#include <stdio.h>
#include <malloc.h>
#define MAX_STACK 10 int COUNT = ;
// define the node of stack
typedef struct node {
int data;
node *next;
}*Snode; // define the stack
typedef struct Stack{
Snode top;
Snode bottom;
}*NewStack; void creatStack(NewStack s) {
// allocate stack
// allocate the elements of stack s->top = (Snode) malloc(sizeof(node));
s->bottom = s->top;
s->top->next = NULL;
} bool push(NewStack s,int val) {
//Snode top = s->top;
// Snode bottom = s->bottom;
if(COUNT == MAX_STACK) {
printf("StackOverFlowError\n");
return false;
}
Snode newNode = (Snode) malloc(sizeof(node));
newNode->data = val; // push the new node into the stack
newNode->next = s->top;
s->top = newNode;
COUNT ++;
//printf("%d \n",s->top->data);
return true;
} int pop(NewStack s) {
if(s->top == s->bottom) {
printf("this is bottom of stack!\n");
return NULL;
}
int val = s->top->data;
Snode tempNode = s->top;
s->top = s->top->next;
free(tempNode);
return val;
} void printStack(NewStack s){
Snode priNode = (Snode) malloc (sizeof(node));
priNode = s->top;
printf("now it is the show time of ur stack:\n");
while(priNode != s->bottom) {
printf("%d \t",priNode->data);
priNode = priNode->next;
}
} void scanfStack(NewStack s) {
printf("now u can write down the elements u cant push:\n");
int i = ;
int val;
for(i = ; i<MAX_STACK; ++i) {
scanf("%d",&val);
push(s,val);
}
} bool deleteStack(NewStack s) {
Snode clear = (Snode) malloc (sizeof(node));
while(s->top != s->bottom) {
clear = s->top;
s->top = s->top->next;
free(clear);
} return true;
} int getMax(NewStack s) {
Snode top = s->top;
Snode bottom = s->bottom;
int max = top->data;
while(top != bottom) {
if(top->data > max) {
max = top->data;
}
top = top->next;
} return max;
} int getMin(NewStack s) {
Snode top = s->top;
Snode bottom = s->bottom;
int Min = top->data;
while(top != bottom) {
if(top->data < Min) {
Min = top->data;
}
top = top->next;
} return Min;
} // using the counting sort -- is not appropriate for the neibouring numbers where there are big difference.
int getMaxNeighD_value(NewStack s){
Snode top = s->top;
Snode bottom = s->bottom;
int max = getMax(s);
int min = getMin(s);
int num = max-min+; // get the length of the new counting sort array
int arr[num];
int i = ;
int j = ; // to put the elements into the new counting sort array
for(; j<num; ++j) {
arr[j] = -;
}
while(top != bottom) {
arr[top->data - min] = top->data;
top = top->next;
} // to find out the max zone where there are max number of -1
int Max_count = ;
int count = ;
for(;i < num; ++i) {
//printf("%d:%d\n",i,arr[i]);
if(arr[i] == -) {
count ++;
}else {
if(count > Max_count) {
Max_count = count;
}
count = ;
}
//printf("%d\n",Max_count+1);
} return Max_count+;
} int main() {
NewStack s = (NewStack) malloc(sizeof(Stack));
creatStack(s);
// push(s,5);
// push(s,6);
// push(s,4);
// push(s,7);
// push(s,10);
// push(s,9);
// push(s,3);
// push(s,56);
// push(s,88);
// push(s,44);
// push(s,66);
scanfStack(s);
printStack(s);
//printf("%d \t",pop(s));
int max = getMax(s);
int min = getMin(s);
printf("%d %d\n",max,min);
int c = getMaxNeighD_value(s);
printf("the max neighbouring D_value is : %d \n",c);
//deleteStack(s);
//pop(s);
}

illustration : counting sort is not appropriate for the array where there are too big difference such as {1, 2, 100000} , then i will report the

      new method of sort called bucket sort to solve the problem.

find out the neighbouring max D_value by counting sort in stack的更多相关文章

  1. counting sort 计数排序

    //counting sort 计数排序 //参考算法导论8.2节 #include<cstdio> #include<cstring> #include<algorit ...

  2. 《算法导论》——计数排序Counting Sort

    今天贴出的算法是计数排序Counting Sort.在经过一番挣扎之前,我很纠结,今天这个算法在一些scenarios,并不是最优的算法.最坏情况和最好情况下,时间复杂度差距很大. 代码Countin ...

  3. HDU 1718 Rank counting sort解法

    本题是利用counting sort的思想去解题. 注意本题,好像利用直接排序,然后查找rank是会直接被判WA的.奇怪的推断系统. 由于分数值的范围是0到100,很小,而student 号码又很大, ...

  4. 41. First Missing Positive(困难, 用到 counting sort 方法)

    Given an unsorted integer array, find the first missing positive integer. For example, Given [1,2,0] ...

  5. [Algorithms] Counting Sort

    Counting sort is a linear time sorting algorithm. It is used when all the numbers fall in a fixed ra ...

  6. 【HackerRank】 The Full Counting Sort

    In this challenge you need to print the data that accompanies each integer in a list. In addition, i ...

  7. 排序算法六:计数排序(Counting sort)

    前面介绍的几种排序算法,都是基于不同位置的元素比较,算法平均时间复杂度理论最好值是θ(nlgn). 今天介绍一种新的排序算法,计数排序(Counting sort),计数排序是一个非基于比较的线性时间 ...

  8. [MIT6.006] 7. Counting Sort, Radix Sort, Lower Bounds for Sorting 基数排序,基数排序,排序下界

    在前6节课讲的排序方法(冒泡排序,归并排序,选择排序,插入排序,快速排序,堆排序,二分搜索树排序和AVL排序)都是属于对比模型(Comparison Model).对比模型的特点如下: 所有输入ite ...

  9. 【算法】计数排序(Counting Sort)(八)

    计数排序(Counting Sort) 计数排序不是基于比较的排序算法,其核心在于将输入的数据值转化为键存储在额外开辟的数组空间中. 作为一种线性时间复杂度的排序,计数排序要求输入的数据必须是有确定范 ...

随机推荐

  1. Java 时间的表示

    //不建议的方式 out.println("<p>结束Servlet的时间:" + new Date().toLocaleString() + "</p ...

  2. 各大浏览器内核介绍(Rendering Engine)

    在介绍各大浏览器的内核之前,我们先来了解一下什么是浏览器内核. 所谓浏览器内核就是指浏览器最重要或者说核心的部分"Rendering Engine",译为"渲染引擎&qu ...

  3. Javascript设计模式学习三(策略模式)

    定义:定义一系列的算法,把它们一个个封装起来,并且使它们可以互相替换.目的:将算法的使用和算法的实现分离开来.比如: if(input == 'A'){ return 1; } if(input == ...

  4. C#RSA算法实现+如何将公钥为XML格式转为PEM格式,给object-C使用

    .net中,处于安全的考虑,RSACryptoServiceProvider类,解密时只有同时拥有公钥和私钥才可以.原因是公钥是公开的,会被多人持有.这样的数据传输是不安全的.C#RSA私钥加密,公钥 ...

  5. ES6学习笔记一

    块级作用域:在ES5中只有全局作用域与函数作用域,ES6中新增的块级作用域避免变量的覆盖与泄露.考虑到代码运行环境,在块级作用域中应避免声明函数,最好用函数表达式的方式声明. let与const:le ...

  6. redis的一些操作

    public class WnsRedisFactory { private static Cache pool = null; private static JedisConnectionFacto ...

  7. 在Extjs中对日期的处理,以及在后端数据在SQL语句的判断处理

    jsp页面可选择时间: { xtype : 'datefield', id : 'START_CREATION_DATE_', format : 'Y-m-d H:i:s', submitFormat ...

  8. JavaScript学习笔记(1))——————call,apply方法

    学习前端也有一段时间了,但是效果甚微.利用时间不够充分,虽然是利用工作之余来学习.但是这不能成为我的借口. 今天学习了(其实看了很多遍)call apply方法. function abc(a,b){ ...

  9. Qtp常见问题

    (1)Qtp不能识别对象 插件加载错误 IE内未加载BHOManager加载项

  10. ACM/ICPC 之 中国剩余定理+容斥原理(HDU5768)

    二进制枚举+容斥原理+中国剩余定理 #include<iostream> #include<cstring> #include<cstdio> #include&l ...