hdu 4150 Powerful Incantation
题目连接
http://acm.hdu.edu.cn/showproblem.php?pid=4150
Powerful Incantation
Description
Some dangerous Witches invaded the garden city! As a righteous magician, james0zan want to find the most powerful incantation so he can beat those dangerous witches easily.
After consulted one hundred and eight thousand Magic Books, james0zan find a way to calculate the power of an incantation. There is a very short incantation called “magic index” which contains the magic power, and each incantation’s power can be calculated by the times the “magic index” appearance in the incantation. Notice that if two “magic index” overlapped, the power only should be calculated once. And we just want the incantation more powerful. That is to say, if the “magic index” is “aa”, the power of incantation “aaaa” is 2(“aa”+”aa”), not 1(“a”+”aa”+”a”) or 3.
Input
The first line is an integer t (t<=30), the number of test cases. Each of the next t lines contains two strings, represent the incantation (length<=10^6) and the “magic index” (length<=5). Every char in the incantation and the magic index is lowercase.
Output
For each test case you should output the power of the incantation.
Sample Input
3
aaaa aa
bsdjfassdiifo sd
papapapapapapap ap
Sample Output
2
2
7
由于模式串很短所以直接暴力即可。。
#include<algorithm>
#include<iostream>
#include<cstdlib>
#include<cstring>
#include<cstdio>
#include<vector>
#include<map>
using std::cin;
using std::cout;
using std::endl;
using std::find;
using std::sort;
using std::map;
using std::pair;
using std::vector;
using std::multimap;
#define pb(e) push_back(e)
#define sz(c) (int)(c).size()
#define mp(a, b) make_pair(a, b)
#define all(c) (c).begin(), (c).end()
#define iter(c) decltype((c).begin())
#define cls(arr,val) memset(arr,val,sizeof(arr))
#define cpresent(c, e) (find(all(c), (e)) != (c).end())
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
#define tr(c, i) for (iter(c) i = (c).begin(); i != (c).end(); ++i)
const int N = ;
typedef unsigned long long ull;
char text[N], pat[];
int main() {
#ifdef LOCAL
freopen("in.txt", "r", stdin);
freopen("out.txt", "w+", stdout);
#endif
int t;
scanf("%d", &t);
while (t--) {
scanf("%s %s", text, pat);
char *p = text;
int ans = , len = strlen(pat);
while (p = strstr(p, pat)) {
ans++;
p += len;
}
printf("%d\n", ans);
}
return ;
}
hdu 4150 Powerful Incantation的更多相关文章
- 【HDU 4150】Powerful Incantation
题 题意 给你s1,s2两个字符串,求s1中有多少个s2 代码 #include<stdio.h> #include<string.h> int t,len1,len2,pos ...
- HDU 5091---Beam Cannon(线段树+扫描线)
题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=5091 Problem Description Recently, the γ galaxies bro ...
- HDU 5115 Dire Wolf 区间dp
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5115 Dire Wolf Time Limit: 5000/5000 MS (Java/Others ...
- hdu 4666:Hyperspace(最远曼哈顿距离 + STL使用)
Hyperspace Time Limit: 20000/10000 MS (Java/Others) Memory Limit: 65535/65535 K (Java/Others)Tota ...
- HDU 1044 Collect More Jewels(BFS+DFS)
Collect More Jewels Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Othe ...
- HDU 1052 Tian Ji -- The Horse Racing(贪心)(2004 Asia Regional Shanghai)
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1052 Problem Description Here is a famous story in Ch ...
- hdu 1045 Fire Net(最小覆盖点+构图(缩点))
http://acm.hdu.edu.cn/showproblem.php?pid=1045 Fire Net Time Limit:1000MS Memory Limit:32768KB ...
- hdu 4499 Cannon dfs
Cannon Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=4499 D ...
- HDU 1045(Fire Net)题解
以防万一,题目原文和链接均附在文末.那么先是题目分析: [一句话题意] 给定大小的棋盘中部分格子存在可以阻止互相攻击的墙,问棋盘中可以放置最多多少个可以横纵攻击炮塔. [题目分析] 这题本来在搜索专题 ...
随机推荐
- Jquery 对象与 DOM对象的相互转换
在做 web 开发时,经常会用到 jquery 和 dom 对象, 有时候需要在这两个对象间进行切换. Jquery 对象 就是通过jQuery包装DOM对象后产生的对象.jQuery对象是jQuer ...
- NOIP2004 虫食算
描述 所谓虫食算,就是原先的算式中有一部分被虫子啃掉了,需要我们根据剩下的数字来判定被啃掉的字母.来看一个简单的例子:43#9865#045+ 8468#6633= 44445506678其中#号代表 ...
- XML Namespace 命名空间
根据 Namespaces in XML W3C 推荐标准的定义,XML 命名空间 是由国际化资源标识符 (IRI) 标识的 XML 元素和属性集合:该集合通常称作 XML“词汇”. 定义 XML 命 ...
- Atom markdown .md 编写格式技巧
使用Atom预览markdown 1.打开任意.md文件(markdown源文件) 菜单栏File->Open file...(ctrl+o)打开文件: 2.windows下使用快捷键 ctrl ...
- 苹果系列机型专业刷机,解锁,解ID
如有软件开发需求,请留言或在猪八戒网主页留言http://home.zhubajie.com/8506525/,常年接收c.c++(vs2010.RAD studio xe5\RAD studio 2 ...
- 4种kill某个用户所有进程的方法
在linux系统管理中,我们有时候需要kill掉某个用户的所有进程,初学者一般先查询出用户的所有pid,然后一条条kill掉,或者写好一个脚本,实际上方法都有现成的,这边有4种方法,我们以kill用户 ...
- Web发布 未能加载文件或程序集“”或它的某一个依赖项。系统找不到指定的...
因为
- shell脚本中的特殊符号
1.{} 大括号:用法一:通配符扩展eg: ls my_{finger,toe}s这条命令相当于如下命令的组合:ls my_fingers my_toeseg: mkdir {userA,userB, ...
- 通过Migration在EF6中用多个DbContext
通过Migration在EF6中用多个DbContext EF EF6 C# Migration 通过Migration在EF6中用多个DbContext 前言 实现目标 设置多数据上下文 更新数据脚 ...
- 观察者(observer)设计模式
转载:http://www.tracefact.net/CSharp-Programming/Delegates-and-Events-in-CSharp.aspx 假设我们有个高档的热水器,我们给它 ...