tkinter界面卡死的解决办法

0、如果点击按钮，运行了一个比较耗时的操作，那么界面会卡死

import tkinter as tk
import time

def onclick(text, i):
   time.sleep(3)
   text.insert(tk.END, '按了第{}个按钮\n'.format(i))

root = tk.Tk()

text = tk.Text(root)
text.pack()

tk.Button(root, text='按钮1', command=lambda :onclick(text,1)).pack()
tk.Button(root, text='按钮2', command=lambda :onclick(text,2)).pack()

root.mainloop()

解决办法：

方式一、直接开线程

import tkinter as tk
import time
import threading

songs = ['爱情买卖','朋友','回家过年','好日子']
movies = ['阿凡达','猩球崛起']

def music(songs):
    global text # 故意的，注意与movie的区别
    for s in songs:
        text.insert(tk.END, "听歌曲：%s \t-- %s\n" %(s, time.ctime()))
        time.sleep(3)

def movie(movies, text):
    for m in movies:
        text.insert(tk.END, "看电影：%s \t-- %s\n" %(m, time.ctime()))
        time.sleep(5)

def thread_it(func, *args):
    '''将函数打包进线程'''
    # 创建
    t = threading.Thread(target=func, args=args)
    # 守护 !!!
    t.setDaemon(True)
    # 启动
    t.start()
    # 阻塞--卡死界面！
    # t.join()

root = tk.Tk()

text = tk.Text(root)
text.pack()

tk.Button(root, text='音乐', command=lambda :thread_it(music, songs)).pack()
tk.Button(root, text='电影', command=lambda :thread_it(movie, movies, text)).pack()

root.mainloop()

方式二、继承 threading.Thread 类

import tkinter as tk
import time
import threading

songs = ['爱情买卖','朋友','回家过年','好日子']
movies = ['阿凡达','猩球崛起']

def music(songs):
    global text # 故意的，注意与movie的区别
    for s in songs:
        text.insert(tk.END, "听歌曲：%s \t-- %s\n" %(s, time.ctime()))
        time.sleep(3)

def movie(movies, text):
    for m in movies:
        text.insert(tk.END, "看电影：%s \t-- %s\n" %(m, time.ctime()))
        time.sleep(5)

class MyThread(threading.Thread):
    def __init__(self, func, *args):
        super().__init__()

        self.func = func
        self.args = args

        self.setDaemon(True)
        self.start()    # 在这里开始

    def run(self):
        self.func(*self.args)

root = tk.Tk()

text = tk.Text(root)
text.pack()

tk.Button(root, text='音乐', command=lambda :MyThread(music, songs)).pack()
tk.Button(root, text='电影', command=lambda :MyThread(movie, movies, text)).pack()

root.mainloop()

三、或者，搞一个界面类：

import tkinter as tk
import time
import threading

songs = ['爱情买卖','朋友','回家过年','好日子'] 
films = ['阿凡达','猩球崛起']

class Application(tk.Tk):
def __init__(self):
        super().__init__()

        self.createUI()

    # 生成界面
    def createUI(self):
        self.text = tk.Text(self)
        self.text.pack()

        tk.Button(self, text='音乐', command=lambda :self.thread_it(self.music, songs)).pack(expand=True, side=tk.RIGHT) # 注意lambda语句的作用！
        tk.Button(self, text='电影', command=lambda :self.thread_it(self.movie, films)).pack(expand=True, side=tk.LEFT)

    # 逻辑：听音乐
    def music(self, songs):
        for x in songs:
            self.text.insert(tk.END, "听歌曲：%s \t-- %s\n" %(x, time.ctime()))
            print("听歌曲：%s \t-- %s" %(x, time.ctime()))
            time.sleep(3)

    # 逻辑：看电影
    def movie(self, films):
        for x in films:
            self.text.insert(tk.END, "看电影：%s \t-- %s\n" %(x, time.ctime()))
            print("看电影：%s \t-- %s" %(x, time.ctime()))
            time.sleep(5)

    # 打包进线程（耗时的操作）
    @staticmethod
    def thread_it(func, *args):
        t = threading.Thread(target=func, args=args)
        t.setDaemon(True)   # 守护--就算主界面关闭，线程也会留守后台运行（不对!）
        t.start()           # 启动
        # t.join()          # 阻塞--会卡死界面！

app = Application()
app.mainloop()