页很慢的解决方案
Chrome启动后打开第一个网页很慢的解决方案 Chrome/Chromium以速度快著称,最近每当打开chrome的时候,打开第一个页面都非常慢,往往需要数十秒的时间,经分 析,应该是卡在了域名解析 ...
- Redis内存模型(2):存储细节
1. 概述 先看一下执行set hellow world时,所涉及的数据模型: (1)dictEntry:Redis是Key-Value数据库,因此对每个键值对都会有一个dictEntry,里面存储了 ...
- linux 进程概念
1,pcb:进程控制块结构体:/usr/src/linux-headers-4.15.0-29/include/linux/sched.h 进程id:系统中每个进程有唯一的id,在c语言中用pid_t ...
- SQLServer之修改用户自定义数据库用户
修改用户自定义数据库用户注意事项 默认架构将是服务器为此数据库用户解析对象名时将搜索的第一个架构. 除非另外指定,否则默认架构将是此数据库用户创建的对象所属的架构. 如果用户具有默认架构,则将使用默认 ...
- Java泛型的重要目的:别让猫别站在狗队里
<Java编程思想>第四版足足用了75页来讲泛型——厚厚的一沓内容,很容易让人头大——但其实根本不用这么多,只需要一句话:我是一个泛型队列,狗可以站进来,猫也可以站进来,但最好不要既站猫, ...
- Jenkins高级用法 - Jenkinsfile 介绍及实战经验
系列目录 1.Jenkins 安装 2.Jenkins 集群 3.Jenkins 持续集成 - ASP.NET Core 持续集成(Docker&自由风格&Jenkinsfile) 4 ...
- Python--开发简单爬虫
简单爬虫架构 动态运行流程 URL管理器的作用 URL管理器的3种实现方式 网页下载器的作用 Python网页下载器的种类 urllib2下载网页的3种方法 网页解析器的作用 Python的几种网页解 ...
- AsyncTask原理
一.概述 Android开发中我们通常让主线程负责前台用户界面的绘制以及响应用户的操作,让工作者线程在后台执行一些比较耗时的任务.Android中的工作者线程主要有AsyncTask.IntentSe ...