Given a string s, find the longest palindromic subsequence's length in s. You may assume that the maximum length of s is 1000.

Example 1:
Input:

  1. "bbbab"

Output:

  1. 4

One possible longest palindromic subsequence is "bbbb".

Example 2:
Input:

  1. "cbbd"

Output:

  1. 2

One possible longest palindromic subsequence is "bb".

这是一道典型的dp题,用dp[][]来存储i,j两个pointer指向的string的一个char, 分别按照相等和不相等来处理即可。

  1. class Solution {
  2. public int longestPalindromeSubseq(String s) {
  3. int length = s.length();
  4. int[][] dp = new int[length][length];
  5. for (int i = ; i < length; i++) {
  6. dp[i][i] = ;
  7. }
  8. for (int subLength = ; subLength <= length; subLength++) {
  9. for (int i = ; i + subLength <= length; i++) {
  10. int j = subLength + i - ;
  11. if (s.charAt(i) == s.charAt(j)) {
  12. dp[i][j] = dp[i + ][j - ] + ;
  13. } else {
  14. dp[i][j] = Math.max(dp[i + ][j], dp[i][j - ]);
  15. }
  16. }
  17. }
  18. return dp[][length - ];
  19. }
  20. }

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