LeetCode OJ--Merge Sorted Array *

http://oj.leetcode.com/problems/merge-sorted-array/

两个有序数组A和B的归并排序，将结果存到A中。因为已知两数组长度且A的数组足够大，所以倒着处理，如果正着的话，会有好多往后挪的操作。

#include <iostream>
using namespace std;
 
class Solution {
public:
    void merge(int A[], int m, int B[], int n) {
        if(m<|| n<)
            return;
        if(n == )
            return ;
        if(m ==)
        {
            for(int i = ;i<n;i++)
                A[i] = B[i];
        }
        int a_pointer = m -;
        int b_pointer = n-;
        int c_pointer = m+n-;
        while(a_pointer!=- && b_pointer!= -)
        {
            while(a_pointer != - &&b_pointer!= - && A[a_pointer]>=B[b_pointer])
            {
                A[c_pointer] = A[a_pointer];
                c_pointer--;
                a_pointer--;
            }
            while(a_pointer!= - && b_pointer != - &&A[a_pointer]<B[b_pointer] )
            {
                A[c_pointer] = B[b_pointer];
                c_pointer--;
                b_pointer--;
            }
        }
        if(a_pointer == - && c_pointer!= -)
            for(int i = ;i<=c_pointer;i++)
                A[i] = B[i];
        for(int i = ;i<=m+n-;i++)
            cout<<A[i]<<endl;
    }
};
 
int main()
{
    Solution myS;
    int A[] = {,,,,,,};
    int B[] = {,,,,,};
    myS.merge(A,,B,);
    return ;
}